MATHEMATICS HIGH SCHOOL

Lori works as a cartoonist for a teen magazine.The time she spent sketching is given by the equation m=12s, where mis the number of minutes and s is the number of sketches. If lori made 3/4 of a sketch, she spent minutes sketching

Answers

Answer 1

Answer:

Answer:

Lori spends 9 minutes on sketching $(3)/(4)$ th of a sketch.

Step-by-step explanation:

Given equation:

$m=12\ s$

where $m\rightarrow$ number of minutes Lori spends on sketching

and $s\rightarrow$ number of sketches Lori makes.

We need to calculate the time spent by Lori in sketching $(3)/(4)$ of a sketch.

So we know the value of $s=(3)/(4)$ as $s$ represents number of sketches and in this situation Lori has sketched only a fraction of a painting.

So we plugin $s=(3)/(4)$ in the equation and calculate $m$ which is time spent by Lori sketching $(3)/(4)$ th of a sketch.

$m=12\ (3)/(4)$

$m=(36)/(4)$

∴ $m=9$ minutes (Answer)

∴ Lori spends 9 minutes on sketching $(3)/(4)$ th of a sketch.

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Given f(x) = —x^2 - 13, find f(-6)
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Evaluate :- a) (6.4)² - (3.6)²

Please help! Super confused lol

Answers

The length of OX would be 6.5 units.

If you look at the angle, it is bisected equally - meaning the ray separating it is a bisector. (The two triangles are similar by angle-angle similarity.) Since the line is a bisector, you simply divide 13 by 2 to get 6.5.

OX = 6.5

13=DX,

OX = 0.5*DX

13*0.5=6.5

Examples of prime numbers

Answers

1,2,3,5,7,11.... Any number that are only divisible by 1 and the number itself

What is the answer for the picture #26

Answers

Oh you're so close !

Just look again at #22, right above it.
Your answer to #22 is correct.
Think hard again about #22.
You'll see how it can help you solve #26, completely on your own.

the answer is 1/13 ². Because if you divide 1/169 and 1/13, then you get 1/13. With that being said, if you multiply 1/13 and 1/13, then you get 1/169. And of course the symbol ( ² ) means squared so you multiply that number he (² ) is over twice. So like 3², 3*3=9.

Helpful???

The total number of laps needed to complete a bike marathon is 75. Kayla completed at least 68 laps. How many possible complete laps could Kayla have completed. Please show work. I'm offering lots of points for this question. Thanks you guys.

Answers

well she needs to complete 75 laps to complete the race so 75 is the upper limit. She has completed at least 68 laps so the lower limit is 68. so the number of laps she could have completed could be from 68 to 75 so the number of laps (x) can be reprented by this inequallity 68 < x < 75

well, I'm not sure if this is correct, it probably isn't, and I'm sorry if it isn't, but i think kayla could have completed 75 laps because there was only 75 laps in the race.

List the midline , amplitude and period of the graph then write an equation

Answers

Answ

Step-by-step explanation:

2/7m-1/7=3/14

Please solve showing work

Answers

(2/7)m - (1/7) = 3/14
2m/7 =(3/14) + (1/7)
2m/7 = (3/14) + 2(1/7)
here we are multiplying 2 with 1/7 to make the denominator same for addition.
2m/7 = (3/14) +(2/14)
2m/7 = (3 + 2)/14
2m/7 = 5/14
2m = (5 *7)/14
2m = 35/14
2m = 5/2
m = 5/4
m = 1.25
So the value of "m" is 1.25

Solution for $(2)/(7)m - (1)/(7) = (3)/(14) \ is \ m = (5)/(4) \ or \ m = 1(1)/(4) \ or \ m = 1.25$

Further explanation

It is a case about one variable linear quations and we have to solve the equation to get the variable m.

Our main goal is to isolate the variable m alone at the end of the process on one side of the equation, until the variable will be equal to the value on the opposite side.

Let us add $(1)/(7)$ to both sides:

$(2)/(7)m - (1)/(7) + (1)/(7) = (3)/(14) + (1)/(7)$

$(2)/(7)m = (3)/(14) + (1)/(7)$

On the right side for the addition operation, we equate the common denominator by multiplying $\ (1)/(7) \ by \ (2)/(2)$

$(2)/(7)m = (3)/(14) + (2)/(14)$

Then we combine terms to get:

$(2)/(7)m = (5)/(14)$

We divide by the coefficient of m, or in other words, multiply both sides by $(7)/(2)$ :

$(2)/(7)m * (7)/(2) = (5)/(14) * (7)/(2)$

Finally, the solution is obtained as follows

$m = (35)/(28)$

We simplify fractions, both the numerator and denominator are divided equally by 7.

$\boxed{ \ m = (5)/(4) \ }$

In the form of mixed fractions, we get:

$\boxed{ \ m = 1 (1)/(4) \ }$

In decimal form, we get

$m = 1 (25)/(100) \rightarrow \boxed{ \ m = 1.25 \ }$

Wanna check the solution into the equation?

$\big( (2)/(7) * (5)/(4) \big) - (1)/(7) = (3)/(14)$

$(10)/(28) - (1)/(7) = (3)/(14)$

$(5)/(14) - (2)/(14) = (3)/(14)$

$(3)/(14) = (3)/(14)$

Both sides show the same value, so the solution is correct.

These are quick steps in summary:

$(2)/(7)m - (1)/(7) = (3)/(14)$

$(2)/(7)m = (3)/(14) + (1)/(7)$

$(2)/(7)m = (3)/(14) + (2)/(14)$

$(2)/(7)m = (5)/(14)$

$m = (5)/(14) * (7)/(2)$

$m = (35)/(28)$

$\rightarrow \boxed{ \ m = (5)/(4) \ }$

$\rightarrow \boxed{ \ m = 1 (1)/(4) \ }$

$\rightarrow \boxed{ \ m = 1.25 \ }$

Note:

The important thing to do is how to manipulate both sides of the equation with the algebraic properties of equality such as:

adding,
subtracting,
multiplying, and/or
dividing both sides of the equation with the same number.

In the form of fractions, the steps that must be considered are

equate the denominator,
simplify fractions, and
for the final answer, convert fractions to mixed fractions or decimal forms

All these processes can occur repeatedly until the isolated variables are obtained on one side of the equation.

Let's practice a lot until you get used to and know which operations should be done first.

Learn more

A word problem that forms a single variable linear equation brainly.com/question/1566971
Learn more about single variable linear equation that has no solution, has one solution, and has infinitely many solutions brainly.com/question/2595790
Questioning the stages of solving a word problem about one variable linear equations brainly.com/question/2038876

Answer details

Grade : Middle School

Subject : Mathematics

Chapter : Linear Equation in One Variable

Keywords : solve, solution, variable, coefficient, 2/7m - 1/7 = 3/14, 5/4, 1 1/4, 1.125, algebraic properties of equality, one, linear equation, isolated, manipulate, operations, add, substract, multiply, divide, fraction, equate, denominator, numerator, both sides, decimal, brainly

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