What is the mass defect of oxygen-16? Assume the following: The atomic number of oxygen-16 is 8. The atomic mass of oxygen-16 is 15.9994 atomic mass units. The mass of one proton is 1.0073 atomic mass units. The mass of one neutron is 1.0087 atomic mass units.

Answers

Answer 1
Answer: To solve for the mass defect of the given atom, add up the individual masses of the nucleons, protons and neutrons. In this case, the total mass of the nucleons is solved through 8x(1.0073 + 1.0087) and is equal to 16.128. Subtracting the mass of the intact nucleus which is 15.9994 gives 0.1286. Thus, the mass defect is 0.1286. 
Answer 2
Answer:

The mass defect of oxygen-16 is 0.1286 amu.

What is mass defect?

The difference between the mass of the atom and the sum of the masses of its parts is called the mass defect (Δm).

To find the mass defect, we have to add nucleas, protons and electron masses.

Since, atomics mass= 15.9994 amu

Total mass of nucleons

= 8(mass of proton + mass of neutron)

=8(1.0073+1.0087)

= 16.128

So, the mass defect

=16.128-15.994

= 0.1286

Hence, the mass defect is 0.1286 amu.

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Answers

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What element is located at b24?B=[-4 10 -3 9
[ 6 0 2 -8
[7 -1 -11 4
[-9 -5 5 -10

Answers

b24 means the element of set B in the second row and 4th column.

(-8) is at that position.

What is set theory?

The mathematical concept of well-defined groupings of objects, or sets, that are referred to as members or elements of the set. The only sets that are taken into consideration are those whose members are also sets because pure set theory only deals with sets.

Given that the set is,

B=[-4 10 -3 9

[ 6 0 2 -8

[7 -1 -11 4

[-9 -5 5 -10

B24 stands for the B element in the second row and fourth column.

There is a (-8) there.

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b24 means Element of the set B in the second row and 4th column .
(-8) is at that position.

When the radius doubles, does the area of the circle double? A) 4π cm2; 8π cm2; NO
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Answers

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Answers

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Answers

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Answers

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