A thesis statement is _____.the subject of your paper
the conclusion
the statement the writer attempts to prove

Answers

Answer 1

Answer: A thesis statement is the statement the writer attempts to prove. The thesis must be something that people could reasonably have differing opinions on. An example is "Internet is bad for the people." This is debatable because different people have different views of the usage of internet.

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How are HNO3(aq) and CH3COOH(aq) similar?(1) They are Arrhenius acids and they turn blue litmus red.(2) They are Arrhenius acids and they turn red litmus blue.(3) They are Arrhenius bases and they turn blue litmus red.(4) They are Arrhenius bases and they turn red litmus blue.
How is 0.00025 written in scientific notation

How many grams of water will form if 10.54 g H2 react with 95.10 g O2

Answers

Answer : The amount of water will be, 94.86 grams

Solution :

First we have to calculate the moles of $H_2$ and $O_2$ .

$\text{Moles of }H_2=\frac{\text{Mass of }H_2}{\text{Molar mass of }H_2}=(10.54g)/(2g/mole)=5.27moles$

$\text{Moles of }O_2=\frac{\text{Mass of }O_2}{\text{Molar mass of }O_2}=(95.10g)/(32g/mole)=2.97moles$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$2H_2+O_2\rightarrow 2H_2O$

From the balanced reaction we conclude that

As, 2 moles of $H_2$ react with 1 mole of $O_2$

So, 5.27 moles of $H_2$ react with $(5.27)/(2)=2.63$ moles of $O_2$

That means, in the given balanced reaction, $H_2$ is a limiting reagent because it limits the formation of products and $O_2$ is an excess reagent.

The excess reagent remains $(O_2)$ = 2.97 - 2.63 = 0.34 moles

Now we have to calculate the moles of $H_2O$ .

As, 2 moles of $H_2$ react with 2 moles of $H_2O$

So, 5.27 moles of $H_2$ react with $(2)/(2)* 5.27=5.27$ moles of $H_2O$

Now we have to calculate the mass of $H_2O$ .

$\text{Mass of }H_2O=\text{Moles of }H_2O* \text{Molar mass of }H_2O$

$\text{Mass of }H_2O=(5.27mole)* (18g/mole)=94.86g$

Therefore, the amount of water will be, 94.86 grams

Answer:

94.03

Explanation:

edge 2023

How many moles is 1.50x10^23 molecules of NH3?

Answers

The number of moles that are 1.50 x10^23 molecules of NH3 are

=0.249 moles

calculation

The number of moles is calculated using Avogadro's law constant

that is According to Avogadro's law

1 moles of a substance = 6.02 x10^23 molecules

? moles = 1.50 x10^23 molecules

by cross multiplication

= [( 1.50 x 10^23 molecules x 1 moles) / (6.02 x10^23)] = 0.249 moles

warm water near the equator rises towards the surface, creating a current. what would you expect to happen to this current if the temperature at the equator decreased?

Answers

IF there is a decrease in the temperature at the equator then it is possible that there is an increase in the speed of current.

Do electrolytes contain ions?

Answers

Yes

Filling in the 20 word ruleeeeeeee jejene jejjene

Answer: yes

Explanation: they contain sodium, potassium, chloride, bicarbonate, calcium, phosphate, magnesium, copper, zinc, manganese, molybdenum, copper, and chromium also.

You are given 50.0 ml of 1.50 m hno3. how many ml of 0.81 m naoh are needed to neutralize it?

Answers

V(HNO₃) = 50.0 mL in liters = 50.0 /1000 =0.05 L
M(HNO₃) = 1.50 M

Number of moles HNO₃ :

n = M x V

n = 1.50 x 0.05

n = 0.075 moles of HNO₃

HNO₃ + NaOH = H₂O + NaNO₃

1 mole HNO₃ -------- ---1 mole NaOH
0.075 moles HNO₃ ---- ?

moles NaOH = 0.075 * 1 / 1

= 0.075 moles of NaOH

V ( NaOH ) :

M = n / V

0.81 = 0.075 / V

V = 0.075 / 0.81

V = 0.0925 L or 92.5 mL

hope this helps!

What determines the strength of an Arrhenius base?