The adrenal glands respond to______

Answers

Answer 1
Answer:

The adrenal gland respond to stress that is experienced in your body.  These are produced within the medulla. The cortisol helps regulate your metabolism, sugar levels and blood pressure. The adrenal glands are controlled by the pituitary gland.


Related Questions

A chemical reaction is at equilibrium. Compared to the rate of the forward reaction, the rate of the reverse reaction is(1) faster and more reactant is produced(2) faster and more product is produced(3) the same and the reaction has stopped(4) the same and the reaction continues in both directions
Every substance is either an element or a ____. Fill in the blank. Molecular Compounds is the chapter I'm on.
All organic molecules have what element in common
The curved top surface of a liquid column
What type of reaction takes place when atoms or molecules rearrange to form new substances?

If 21.3 grams of lithium react with excess water, how many liters of hydrogen gas can be produced at 297 kelvin and 1.40 atmospheres?

Answers

Hope it cleared your doubt :)

Gaseous methane (CH₄) reacts with gaseous oxygen gas (O₂) to produce gaseous carbon dioxide (CO₂) and gaseous water (H₂O) If 0.391 g of carbon dioxide is produced from the reaction of 0.16 g of methane and 0.84 g of oxygen gas, calculate the percent yield of carbon dioxide.

Answers

Answer : The percent yield of CO_2 is, 68.4 %

Solution : Given,

Mass of CH_4 = 0.16 g

Mass of O_2 = 0.84 g

Molar mass of CH_4 = 16 g/mole

Molar mass of O_2 = 32 g/mole

Molar mass of CO_2 = 44 g/mole

First we have to calculate the moles of CH_4 and O_2.

\text{ Moles of }CH_4=\frac{\text{ Mass of }CH_4}{\text{ Molar mass of }CH_4}=(0.16g)/(16g/mole)=0.01moles

\text{ Moles of }O_2=\frac{\text{ Mass of }O_2}{\text{ Molar mass of }O_2}=(0.84g)/(32g/mole)=0.026moles

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

CH_4+2O_2\rightarrow CO_2+2H_2O

From the balanced reaction we conclude that

As, 2 mole of O_2 react with 1 mole of CH_4

So, 0.026 moles of O_2 react with (0.026)/(2)=0.013 moles of CH_4

From this we conclude that, CH_4 is an excess reagent because the given moles are greater than the required moles and O_2 is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of CO_2

From the reaction, we conclude that

As, 2 mole of O_2 react to give 1 mole of CO_2

So, 0.026 moles of O_2 react to give (0.026)/(2)=0.013 moles of CO_2

Now we have to calculate the mass of CO_2

\text{ Mass of }CO_2=\text{ Moles of }CO_2* \text{ Molar mass of }CO_2

\text{ Mass of }CO_2=(0.013moles)* (44g/mole)=0.572g

Theoretical yield of CO_2 = 0.572 g

Experimental yield of CO_2 = 0.391 g

Now we have to calculate the percent yield of CO_2

\% \text{ yield of }CO_2=\frac{\text{ Experimental yield of }CO_2}{\text{ Theretical yield of }CO_2}* 100

\% \text{ yield of }CO_2=(0.391g)/(0.572g)* 100=68.4\%

Therefore, the percent yield of CO_2 is, 68.4 %

Put these events in order.= Your phone contacts a base station in a cell.
= Once connected, a duplex system allows you to talk to the other person at the same time.
= You dial a number on your cell phone.
The MTSO then connects you to the other device.
= A base station contacts the Mobile Telephone Switching Office (MTSO).

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Answer:

You dial a number on your phone

Your phone contacts a base station

The base station contacts the MTSO

The MTSO connects you to the other device

You talk to the person on the other device.

Groups of cells that work together are called .

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group of tissues form a cell , and a group of cells form an organ 

The amount of carbon in the atmosphere is about _____ of the total amount of carbon on Earth.a. 0.01%
b. 0.1%
c. 1%
d. 10%

Answers

Answer:

a) 0.01 %

Explanation:

The carbon in the atmosphere is mainly in the form of carbon dioxide (CO2).

The ammount of carbon is arround 700 gigatons and they represent the 0.01 % of the carbon on Earth.

C is the correct answer

What is the scale factor used to create a model of an animal from the actual animal? 1) 1:10 2) 1:20 3) 1:30 4) 1:40

Answers

The scale factor used to create a model of an animal from the actual animal depends on the size and details required for the model. However, among the options provided, the most commonly used scale factor for creating detailed animal models is 1:40.