MATHEMATICS HIGH SCHOOL

If the variance of the data values in a population is 324, what is the standard deviation of the data values?A. 14
B. 12
C. 16
D. 18

Answers

Answer 1
Answer: Simply the standard deviation of the data values is the square root of the variance:S= √(V)= √(324)=18
Answer: D)18
  
Answer 2
Answer:

Answer:

18

Step-by-step explanation:

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A ball is thrown straight up from the top of a 40 feet tall building with an initial speed of 24 feet per second. The height of the ball as a function of time can be modeled by what function h(t) = _________________ 1. after how many seconds the ball hit the ground. 2.What is the maximum height of the ball? 3.How long did it take for the ball to reach its maximum height?

Answers

Answer:

1)The ball hits the ground after 3 seconds.

2)The maximum height of the ball is 49 feet

3)It takes 1.25 seconds to reach its maximum height

Step-by-step explanation:

Height of building = 40 feet

We are given that A ball is thrown straight up from the top of building with an initial speed of 24 feet per second.

So, The height of the ball as a function of time can be modeled by: h(t)=-16t^2+40t+24

1)After how many seconds the ball hit the ground.

Substitute h(t)=0

So,-16t^2+40t+24=0\n-2t^2+5t+3=0\n2t^2-5t-3=0\n2t^2-6t+t-3=0\n2t(t-3)+1(t-3)=0\n(2t+1)(t-3)=0\nt=(-1)/(2) , 3

Since time cannot be negative

So,the ball hits the ground after 3 seconds.

2)What is the maximum height of the ball?

It takes maximum height at vertex

Formula : t = (-b)/(2a)

t=(-40)/(2(-16))=1.25 seconds

Substitute the value of t in function

h(1.25)=-16(1.25)^2+40(1.25)+24\nh(1.25)=49 feet

So,the maximum height of the ball is 49 feet

3).How long did it take for the ball to reach its maximum height?

It takes 1.25 seconds to reach its maximum height

Expand: (b + 2)(b - 4)

Answers

(b+2)(b-4)
b x b = b^2
b x 2 = 2b
b x -4= -4b
2 x -4=-8

b^2+2b-4b-8=   b^2-2b-8
i believe the answer is b^2-2b-8

How many 2 inch segments are there in 12 ft

Answers

72 2's in 12 ft
Hope this helped :)

Faye owned 1,300 shares of Wonderband Corp. Last week, a 2-for-1 split was executed. The pre-split price per share was w dollars. a. Determine the number of shares Faye owned after the split. b. Write an algebraic expression for the price per share after the split. c. Express the total value of the Wonderband stock Faye owned algebraically after the split.

Answers

Answer:

A = 1/2 1300 = 2600

Step-by-step explanation:

B 1/2 w = 1/2w

c = 1300w before  2600 1/2w = 1300 after

Given: 5 > x + 7. what is the solution set

Answers

To answer the problem, transpose all the constants and the variables to the opposite side of the inequality. The operation results to,
                                         5 - 7 > x
Solving for x gives, 
                                         x < -2
Thus, the solution set for this item is x such that x is less than -2.

Need help in this question please show work along with answer

Answers

                              (x² - y²)² + (2xy)² = (x² + y²)²
                     (x² - y²)(x² - y²) + 2x²y² = (x² + y²)(x² + y²)
            x²(x² - y²) - y²(x² - y²) + 2x²y² = x²(x² + y²) + y²(x² + y²)
x²(x²) - x²(y²) - y²(x²) + y²(y²) + 2x²y² = x²(x²) + x²(y²) + y²(x²) + y²(y²)
                x⁴ - x²y² - x²y² + y⁴ + 2x²y² = x⁴ + x²y² + x²y² + y⁴
                       x⁴ - 2x²y² + y⁴ + 2x²y² = x⁴ + 2x²y² + y⁴
                       x⁴ - 2x²y² + 2x²y² + y⁴ = x⁴ + 2x²y² + y⁴
                                              x⁴ + y⁴ = x⁴ + 2x²y² + y⁴
                                            - x⁴         - x⁴
                                                     y⁴ = 2x²y² + y⁴
                                                   - y⁴              - y⁴
                                                      0 = 2x²y²
                                                      2       2
                                                      0 = x²y²
                                                      0 = xy

I didn't find the answer to the problem.
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