MATHEMATICS HIGH SCHOOL

In the following Laplace transform, how do you get rid of the cos(2at)*sin(at)?L{sin^3 (at)}
L{ sin(at) * [1/2 ( 1 - cos(2at)]}
1/2 L{sin(at)} - 1/2 L{cos(2at)*sin(at)}
1/2 * (a^2)/(s^2 + a^2) - 1/2 L{cos(2at)*sin(at)}

Answers

Answer 1
Answer: sin A cos B=1/2[sin(A-B)+sin(A+B)]
sin(at)*cos(2at)=1/2[sin(3at)-sin(at)]

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The sum of the digits of a two-digit number is 9. If the digits are reversed, the new number is 27 less than the original. Find the original number.

An element with mass 1000 grams decays by 14.8% per minute. How much of the element is remaining after 11 minutes, to the nearest 10th of a gram?

Answers

100\%-14.8\%=85.2\%=0.852\n\n1000g\ *\ 0.852^(11)\approx171.7g\leftarrow answer

Solve these following easy questions: a) Round 23.542 to the nearest tenth.
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Answers

Answer:

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What is the ratio of 33/36

Answers

all you have to do is find a number that both of them is divisible by and divide it by them. for example, when you divide it by 3, you will get 11/12
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Can someone help asap​

Answers

Answer:

The gasoline used by truck =

Total gas - Gasoline left..

Gas used = 23/3-123/27

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"Find the point of intersection for each system of linear equations. Which method did you use & why?"

Answers

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What is 6.99 × 10−4 in standard form? A) 0.0000699 B) 0.000699 C) 0.0699 D) 6,990

Answers

Option B: 0.000699 is the standard form

Explanation:

Given that the expression 6.99* 10^{-4

We need to determine the standard form of the expression 6.99* 10^{-4

Since, the power is in negative four, then we need to move the decimal point four places before the number 6.

Moving the decimal point four places before the number 6, we get,

0.000699

Thus, the standard form of the given expression is 6.99* 10^{-4

Therefore, Option B is the correct answer.

Answer:

It is B

Step-by-step explanation:

I just took it on USA test prep :)
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