If the work required to stretch a spring 2 ft beyond its natural length is 12 ft-lb, how much work is needed to stretch it 9 in. beyond its natural length?
Answers
The amount of work required to stretch 9 inches beyond the natural length will be 4.5 ft-lb
Given data:
To determine the work required to stretch the spring 9 inches beyond its natural length, use the concept of Hooke's Law.
Hooke's Law states that the force required to stretch or compress a spring is directly proportional to the displacement from its equilibrium position.
Given that stretching the spring by 2 ft requires 12 ft-lb of work, determine the constant of proportionality.
The constant of proportionality (k) represents the stiffness of the spring and can be calculated using the formula:
k = work / displacement
k = 12 ft-lb / 2 ft
k = 6 lb/ft
Now, calculate the work required to stretch the spring 9 inches (0.75 ft) beyond its natural length using the same constant of proportionality:
work = k * displacement
work = 6 lb/ft * 0.75 ft
work = 4.5 ft-lb
Hence, it would require 4.5 ft-lb of work to stretch the spring 9 inches beyond its natural length.
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I need help to simplify
Can someone help me with this and explain me how to do it please :) ^
Answers
Answers
The number of the boxes can fit in this space if each is 10 cm long, 6 cm wide and 4 cm high will be 125,000.
What is the volume of the rectangular prism?
Let the prism with a length of L, a width of W, and a height of H.
Then the volume of the prism is given as
V = L x W x H
A moving company is trying to store boxes in a storage room with a length of 5 m, width of 3 m and height of 2 m.
Then the volume of the room (in cm) will be
V₁ = 500 x 300 x 200
V₁ = 30,000,000 cubic cm
Then the number of the boxes can fit in this space if each is 10 cm long, 6 cm wide and 4 cm high will be
The volume of each box will be
V₂ = 10 x 6 x 4
V₂ = 240 cubic cm
The number of the boxes can fit in this space if each is 10 cm long, 6 cm wide and 4 cm high will be
V₁ / V₂ = 30,000,000 / 240
V₁ / V₂ = 125,000
More about the volume of the prism link is given below.
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= 30000000 cm³
Volume of 1 box = 10 * 6 * 4
= 240 cm³
Thus, number of boxes in the room
= 30000000/ 240
= 125000 boxes ;
Thus, 125000 boxes can be stored in the room.
A. point M
B. point N
C. point O
D. point R
diagram shown below...
(((<--------M---------N---------O------P--------Q----------R--------S--------->)))
Answers
Answer:
Point R located on ray PQ.
Step-by-step explanation:
Given : Diagram
To find : Which point is located on ray PQ.
Solution : We have given <--------M---------N---------O------P--------Q----------R--------S--------->.
Ray : A part of a line with a start point but no end point (it goes to infinity).
We can see from the diagram ray PQ start from P but it has no end point.
So , point R ans S located on ray PQ but we have option R
Therefore, D. point R located on ray PQ.
Answers
Answer:
X
Step-by-step explanation:
X+y=X so the answers x
The value of x using the two rectangles is 8.
We have,
A rectangle is a 2-D shape with length and width.
The length and width are different.
If the length and width are not different then it is a square.
The area of a rectangle is given as:
Area = Length x width
Rectangle A:
Area
= length x width
= 6 x 4
=24 cm²
Rectangle B:
Area
= length x width
= 3x cm²
Now,
The area of both triangles is the same.
This means,
Area of first rectangle = Area of the second rectangle
24 = 3x
x = 24/3
x = 8
Thus,
The value of x using the two rectangles is 8.
Learn more about rectangles here:
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Answers
If the main tank at an aquarium is a cylinder getting the volume of the tank we have to follow the equation V = πr^2h. So we basically following the equation we should have V = (3.14)(101.5)2(25). We have to get the full equivalent values for each parameter so this would show as V = (3.14)(10302.25)(25) = 808726.625 or 808727 cubic feet.