The dopamine molecule has an intermediate hydrophobicity. Edit the dopamine molecule so that it is more hydrophobic.

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Answer 1

Answer: You should edit the dopamine molecule by tampering with its polar groups. Polar groups affect chemical's physical properties including hydrophobicity.

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An anvil-shaped heard is a feature of a mature thunderstorm : true false

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True! The anvil is a surefire sign of a mature thunderstorm

3.3 kg aluminum chromate

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this is not a question

would you select water or gasoline to try dissolving the following : table sugar, motor oil, rubber from tire marks, adhesive residue from a packing tape

Answers

To know the answer, we determine the polarities of the solvent we have. Water is polar and gasoline is nonpolar. We remember that like dissolves like. Therefore, the answers are:

table sugar = water
motor oil = gasoline
rubber from tire marks = gasoline
adhesive residue from a packing tape = gasoline

Answer:

table sugar: water

motor oil: gasoline

rubber from tire marks: gasoline

adhesive residue from a packing tape: gasoline

Explanation:

Like dissolves like so a polar compound will dissolve in a polar solvent and a non polar compound will dissolve in a non-polar solvent. The intermolecular forces of attraction are responsible for the dissolution of substances in different solvents.

For example, polar solute exhibit hydrogen bonding and dipole interaction with polar solvents (water). Non-polar solute exhibit London dispersion forces with non-polar solvents(gasoline).

When harmful bacteria invade a wound, the skin around the wound turns red. This is known as:

Answers

Answer:

Inflammation

Explanation:

Inflammation is the response to a cut. The blood vessels expand when you get cut to allow white blood cells to flock to the wound site. These attack any bacteria that got past the clot. If you mean excess bacteria, then that would be an infection.

Determine the half-life of potassium if in 3460 years a 200 g sample decayed into 25 g

Answers

$M=m_o*(1)/(2)^(t)/(T)\n M-mass\ aftter\ decay\n m-initial\ mass\n t-time\n T-period(half-life)\n 25=200*(1)/(2)^(3460)/(T)|:200\n (1)/(8)=((1)/(2))^(3460)/(T)\n ((1)/(2))^3=((1)/(2))^(3460)/(T)\n 3=(3460)/(T)\n T=1153(1)/(3)$

or easiest way
200g -----> 100g -------> 50g -----> 25g
We can that there were three decays.
1 decay ----------- x years
3 decays---------- 3460
$x=1153(1)/(3)$

As the pressure on the surface of a liquid decreases, the temperature at which the liquid will boil(1) decreases
(2) increases
(3) remains the same

Answers

Answer: option (1) decreases.

Explanation:

May be you have experienced that: when you go to the beach, where the atmposhpere pressure is greater than the atmosphere pressure in places that are at higher altitudes, the water takes longer to boil. That is because the boiling temperature is greater, and you need more total heat (more time) to permit the liquid to reach that temperature.

The reason why that happens is because substances boil when the vapor pressure (the pressure of the particles of vapor over the liquid) equals the atmosphere pressure. So, when the atmposhere pressure increases, the temperature at which the vapor pressure reaches the atmosphere pressure also increases, and when the atmosphere pressure decreases, the temperature at which the vapor pressure reaches the atmosphere pressure decreases.

As the pressure on the surface of a liquid decreases, the temperature at which the liquid will boil(1) decrease.

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