Fatty acids are carboxylic acids with a long, unbranched hydrocarbon chain. There are three main classes of fatty acids. Classify the fatty acids as saturated, monounsaturated, or polyunsaturated.

Answer:

freezing point   (°C) of the solution =  - 3.34° C

Explanation:

From the given information:

The freezing point (°C) of a solution can be prepared by using the formula:

where;

i = vant Hoff factor

the vant Hoff factor is the totality of the number of ions in the solution

Since there are 1 calcium ion and 2 nitrate ions present in Ca(NO3)2, the vant Hoff factor = 3  

= 1.86 °C/m

m = molality of the solution and it can be determined by using the formula

which can now be re-written as :

molality = 0.599 m

∴

The freezing point (°C) of a solution can be prepared by using the formula:

the freezing point of water - freezing point of the solution

3.34° C = 0° C -  freezing point of the solution

freezing point  (°C) of the solution =  0° C - 3.34° C

freezing point   (°C) of the solution =  - 3.34° C

There is 65% of NaHCO3 in the sample.

The equation of the reaction is;

HA + NaHCO3 -----> NaA + CO2 + H2O

Amount of CO2 formed = mass/molar mass

mass of CO2 = 0.561 g/44 g/mol = 0.013 moles

From the balanced reaction equation;

1 mole of NaHCO3 yields 1 mole of CO2

0.013 moles of Na2CO3 yields 0.013 moles of CO2

Hence, mass of NaHCO3 in the sample = 0.013 moles × 84 g/mol = 1.092 g of NaHCO3

Percentage by mass of NaHCO3 = 1.092 g/1.68 g ×100/1

= 65%

Learn more: brainly.com/question/25150590

Answer:

63.75%.

Explanation:

The first step here is to write out the reaction showing the chemical reaction between the two chemical species. Thus, we have;

HA(aq) + NaHCO3 --------------> CO2(g) + H20(l) + NaA(aq).

Therefore, the mole ratio is 1 : 1 : 1 : 1 that is go say one mole of HA reacted with one mole of NaHCO3 to give one mole of CO2 and one .ole of NaA.

Hence, the number of moles of CO2 = mass/molar mass = 0.561/44 = 0.01275 moles.

Thus, the number of moles of NaHCO3 = number of moles of CO2 = 0.01275 moles.

Therefore, we have ( 0.01275 moles × 84 g/mol) grams = 1.071 g NaHCO3 in the mixture.

Therefore, the percent by mass of N a H C O 3 in the original mixture = 1.071/1.68 × 100 = 63.75%.

Explanation:

A compound is a substance that contains more than two different atoms in a fixed ratio by mass. Elements of a compound are chemically combined together.

A homogeneous mixture is defined as a mixture in which solute particles are uniformly distributed into the solvent.

Whereas a heterogeneous mixture is defined as a mixture in which solute particles are non-uniformly distributed in a solvent.

In both homogeneous and heterogeneous mixture there is no chemical combination between solute and solvent particles.

Therefore, each given substance is classified as follows.

(a) Orange juice :  As it contains pulp of orange along with the liquid which are not present in uniform composition. Hence, orange juice is a heterogeneous mixture.

(b) vegetable soup : This soup also contains vegetable pieces and spices which are non-uniformly distributed. Hence, it is also a heterogeneous mixture.

(c) cement : It contains several different compound present in definite composition. Hence, cement is a homogeneous mixture.

(d) calcium sulfate : Its chemical formula is and in this compound both calcium and sulfate atoms are chemically combined together. Therefore, calcium sulfate is a compound.

(e) Tea : It is a homogeneous mixture as there is uniform composition of tea water in milk.

Answer:

.

Explanation: