is required?
a. 7.00 mL
b. 8.40 mL
c. 17.1 mL
d. 58.3 mL
Answer:
Explanation:
To determine the volume of the stock solution required to prepare 3.50 L of 0.200 M hydro chloric acid, we can use the formula:
M1V1 = M2V2
where:
M1 = concentration of the stock solution
V1 = volume of the stock solution
M2 = desired concentration of the diluted solution
V2 = desired volume of the diluted solution
Let's substitute the given values into the formula:
M1 = 12.0 M
V1 = ?
M2 = 0.200 M
V2 = 3.50 L
Now we can solve for V1:
12.0 M x V1 = 0.200 M x 3.50 L
V1 = (0.200 M x 3.50 L) / 12.0 M
V1 = 0.0583 L
To convert the volume from liters to milliliters, we multiply by 1000:
V1 = 0.0583 L x 1000 mL/L
V1 = 58.3 mL
Therefore, the volume of the stock solution required is 58.3 mL.
So, the correct answer is d. 58.3 mL.
To determine the volume of the stock solution required, we can use the formula:
Molarity1 x Volume1 = Molarity2 x Volume2
Where Molarity1 and Volume1 represent the initial concentration and volume, and Molarity2 and Volume2 represent the final concentration and volume.
Given:
Molarity1 = 12.0 M
Volume1 = ?
Molarity2 = 0.200 M
Volume2 = 3.50 L
Plugging in the values into the formula, we have:
12.0 M x Volume1 = 0.200 M x 3.50 L
Simplifying the equation, we can solve for Volume1:
Volume1 = (0.200 M x 3.50 L) / 12.0 M
Volume1 ≈ 0.0583 L
To convert this to milliliters, we multiply by 1000:
Volume1 ≈ 58.3 mL
Therefore, the volume of the stock solution required is approximately 58.3 mL.
The closest answer option is d. 58.3 mL.
I hope this explanation helps! Let me know if you have any further questions.
Answer:
Yes, they are useful.
Explanation:
They allow us to make use of strengths and benefits of a particular element while not being hampered by it's faults.
A yield of NH3 of approximately 98% can be obtained at 200°C and 1,000 atmospheres of pressure.
How many grams of Ny must react to form 1.7 grams of ammonia, NH3?
0.052 g
1.49
0.00589
2.8 g
Answer:
Explanation:
Here we have to use stoichiometry.
First of all, we have to calculate the mass of 100% of yield:
1.7 g ------- 98%
X -------- 100%
X = 1.73 g (approximately)
Second, we have to calculate the mass of N2 that is necessary to react to produce the mass of 1.73g of NH3. To do that, we have to use the Molar mass of N2 and NH3 and don't forget the stoichiometric relationship between them.
Molar Mass N2 : 14x2 = 28 g/mol
Molar Mass NH3: 14 + 3 = 17 g/mol
28g (N2) ------- 17x2 (NH3)
X ------------ 1.73 g
X = 1.42 g (approximately)
Anaerobic respiration
Aerobic respiration
Photosynthesis
Answer:
The correct option is: D. Photosynthesis
Explanation:
Photosynthesis is a biological process in green plants by which food such as sugar (like glucose C₆H₁₂O₆), is synthesized from water (H₂O) and carbon dioxide (CO₂) from the atmosphere, in the presence of light energy. This process produces oxygen gas (O₂) as a by-product.
This reaction converts the light energy from the sun to chemical energy.
The reaction involved is: 6 CO₂ (g) + 6 H₂O + light → C₆H₁₂O₆ (s) + 6 O₂ (g)
Photosynthesis is the only process among the given options, that produces oxygen gas.
In living things, enzymes serve as a catalyst.
A material known as a catalyst would be an element or just a compound that quickens chemical reactions. The procedure of catalysis involves introducing a catalyst to a chemical reaction to speed up the process. The reaction does not consume catalysts, and they are unaffected after it.
Proteins called enzymes serve as biological catalysts. Chemical reactions are accelerated by catalysts. Numerous biological processes, including development, blood clotting, disease treatment, respiration, digestion, reproduction, as well as many more, are aided by enzymes.
Proteins are called enzymes to catalyze chemical reactions in our bodies. By reducing the activation energy, they serve as a catalyst to quicken the process. The enzyme has been referred to as a biocatalyst since it speeds up a chemical reaction again without altering its equilibrium.
Therefore, In living things, enzymes serve as a catalyst.
Hence, the correct answer will be option (B)
To know more about enzymes and catalyst.
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