A company’s total cost from manufacturing and selling x units of their product is given by: y = 2x2 – 600x + 49,000. How many units should be manufactured in order to minimize cost, and what is the minimum cost?a. (100, $9,000)b. (125, $3,250)c. (150, $4,000)d. (170, $4,800)e. (200, $9,000)

Answers

Answer 1
Answer:

Answer: Option 'c' is correct.

Step-by-step explanation:

Since we have given that

y=2x^2-600x+49000

We need to find the number of units in order to minimize cost.

We first derivative w.r.t. x,

y'=4x-600

For critical points:

y'=0\n\n4x-600=0\n\n4x=600\n\nx=(600)/(4)\n\nx=150

Now, we will check whether it is minimum or not.

We will find second derivative .

y''=4>0

So, it will yield minimum cost.

Minimum cost would be

y(150)=2(150)^2-600* 150+49000\n\ny(150)=\$4000

Hence, At 150 units, minimum cost = $4000

Therefore, Option 'c' is correct.


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7. Given a right triangle as shown below, use a calculator to estimate the length of themissing side to the nearest tenth of a centimeter

If x=2 find y 5x-y=5

Answers

Answer:

y=5

solution,

X=2

now,

\n 5x - y = 5 \n or \: 5 * x - y = 5 \n or \: 5 * 2 -  y = 5 \n or \: 10 - y = 5 \n or \:  - y = 5 - 10 \nor \:   - y =  - 5 \n y = 5

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Hot air balloons are able to fly at a very high altitudes a world record height of 64997 feet was set in 1988 in 2005 a new record of 68986 feet was set how many feet higher was 2005 record than the 1988 récord first draw a diagram to show the parts of the problem

Answers

Answer:

just do 68986

- 64997

______

3,989

Two cyclists, 112 miles apart, start riding toward each other at the same time. One cycles 3 times as fast as the other, and they meet after 4 hours of riding.a. Write an equation using the information as it is given above that can be solved to answer this problem. Use the variable r to represent the speed of the slower cyclist.

b. What are the speeds of the two cyclists? Put both values in the answerbox, separated with a comma, and select the appropriate units.

Answers

Answer:

Speed of a= 21 miles/hr

r = Speed of b= 7 miles/hr

Speed of a = 3r

Step-by-step explanation:

The cyclist are 112 miles apart

Time traveled by two = 4 hours

Speed of a = 3 * speed of b

If a cylcles 3 times More than b, then a will cover 3*distance of b

But speed = distance/time

Time = 4hours

Total distance=112

a = 3b

3b + b = 112

4b = 112

b = 112/4

b = 28 miles

a = 3b

a = 3*28

a = 84 Miles

They bought traveled 4 hours

Speed of a = 84miles/4 hours

Speed of a= 21 miles/hr

Speed of b = 28miles/4 hours

Speed of b = 7 miles/hr

Final answer:

The slower cyclist is traveling at a speed of 7 mph, while the faster cyclist is traveling at 21 mph.

Explanation:

We first need to recognize that the sum of the distances travelled by each cyclist is equal to the total 112 miles. We can let r represent the speed of the slower cyclist, and since the faster cyclist is traveling 3 times the speed of the slower, we can call his speed 3r.

As they each traveled for 4 hours, the slower cyclist traveled a distance of 4r miles, and the faster cyclist traveled a distance of 4 × 3r = 12r miles. Their combined distances should equal the total distance between them, 112 miles. This forms the equation 4r + 12r = 112.

To solve for r, we combine the like terms on the left side of the equation to get 16r = 112. Dividing both sides by 16, we find r = 7 miles per hour. Therefore, the slower cyclist is traveling at 7 mph, and the faster cyclist is traveling 3 times that speed, giving us 21 mph.

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Let S = {a, b, c). Find the following:a) the number of reflexive relations on S

b)the number of reflexive and symmetric relations on S

Answers

Answer:

The number of reflexive relations on S  is 64.

The number of reflexive and symmetric relations on S  is 8.

Step-by-step explanation:

Consider the provided set S = {a, b, c}.

The number of elements in the provided set is 3.

Part (a) the number of reflexive relations on S

To calculate the number of reflexive relation on S we can use the formula as shown:

Total number of Reflexive Relations on a set:2^(n(n-1)).

Where, n is the number of elements.

In the provided set we have 3 elements, so substitute the value of n in the above formula:

2^(3(3-1))

2^(3(2))

2^(6)

64

Hence, the number of reflexive relations on S  is 64.

Part(b) The number of reflexive and symmetric relations on S.

To calculate the number of reflexive and symmetric relation on S we can use the formula as shown:

Total number of Reflexive and symmetric Relations on a set:2^{(n(n-1))/(2)}.

Where, n is the number of elements.

In the provided set we have 3 elements, so substitute the value of n in the above formula:

2^{(3(3-1))/(2)}

2^{(3(2))/(2)}

2^{(6)/(2)}

2^(3)

8

Hence, the number of reflexive and symmetric relations on S  is 8.

I’m very confused pls help 50 PTSFind the quadratic function y=ax^2 +bx+c whose graph passes through the given points. (-1,-11) (2,-26) (-3,-31)

Answers

The quadratic value function is y = -x² - 4x + 16

Given data ,

Let the quadratic equation be represented as A

Now , the value of A is

Let the function passes through the given points. (-1,-11) (2,-26) (-3,-31)

And , using the point (-1,-11) , we get

-11 = a(-1)² + b(-1) + c

-11 = a - b + c

Using the point (2,-26) , we get

-26 = a(2)² + b(2) + c

-26 = 4a + 2b + c

Using the point (-3,-31) , we get

-31 = a(-3)² + b(-3) + c

-31 = 9a - 3b + c

And , the three set of equations are

-11 = a - b + c

-26 = 4a + 2b + c

-31 = 9a - 3b + c

From the first equation, we can solve for c:

c = 11 - a + b

Substituting this expression for c into the other two equations, we get:

-26 = 4a + 2b + 11 - a + b

-31 = 9a - 3b + 11 - a + b

Simplifying these equations, we get:

-15 = 3a + 3b

-21 = 8a - 2b

Solving the first equation for b in terms of a, we get:

b = -5 - a

Substituting this expression for b into the second equation, we get:

-21 = 8a - 2(-5 - a)

Simplifying and solving for a, we get:

a = -1

Substituting this value of a into the equation for b that we found earlier, we get:

b = -5 - (-1) = -4

Finally, substituting these values of a and b into the equation for c that we found earlier, we get:

c = 11 - (-1) - (-4) = 16

Hence , the quadratic function that passes through the given points is given by y = -x² - 4x + 16

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1) How do you describe Ana in the selection?​

Answers

Answer:

she develops a fair and healthy relationship with her classmate but also she elected the class president at their school

Step-by-step explanation:

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