Jerome works as a waiter. He earns 80$ each weekend plus 15 percent in tips on meals served. Jerome served 725$ worth of meals last weekend. How much did Jerome earn last weekend?

Answers

Answer 1
Answer:

Answer:

  $188.75

Step-by-step explanation:

His earnings were ...

  $80 + 0.15 × $725 = $80 +108.75 = $188.75

Jerome earned $188.75 last weekend.


Related Questions

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Please help what is m+6 = 20
Which one is greater 2.857 or 2.87
3t + 15 = 45. solve pls​
The ratio of the radii of two circles is 3:7. What is the ratio of their circumferences? A. 1:1 B. 3:7 C. 3:14π D. 6π:7 E. 9:49

Six students share 8 granola bars equally. How many granola bars does each student get?

Answers

Answer:

1 whole one and a third of one.

Step-by-step explanation:

1 1/3 of a granola bar

Answer: 1.33333333333 or 1.3 as a repeating decimal

Just divide 8 ÷ 6

Three hundred high school seniors were surveyed about their intended college majors. The results are displayed in the Venn Diagram below: A Venn Diagram titled College Majors with two circles labeled Math and Science. In the math portion is 120. In the intersection is blank. In the Science portion is 50. The area outside the two circles is labeled 100.

If a student is randomly selected from the group, what is the probability that they are majoring in both math and science? Round your answer to the nearest whole percent.

Answers

I see what's going on, we have to find the number of students in the intersection. Math is 120, Science is 50, neither is 100. Add all of these together, 120 + 50 + 100 = 270, then subtract from 300, 300-270 = 30
Now, we divide 30/300 which gives .1, move the decimal over 2 places to the right and that makes it 10%

Answer: (1)/(10)

Step-by-step explanation:

Since, The total number of student = 300

Out of which,

The number of students who are only in Maths  = 120

And, The number of students who are only in Science  = 50

While, the students who are not from any subject = 100

Hence, the number of student who are from both maths and science = Total student - Maths student (only) - science student (only) - None

= 300 - 120 - 50 - 100

= 30

That is, there are 30 students who are both from science and maths,

Thus, the probability of selecting one student who is both from maths and science = 30/300 = 1/10

Ship A receives a distress signal from the southwest, and ship B receives a distress signal from the same vessel from the north. At what location is the vessel in distress located? Describe how you arrived at your conclusion using complete sentences. You must show all work in order to receive credit.

Answers

g=t negative 320+f5 t=b

Check my answer please? If p varies directly with q, and p = 8 when q = 2, what is the value of p when q = 7?

A.
p = 40

B.
p = 100

C.
p = 28

D.
p = 1

i think that it's c.

Answers

yes you are right it's C

Formulate the quadratic function that contains the points (-1,2), (0,-1) and (2,5). F(x) = 2x2 - x - 1 f(x) = 2x2 x 1 f(x) = 2x2 - x 2 f(x) = 2x2 - x - 2.

Answers

Answer:

  (a)  F(x) = 2x^2 - x - 1

Step-by-step explanation:

The quadratic regression function of a graphing calculator does this nicely.

The one attached shows the function to be ...

  F(x) = 2x^2 -x -1

__

Additional comments

The supplied point (0, -1) tells you the y-intercept is -1. That means the constant in the function's equation will be -1. Only one answer choice has that.

  F(x) = 2x^2 -x -1

__

As always, the first step in problem solving should be to look at the problem, and look at the available solution choices. Understanding these things will generally allow you to throw out answer choices that don't provide a sensible answer to the question. Here, that leaves you with only one answer choice, which is all you need.

Simplify the expression

Answers

Answer:

The simplified form of given expression\frac{15xy}{5x^{(1)/(2)}y^2} is \frac{3x^{(1)/(2)}}{y}

Step-by-step explanation:

Given: Expression \frac{15xy}{5x^{(1)/(2)}y^2}

We have to write the given expression in simplified form,

Consider the given expression \frac{15xy}{5x^{(1)/(2)}y^2}

Divide the numbers (15)/(5)=3

we get,

=\frac{3xy}{y^2x^{(1)/(2)}}

Apply exponent rule , (x^a)/(x^b)\:=\:x^(a-b)

\frac{x}{x^{(1)/(2)}}=x^{1-(1)/(2)}=x^{(1)/(2)}

we get,

=\frac{3yx^{(1)/(2)}}{y^2}

Cancel y term, we have,

=\frac{3x^{(1)/(2)}}{y}

Thus, The simplified form of given expression\frac{15xy}{5x^{(1)/(2)}y^2} is \frac{3x^{(1)/(2)}}{y}

Answer:

3x^{(1)/(2)}y^(-1)

Step-by-step explanation:

The given expression is:

\frac{15xy}{5x^{(1)/(2)}y^2}

We have to simplify the above given expression.Thus,

Firstly, divide the constant terms, we get

(15)/(5)=3

Now, applying the exponent law, that is (x^a)/(x^b)=x^(a-b), we have

\frac{xy}{x^{(1)/(2)}y^2}=x^{1-(1)/(2)}y^(1-2)=x^{(1)/(2)}y^(-1)

Thus, the simplified form of the above given equation is:

3x^{(1)/(2)}y^(-1)