If 7.84 x 10^7 J of energy is released from a fusion reaction, what amount of mass in kilograms would be lost? Recall that c = 3 x 10^8 m/s.7.06 x 10^24

8.71 x 10^-4

8.71 x 10^-7

8.71 x 10^-10

Answers

Answer 1
Answer: Use the formula
E=mc^2

plug the values,

The amount of mass in kilograms would be lost is 8.71 x 10^-10
Answer 2
Answer:

Answer : The mass lost would be, 8.71* 10^(-10)Kg

Solution : Given,

Energy released = 7.84* 10^(7)J=7.84* 10^(7)\text{ Kg }m^2/s^2

(1J=1\text{ Kg }m^2/s^2)

Speed of light 'c' = 3* 10^(8)m/s

Formula used :

E=m* c^2

where,

E = energy

m = mass

c = speed of light

Now put all the given values in the above formula, we get

7.84* 10^(7)\text{ Kg }m^2/s^2=m* (3* 10^(8)m/s)^2

m=8.71* 10^(-10)Kg

Therefore, the mass lost would be, 8.71* 10^(-10)Kg


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Answers

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Answers

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Answers

Explanation:

Given parameters:

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Unknown:

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Solution:

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Answers

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