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The value of delta for the [C_rF_6]^3- complex is 182 kJ/mol. Calculate the expected wavelength of the absorption corresponding to promotion of an electron from the lower-energy to the higher-energy of orbital set in this complex. (Remember to divide by Avogadro's number.) Should the complex absorb in the visible range?

Answers

Answer 1

Answer:

Answer: Yes the absorb in the visible range.

Explanation:

The relationship between wavelength and energy of the wave follows the equation:

$E=(Nhc)/(\lambda)$

where,

$E$ = energy of the wave = 182 kJ/mol = 182000 J/mol

N = avogadro's number = $6.023* 10^(23)$

h = plank constant = $6.6* 10^(-34)Js^(-1)$

c = speed of light = $3* 10^8m/s$

$\lambda$ = wavelength of the wave = ?

Putting all the values:

$182000=(6.023* 10^(23)* 6.6* 10^(-34)* 3* 10^8m/s)/(\lambda)$

$\lambda=0.65* 10^(-6)m=650nm$ $(1nm=10^(-9)m)$

The wavelength range for visible rays is 400 nm to 750 nm, thus the complex absorb in the visible range.

Answer 2

Answer:

Final answer:

The expected wavelength of the absorption in the [CrF6]3- complex cannot be calculated without knowing the exact value of ΔE. Therefore, it is unclear if the complex will absorb in the visible range.

Explanation:

In this complex, the value of delta (Δ) is 182 kJ/mol. To calculate the expected wavelength of the absorption corresponding to the promotion of an electron from the lower-energy orbital to the higher-energy orbital, we can use the equation: Wavelength = (hc)/(ΔE), where h is Planck's constant and c is the speed of light. By substituting the given values and dividing by Avogadro's number, we can calculate the expected wavelength.

However, the information given in the question does not provide the exact value for ΔE. Without this information, it is not possible to calculate the expected wavelength accurately. Therefore, we cannot determine if the complex will absorb in the visible range.

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An element x is found to have a mass number of 31 and atomic number of 17. idenrify the group and the period to which it belongs?

Answers

Answer:

Well atomic number 17 is Chlorine, which is most commonly found as a gas, and is period 7.

Explanation:

elements found on period 7 are some of the most unstable elements.

Gasline is solid by the liter in many countries. How many liters are required to fill a 12.0-gal gas tank?

Answers

Answer : The volume required to fill the gas tank is, 45.42 liters

Explanation :

Conversion used for gallon to liters are:

$1\text{ gallon}=3.785\text{ liter}$

As we are given the volume of gas tank in gallon is, 12.0 gal

Now we have to determine the volume of gas tank in liters.

As, 1 gallon = 3.785 liter

So, 12.0 gallon = $\frac{12.0\text{ gallon}}{1\text{ gallon}}* 3.785\text{ liter}=45.42\text{ liter}$

Therefore, the volume required to fill the gas tank is, 45.42 liters

What data should be plotted to show that experimental concentration data fits a first-order reaction? A) 1/[reactant] vs. time B) [reactant) vs. time C) In[reactant] vs. time D) In(k) vs. 1/1

Answers

The data that should be plotted to show that experimental concentration data fits a first-order reaction is: C. In [reactant] vs. time.

What is a first-order reaction?

A first-order reaction can be defined as a type of chemical reaction in which the reaction rate (rate of reaction) is directly proportional to the concentration of the reacting chemical substance or elements.

Mathematically, the integrated rate law equation for a first-order reaction is given by this formula:

$A=A_o e^(kt)$

Where:

A is the concentration after time (t).

$A_o$ is the initial concentration of the reactant.

t is the time.

k is the rate constant.

Taking the ln of both sides, we have:

$ln(A)=ln(A_o)-kt$

Therefore, the data that should be plotted to show that experimental concentration data fits a first-order reaction is In[reactant] versus time.

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Answer:

C) In[reactant] vs. time

Explanation:

For a first order reaction the integrated rate law equation is:

$A = A_(0)e^(-kt)$

where A(0) = initial concentration of the reactant

A = concentration after time 't'

k = rate constant

Taking ln on both sides gives:

$ln[A] = ln[A]_(0)-kt$

Therefore a plot of ln[A] vs t should give a straight line with a slope = -k

Hence, ln[reactant] vs time should be plotted for a first order reaction.

Identify the type of bonding within each substance. Co ( s ) ionic covalent metallic CoCl 2 ( s ) covalent ionic metallic CCl 4 ( l ) metallic covalent ionic

Answers

Answer:

1. Co ( s ) - metallic bonding

2. CoCl₂ ( s ) - ionic bonding

3. CCl₄ ( l ) - covalent bonding

Explanation:

Metallic bonding -

It is the type of bonding present between the atoms of the metals , via the electrostatic interaction between the metal and the delocalized electrons , is known as metallic bonding .

For example ,

Mostly metals show metallic bonding .

Ionic bonding -

It is the type of bonding present between the ions i.e. , the cation and the anion is known as ionic bonding .

For example ,

Mostly ionic compound , like salts show ionic bonding .

Covalent bonding -

It is the type of bonding which is present between shared pair of electrons , is known as covalent bonding .

For example ,

Most of the carbon compounds are capable to show covalent bonding .

Hence , from the question ,

1. Co ( s ) - metallic bonding

2. CoCl₂ ( s ) - ionic bonding

3. CCl₄ ( l ) - covalent bonding

Final answer:

Co(s) forms metallic bonds, CoCl2(s) forms ionic bonds, and CCl4(l) forms covalent bonds.

Explanation:

The type of bonding within each substance can be identified by understanding the nature of the substances.

Co(s): Co (solid) denotes a metal, and metals typically form metallic bonds.
CoCl2(s): CoCl2 is a compound formed between a metal (Co) and a nonmetal (Cl), making it an ionic compound.
CCl4(l): CCl4 is a molecular compound composed of carbon and chlorine atoms, so it forms covalent bonds.

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Please help me I will give a brainleist to the. first person to answer

Answers

Answer:

Explanation:

The Agricultural Revolution gave Britain the most productive agriculture in Europe, with 19th-century yields as much as 80% higher than the Continental average. ... By the 19th century, marketing was nationwide and the vast majority of agricultural production was for the market rather than for the farmer and his family.

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A sample of phosgene gas at an initial concentration of 0.500 m is heated at 527 °c in a reaction vessel. at equilibrium, the concentration of co (g) was found to be 0.046 m. calculate the equilibrium constant for the reaction at 527 °c.

Answers

Answer : The equilibrium constant will be - 0.454

Explanation : The reaction is given below;

$COCl_(2) \ \textless \ ----\ \textgreater \ CO + Cl_(2)$

We need to find Equilibrium constant - $K_(c)$ ;

$K_(c)$ = [CO] [ $Cl_(2)$ ] / $[COCl_(2) ]$

So, $K_(c)$ = [0.046] X [0.046] / [0.5 - 0.046]

Therefore, $K_(c)$ = 0.454

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