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Assume you drop a rock from a cliff which is 5000 feet above the ground. The distance in feet, y, of the rock below the cliff at the time t seconds after it was dropped is given by the equationY=-1/2gt^2

Answers

Answer 1

Answer:

Answer:

Step-by-step explanation:

Given that height of cliff H = 5000 ft

You drop rock from cliff and the distance of rock below the cliff at time,t is given by:

$y= -(1)/(2) gt^(2)$

Q1. How far below the cliff is the rock 7 seconds after it dropped ?

Ans. Here, t=7 seconds

By using formula provide, g=32.18 ft{tex] $s^(-2)$

y=- \frac{1}{2} × 32.17 × (7)^{2}[/tex] = 788.165 ‬ft

Note: Negative sign shows the direction and 240.345 is magnitude

Therefore, Rock is 788.165‬ ft from Cliff

Q2. How far is the rock from the bottom 7 seconds after it dropped ?

By using formula provide,

Ans. After 7 seconds, Rock is 788.165‬ ft from Cliff

Therefore, Rock is 5000-788.165‬ = 4,211.835 ft from bottom

Q3. When will rock hit the bottom?

Ans. Height of cliff H= 5000 ft

Using formula provided, g=32.18 ft $s^(-2)$

$y = -(1)/(2) gt^(2)$

$-5000 = - (1)/(2) 32.18 × t^(2)$

$t^(2) = (5000×2)/(32.18)$

$t^(2) = 311.13876$

$t = 17.6s$

Q4. The Velocity of the rock at impact?

Ans. Velocity is given as V= g×t

By using formula, We get

V= 32.14 × Total time to reach ground

V= 32.14 × 17.6 = 565.66 ft/s

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You are relieved from your position as a machine operator at the plant at 11:25 for a 50-minute lunch break. When must you begin working again.

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Answer:

12:15

Step-by-step explanation:

Rounding (3.762) to the nearest tenths place is

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Answer:

3.8

Step-by-step explanation:

Rounding to the nearest tenth means that eliminating the digits in the hundredths and thousandths place and if the hundredths place is greater than 5, then you also have to add a 1 to the tenths place.

So, The number becomes:

=> 3.8 (Hundredths place have 6 which is greater than 5)

Answer:

3.8

Step-by-step explanation:

pls mark as brainliest

How do you do a question like this? 80% as a fraction in simplest form.

Answers

Take away 0.20 of the amount.

A person's heart rate is 65 beats per minute at rest. It increases by 12 beats per minute for each ofthe first 10 minutes of exercise. What is the person's heart rate after 6 minutes of exercise?

Answers

the heartbeat per minute is 137 i used calculator

Final answer:

The heart rate of the person after 6 minutes of exercise, assuming it increases by 12 beats per minute during this period, would be 137 beats per minute.

Explanation:

The question asks for the heart rate of a person after 6 minutes of exercise, given that it increases by 12 beats per minute during the first 10 minutes. To solve this, we start with the person's resting heart rate, which is 65 beats per minute. For each minute of exercise, we add 12 beats to the resting rate. So for 6 minute workout, the increase would be 6 times 12, which equals 72. Adding this to the resting heart rate, 65 + 72, the heart rate after 6 minutes of exercise would be 137 beats per minute.