When the ideal gas law constant 0.0821 is used, what unit of pressure should be used in the ideal gas law calculation?

Answers

Answer 1
Answer: The pressure unit is in atmospheres or atm. To confirm this from the ideal gas equation: 

R = VP/nT

plugging in the standard values of pressure, temperature and molar volume,

R = (22.4L/mo)l(1atm)/(273.15K) = 0.0821

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Which of the following is not a physical change? Melting ice

Breaking glass

Filtering a mixture

Burning paper

Answers

When you burn paper you are chemically altering it so that is the correct answer. When you do all the other choices all of the components stay the same. Just because it changes shapes doesn't mean it'll change chemically toom

ASAP pleaseee and Thankyou​​

Answers

Answer:

I know the answer, but it is hard to explain

Explanation:

yIt easy u but the single letter in the outside boxes. Then u but the one in the middle box. But the BB in one corner. then but bb on the opposite corner. Then but Bb on the other box.

Answer:

father.....Bb

mother.....bb

offspring, 50%Bb brown eyes ,50%bb blue eyes

Calculate the number of moles56.75 g of Al(NO3)3
8.35 g of Al2(SO4)3
3.8 g of FeSO4

Answers

number of moles = mass /molar mass

Why do comets have tails

Answers

Answer:

Comets are composed of ice, dust and frozen gases. The core of the comet is known as nucleus which is formed of rocks and frozen gases. Coma is the atmosphere of the comet. As the comet enters the inner solar system, the coma expands due to sublimation of frozen gases. As it nears the sun, the coma extends backwards and forms a long tail. It extends backwards due to the solar wind. The charged particles from the sun take away the evaporated material and dust of the comet backwards forming tail.

As a comet approaches the Sun, it starts to heat up. The ice transforms directly from a solid to a vapor, releasing the dust particles embedded inside. Sunlight and the stream of charged particles flowing from the Sun – the solar wind – sweeps the evaporated material and dust back in a long tail.

As the number of effective collisions between reacting particles increases the rate of reaction

Answers

the rate of reaction increases 

show me the steps for solving this problem how many grams of O2 are required to burn 46.0 grams of C5H12

Answers

(MM)C5H12=5x12+12x1=72g/mol
(MM)O2=2x16=32g/mol
Acoording to equation:
C5H12 + 8O2 => 5CO2 + 6H2O

The proportion between C5H12 and O2 is 1:8 in mol

So: 72/16=46/x finale x=10,2g of O2