Which ion is part of every amino acid?

Answers

Answer 1
Answer: In an amino acid, there are two ions present - the positively charged and the negatively charged. The positively charged is called the amino group while the negatively charged is the carboxyl group.

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An equilibrium mixture of PCl5(g), PCl3(g), and Cl2(g) has partial pressures of 217.0 Torr, 13.2 Torr, and 13.2 Torr, respectively. A quantity of Cl2(g) is injected into the mixture, and the total pressure jumps to 263.0 Torr (at the moment of mixing). The system then re-equilibrates. The appropriate chemical equation is:PCl3(g) + Cl2(g) ---> PCl5(g)

Calculate the new partial pressures after equilibrium is reestablished. [in torr]

PPCl3

PPCl2

PPCl5

Answers

equilibrium is a situation in which economic forces such as supply and demand are balanced and in the absence of external influences the values of economic variables will not change

The equilibrium constant depends on the following:-

  • Pressure
  • Volume

The formula used in the question is as follows:-

k_p = (P_1)/(P_1*P_2), After putting the value, the equilibrium constant is as follows:-

k_p = (217)/(13.2*13.2)

After solving it, the equilibrium constant is 1.245.

The pressure in different systems is as follows:-

Hence, the total pressure is:- P_1 + P_2+ P_3

263 = 13.2 + P_2 + 217

After solving it, the P2 is 32.8torr.

The equilibrium constant in the second case is:-

k_p = (P_1^')/(P_1^' * P_2^')

After putting the value,

1.245= (217+x)/((13.2-x )* (32.8-x))

After solving, the value of x is 6.402torr

Hence, the partial pressure PCL_3,\ CL2, \ PLC_5\ is 6.798, 26.398, and 223.402 respectively.

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Answer:

The new partial pressures after equilibrium is reestablished for PCl_3:

P_1'=6.798 Torr

The new partial pressures after equilibrium is reestablished Cl_2:

P_2'=26.398 Torr

The new partial pressures after equilibrium is reestablished for PCl_5:

P_3'=223.402 Torr

Explanation:

PCl_3(g) + Cl_2(g)\rightleftharpoons PCl_5(g)

At equilibrium before adding chlorine gas:

Partial pressure of the PCl_3=P_1=13.2 Torr

Partial pressure of the Cl_2=P_2=13.2 Torr

Partial pressure of the PCl_5=P_3=217.0 Torr

The expression of an equilibrium constant is given by :

K_p=(P_1)/(P_1* P_2)

=(217.0 Torr)/(13.2 Torr* 13.2 Torr)=1.245

At equilibrium after adding chlorine gas:

Partial pressure of the PCl_3=P_1'=13.2 Torr

Partial pressure of the Cl_2=P_2'=?

Partial pressure of the PCl_5=P_3'=217.0 Torr

Total pressure of the system = P = 263.0 Torr

P=P_1'+P_2'+P_3'

263.0Torr=13.2 Torr+P_2'+217.0 Torr

P_2'=32.8 Torr

PCl_3(g) + Cl_2(g)\rightleftharpoons PCl_5(g)

At initail

(13.2) Torr     (32.8) Torr                        (13.2) Torr

At equilbriumm

(13.2-x) Torr     (32.8-x) Torr                        (217.0+x) Torr

K_p=(P_3')/(P_1'* P_2')

1.245=((217.0+x))/((13.2-x)(32.8-x))

Solving for x;

x = 6.402 Torr

The new partial pressures after equilibrium is reestablished for PCl_3:

P_1'=(13.2-x) Torr=(13.2-6.402) Torr=6.798 Torr

The new partial pressures after equilibrium is reestablished Cl_2:

P_2'=(32.8-x) Torr=(32.8-6.402) Torr=26.398 Torr

The new partial pressures after equilibrium is reestablished for PCl_5:

P_3'=(217.0+x) Torr=(217+6.402) Torr=223.402 Torr

When 2 mol of Fe(s) reacts with Cl2(g) to form FeCl3(s) according to this equation, 799 kJ of energy is evolved. Calculate ΔrHo. A) -399.5 kJ mol^-1 B) -199.75 kJ mol^-1 C) 399.5 kJ mol^-1 D) 199.75 kJ mol^-1

Answers

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Some scientific evidence suggests that our universe is ever-expanding from a hot and dense initial state. Briefly describe at least one piece of evidence that supports the theory known as the Big Bang.

Answers

cosmic microwave background radiation (CMBR) is one piece of evidence for the big bang

Answer:

Cosmic microwave background and Hubble's Law.

Explanation:

Microwave background is basically electromagnetic radiation, but it's the remanent from earlier periods of the universe, they are the oldest electromagnetic wave in the Universe. Also, Hubble's Law says that the Universe faster galaxies are those are further away, because they belong to the first period of the explosion.

Gabriella weighs 450 N. She climbs a flight of stairs to a height of 3 m. It takes her 5 seconds. How much work does Gabriella do when she climbs the stairs?A.
150 J

B.
270 J

C.
1350 J

D.
2250 J

Answers

The formula that can be applied in this problem is W = Fd where W is work, F is the force and d is distance. You have 450N and 3m, all you have to do is to multiply it.

W = Fd

W = (450N) (3m)

W = 1350J

The answer is letter C.

A placebo is a substance that is unlikely to affect the dependent variable. a. True
b. False

Answers

Answer : Option a) True.

Explanation : A placebo is a substance that is unlikely to affect the dependent variable. True as in a clinical trial for any change in the placebo arm is known as the placebo response, and the difference between this placebo response and the result of no treatment is called as the placebo effect. Therefore, a placebo may be given to any person in a clinical context in order to deceive that recipient into thinking that it is an part of active treatment. It actually resembles a drug but is not an actual active drug, so, it is clear that it will not affect dependent variable.

True. A placebo is a substance used to ensure that the independent variable is what is affecting the dependent variable. Usually used in drug trials

Nuclear fission produces about one-fifth the power in the United States. An unintended positive consequences of nuclear power has been that A) a lot of power is generated. B) radioactive waste is created. C) less greenhouse gases are created. D) nuclear power plants are targets for terrorists.

Answers

answer is C) less green house gases are created

Answer:

b

Explanation: i did it and it wasn't c it was b