MATHEMATICS HIGH SCHOOL

Given the polynomial 2x3 + 18x2 − 18x − 162, what is the value of the coefficient 'k' in the factored form?2x3 + 18x2 − 18x − 162 = 2(x + k)(x − k)(x + 9)

k= ____________

Answers

Answer 1

Answer:

Answer:

Step-by-step explanation:

Alright, lets get started.

$2x^3 + 18x^2 -18x -162 = 2(x+k)(x-k)(x+9)$

$2(x+k)(x-k)(x+9) =2x^3 + 18x^2 -18x -162$

$2(x^2-k^2)(x+9)=2x^3 + 18x^2 -18x -162$

$2(x^3+9x^2-k^2 x+9k^2)=2x^3 + 18x^2 -18x -162$

$2x^3 + 18x^2 -2k^2x+18k^2= 2x^3 + 18x^2 -18x -162$

comparing both sides

$2k^2 =18$

$k^2=9$

$k=3$

hence answer is k = 3(plus/minus) : Answer

Hope it will help :)

Answer 2

Answer:

Your Answer:

k = 3

Hope this helps y'all :)

Related Questions

Can someone help me with this one.i will give you a brainlist if you give the answers. thanks!
Add 3/7 + 4/5 please helppppp me
Needin help for math
Solve i=prt if i=105, p=700 & r=0.05
Mr Jones is 4 years older than his wife and 31 years older than his son. their ages add up to 82 years. if Mr Jones is x years old, find the value of x and the ages of his wife and son.first person here gets the brainiest award thingy!

Calculate the following limit:

Answers

$\lim_(x\to\infty)\frac{\sqrt x}{\sqrt{x+√(x+\sqrt x)}}=\n\lim_(x\to\infty)\frac{(\sqrt x)/(\sqrt x)}{\frac{\sqrt{x+√(x+\sqrt x)}}{\sqrt x}}=\n\lim_(x\to\infty)\frac{1}{\sqrt{(x+√(x+\sqrt x))/(x)}}=\n\lim_(x\to\infty)\frac{1}{\sqrt{1+(√(x+\sqrt x))/(x)}}=\n\lim_(x\to\infty)\frac{1}{\sqrt{1+(√(x+\sqrt x))/(√(x^2))}}=\n$
$\lim_(x\to\infty)\frac{1}{\sqrt{1+\sqrt{(x+\sqrt x)/(x^2)}}}=\n\lim_(x\to\infty)\frac{1}{\sqrt{1+\sqrt{(1)/(x)+(\sqrt x)/(√(x^4))}}}=\n\lim_(x\to\infty)\frac{1}{\sqrt{1+\sqrt{(1)/(x)+\sqrt{(x)/(x^4)}}}}=\n\lim_(x\to\infty)\frac{1}{\sqrt{1+\sqrt{(1)/(x)+\sqrt{(1)/(x^3)}}}}=\n=\frac{1}{\sqrt{1+\sqrt{0+√(0)}}}=\n$
$=(1)/(√(1+0))=\n=(1)/(√(1))=\n=(1)/(1)=\n1$

Type the correct answer in each box. If necessary, use / for the fraction bar(s).In this triangle, the product of sin B and tan C is
, and the product of sin C and tan B is
.

Answers

The product of sin B and tan C is c/a

The product of sin C and tan B is b/a

Further explanation

We can use

SOH stands for Sine = Opposite ÷ Hypotenuse.

CAH stands for Cosine = Adjacent ÷ Hypotenuse.

TOA stands for Tangent = Opposite ÷ Adjacent.

There is a picture attached

$\tt sin~B=(b)/(a)\n\nTan~C=(c)/(b)\n\nsin~B* Tan~C=(b)/(a)* (c)/(b)=(c)/(a)$

$\tt sin~C=(c)/(a)\n\nTan~B=(b)/(c)\n\nsin~C* tan~B=(c)/(a)* (b)/(c)=(b)/(a)$

Answer:

The product of sin B and tan C is (c/a)

The product of sin C and tan B is (b/a)

PLATO

A=(s-2)180 solve for s

Answers

You said that    A = (s-2) 180

Divide each side by 180 : A/180    = s-2

Add 2 to each side:     A/180 + 2 = s

A = (s - 2)180

A = (s)180 - (2)180

A = 180s - 360 (add 360 to each side)

A + 360 = 180s - 360 + 360

A + 360 = 180s (divide 180 from each side)

(A + 360)/180 = s

s =

II A-
d, e, i, u, Us d
Ly
Find the distance between the points (1, 2) and -3, 4).

Answers

Answer:

2√5

Step-by-step explanation:

Which ordered pair is a solution of the system? x + 4y = 19
y = -2x - 4

A. (3,4)
B. (7,3)
C. (-5,6)
D. (-2,0)

Answers

y = -2x - 4

x + 4y = 19
x + 4(-2x - 4) = 19
x + (-8x) - 16 = 19
-7x - 16 = 19
-7x = 35
-x = 5
x = -5

y = -2x - 4
y = -2(-5) - 4
y = 10 -4
y = 6

Solution set {-5, 6} (C)

2. A highway makes an angle of 6 with the horizontal. This angle is maintained for a horizontal distance of 5 miles. To the nearest hundredth of a mile, how high does the highway rise in this 5-mile section? Show the steps you use to find the distance.

Answers

given:
angle of 6 : i'm assuming this is 6 degrees.
distance of 5 miles.

tan(6) = rise/5 mi
rise = 5 mi * tan(6)
rise = 5 mi * 0.10510423526
rise = 0.52552117632

rise = 0.53 miles.

Other Questions

Hy! (√2+1)²+(3-√3)²-(√5+1)²=???Thank yours!:*

Plsss help!!!!!!!!

The entire exterior of a large wooden cube is painted red, and then the cube is sliced into n^3 smaller cubes (where n > 2). Each of the smaller cubes is identical. In terms of n, how many of these smaller cubes have been painted red on at least one of their faces?A. 6n^2B. 6n^2 – 12n + 8C. 6n^2 – 16n + 24D. 4n^2E. 24n – 24

Solve the equation sin(x - 20°) = cos(42º) for x, where 0

Given the polynomial 2x3 + 18x2 − 18x − 162, what is the value of the coefficient 'k' in the factored form?2x3 + 18x2 − 18x − 162 = 2(x + k)(x − k)(x + 9) k= ____________

Answers

Related Questions

Answers

Answers

Further explanation

Answers

Answers

Answers

Answers

Given the polynomial 2x3 + 18x2 − 18x − 162, what is the value of the coefficient 'k' in the factored form?2x3 + 18x2 − 18x − 162 = 2(x + k)(x − k)(x + 9)

k= ____________