MATHEMATICS HIGH SCHOOL

If x2 - 4 = 45, then x could be equal to
9
3
5
-7
-4

Answers

Answer 1
Answer: x^(2) - 4 = 45

x^(2) = 45 + 4

x^(2) = 49

\sqrt{ x^(2) } = √(49)

x = 7
Answer 2
Answer: Hi:))

x² - 4 = 45

X² = 45 + 4

X² = 49

√x² = √49

x = 7

Related Questions

Suppose that you roll a pair of honest dice. If you roll a total of​ 6, you win​ $18; if you roll a total of​ 11, you win​ $72; if you roll any other​ total, you lose​ $9. Let X denote the payoff in a single play of this game. Find the expected value of a play of this game. Round your answer to the nearest penny.A.) -​ $0.50B.) −​ $1.00C.) ​$0D.) ​$0.75E.) −​ $0.75
What is 3/7 in words
If x is the principle square root of 7, what must be true.
Consider the points A (-16, 39), B(4, 3) and C (9, -6):Find the slope of AB.
Solve for H .........

Name 3 pairs of numbers that have 5 as their greatest common factor (gcf). Use each number only once in your answer.

Answers


The greatest common factor of two variables or numbers can be determined by listing all of the factors of the two numbers and then determining which is the greatest among all. In this case, one pair can be 10 and 15, 20 and 25, and 35 and 45. 
so 3 pairs of nr. with gcf. the 5 

1. 5 and 10 what are 5*1 and 5*2
2. 15 and 20  --- 5*3 and 5*4
3. 25 and 30 --- 5*5 and 5*6 

hope helped 

Circle P
has center
P
(2, 0) and radius 20. Circle
Q
has center
Q
(0, 4) and radius 2.
(a)
Describe the rule for translating center
Q
onto center
P
.
(b)
Determine the scale factor for dilating circle
Q
so that it has the same radius as circle
P.
(c)
Are circles
P
and
Q
similar? Explain your answer.

Answers

Siras !  Don't try to picture this all in your head !
You'll wear out your brain.
You MUST sketch it on a piece of paper.
Draw an x-axis and a y-axis, then draw the two circles.

I'm drawing myself a picture right now, and I'm
supposed to be some kind of a genius.

a).  In order to move Circle-Q so that both centers are
at the same point, you need to move the center of Q
4 units down and 2 units to the right.
      When you do that, you'll have the little circle inside the
big circle, with their centers both at the same place.

b).  The radius of Q is 2.
       The radius of P is 20.
       What do you have to multiply 2 by, in order to get 20 ?
       THAT's the scale factor to dilate Q so that it has the same
radius as P.
       When you do that, suddenly it'll look like you only have one circle
on the paper ... they'll both have the same radius and their centers are
at the same place, so you can't tell them apart.

c).  All circles are similar !

I went online (you could easily go there too).  I searched the question
"Are circles similar ?" and a lot of interesting stuff came up.  (you could
do that too).  I saw a lot of ways to prove that all circles are similar. 
The best one says:

       Two figures are "similar" if you can make one of them
       exactly fit on top of the other one (make them congruent)
       with translations and dilations.

You just did that with P and Q !

-- Translation is moving them around.
   You moved Q and put the centers of both circles at the same place.

-- Dilation is blowing it up or blowing it down, so its size changes
but its shape doesn't change.
   You blew Q up so that it had the same radius as P.
   Then the two circles exactly fit over/under each other.

So the two circles are similar. 

N=480×10^9
Write N as a product of powers of its prime factors.

Answers

N = 5^(10) × 2^(14) × 3

This is about prime factors

By definition, a prime factor is a factor of a number and that factor is also a prime number.

A prime number is one that is divisible by only itself and 1.

The number we have is; 480 × 10^(9)

Now, let's list the prime factors or 480 and they are;

2, 3, 5

Now, using these prime factors alone to get 480, we have;

5 × 3 × 2 × 2 × 2 × 2 × 2 = 480

In powers, gives;

5 × 3 × 2^(5)

Now,the 10^(9) with the 480 can also be expressed in terms of it's prime factors which are 2 and 5 as;

(5 × 2)^(9)

Expanding this gives; 5^(9) × 2^(9) = 10^(9)

Thus;

480 × 10^(9) = 5 × 3 × 2^(5) × 5^(9) × 2^(9)

This gives;

5^(10) × 2^(14) × 3

Read more at; brainly.com/question/4853862

Answer:

I got 5^10 x 2^14 x 3

Step-by-step explanation:

1. Do a tree to find 480 as a product of its prime factors

2. You should get 480= 5x2x3x2x2x2x2

3. 10 expressed as a product of its prime factors is 5x2

4. so 10^9 expressed as a product of its prime factors would be

5x2x5x2x5x2x5x2x5x2x5x2x5x2x5x2x5x2

5. You can then write out 480x10^9 as a product of its prime factors

5x2x3x2x2x2x2x5x2x5x2x5x2x5x2x5x2x5x2x5x2x5x2x5x2

6. change this to use powers

5^10 x 2^14 x 3

Distance between Town A and Town B = 420 miles. Average speed of automobile = 45 mph. Time to travel between Town A and Town B = _____ hours.

Answers

Speed=distance / time  ⇒ time=distance/ speed.
Data:
distance=420 miles
speed=45 mph=45 miles/hour

Time=(420 miles) / (45 miles/ hour)=9.333... hour=9 hour, 20 minutes.

Answer:
Time to travel between Twon A and Town B=9.33 hours.

If f(x) = 2x2 +5/(x-2),(the / means square root, not divide) complete the following statement: The domain for f(x) is all real numbers___than or equal to 2.

Answers

Answer:

Greater

Step-by-step explanation:

The domain for f(x) is all real numbers greater than or equal to 2.

x>=2

What is the area of this figure?

Answers

Answer:

35 in^2

Step-by-step explanation:

15+20=35
Other Questions
The slope of the line whose equation is 3x - 2y = 4 is 2/3 3/2 -2 2x + y = 8 x + y = 4 The lines whose equations are given intersect at (4, 0) (0, 4) all points on the line The points (2, 1), (3, 3), (4, 5), and (5, 6) are collinear. a. Trueb. False
Find the quadratic equation whose roots are 3+- i / 2
Fill in the missing number. (please explain your answer)​
Find the value of 18 ÷ 9 ∙ 3