CHEMISTRY HIGH SCHOOL

Which of the following creates a voltage difference?A. Battery
B. Amperes
C. Charge
D. Resistance

Answers

Answer 1
Answer: Battery is a result of voltage or potential difference which creates the stored energy within the cell. Amperes and resistance individually could not create the voltage difference alone, and thus need each other. Difference in charges results to difference in potentials or voltage. Hence, the answer is C.
Answer 2
Answer:

Answer:

The correct option is C

Explanation:

A battery is an electrochemical device that converts chemical energy into electrical energy. Electrochemical device contains two electrodes (anode and cathode). These two electrodes are placed in contact with an electrolyte. A spontaneous chemical reaction (redox reaction) causes electrical energy/current to be produced. This chemical reaction causes a potential difference (which produces electric current/charge). However, this charge/electric current causes a voltage difference.

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How much of a 5.0 g sample of strontium-90 will remain after 87 years?

Answers

Since radioacitive decay fallows first order kinetics you can use the equation lnA(t)=-kt+lnA₀.  
A₀=the initial amount of sample
A(t)=the amount of sample after t years
t=time
k=rate constant

First you need to solve for the rate constant (k) to get the equation
-((lnA(t)-lnA(0))/t=k which can simplify into k=-ln(A(t)/A₀)/t which can then be simplified further to ln(A₀/A(t))/t=k.   I think the half life of strontium-90 is 28.8 years which means that when t=28.8 years, A(t) is going to equal 1/2 of A₀ and you can make the equation k=ln2/28.8 to get k=0.02408.

Now you need to solve for A(t) in the equation ln(A(t))=-kt+lnA₀ to get A(t)=e^(-kt+lnA₀) which simplifies to A(t)=A₀e^-kt.  When you plug t=87, A₀=5g, and k=0.02408 into that equation you should get 0.616g.

Therefore after 87 years you will have 0.616g of strontium-90 if you started with a 5g sample.

I hope this helps.  Let me know in the comments if anything is unclear.

If 3.0g of H20 actually forms what is the percentage yield

Answers

Percent yield is expressed as the ratio of the actual yield and the theoretical yield of the reaction multiplied by 100 to get the percent value. The actual yield is usually given in a problem. The theoretical yield is calculated from the reaction. For this problem, it cannot be solved since we cannot obtain the theoretical yield.

A maritime polar air mass is a cold air mass that forms over which two oceans

Answers

Answer:

The correct answer is Pacific and Atlantic oceans.

Explanation:

When an air body of a specific site or region reflects the temperature and other climatic condition of water and land it is known as air mass. The air substitutes heat with the water or the land, till the temperature of the air becomes equivalent to that of the surface underneath it. A maritime polar air mass refers to the air mass, which gets produced over the Northern Pacific oceans and the Northern Atlantic oceans. This is accountable for bringing a mass of cold air into the mentioned oceans.
northern atlantic and northern pacific oceans

Write balanced complete ionic equation for AgNO3(aq)+NaCl(aq)→AgCl(s)+NaNO3(aq)

Answers

AgNO3(aq)+NaCl(aq)→AgCl(s)+NaNO3(aq)
the coefficients are 1 because the equation is balanced already

What is the concentration of O2(g), in parts per million, in a solution that contains 0.008 gram of O2(g) dissolved in 1000. grams of H2O(l)?

Answers

concentration of O₂ dissolved in H₂O can be written as ppm

ppm stands for parts per million - mg/kg

the amount of mg in 1 kg of solution

the mass of O₂ - 0.008 g

1000 mg equivalent to 1 g

therefore mass of O₂ in mg - 0.008 g x 1000 mg/g = 8 mg

the mass of water is 1000 g

1000 g is equivalent to 1 kg

mass of water in kg - 1000 g / 1000 g/kg = 1 kg

there's 8 mg of O₂ in 1 kg of water

therefore concentration of O₂ is - 8 mg/kg

also can be written as 8 ppm

answer is 8 ppm

Answer : The concentration of O2(g) in parts per million is, 8 ppm

Solution : Given,

Mass of oxygen gas (solute) = 0.008 g

Mass of water (solvent) = 1000 g

First we have to calculate the mass of solution.

Mass of solution = Mass of solute + Mass of solvent = 0.008 + 1000 = 1000.008 g

Now we have to calculate the concentration of O2(g) in parts per million.

ppm : It is defined as the mass of solute present in one million (10^6) parts by mass of the solution.

ppm=\frac{\text{Mass of solute}}{\text{Mass of solution}}* 10^6

Now put all the given values in this expression, we get

ppm=(0.008g)/(1000.008g)* 10^6=7.99=8ppm

Therefore, the concentration of O2(g) in parts per million is, 8 ppm

7. Methane, CH, burns in oxygen gas to form water and carbon dioxide. Wequation for this reaction?a. CH4+ O H2O CO2b. CH4+ 40 2H20+ CO2c. CH4 O2 H2O CO2d. CH4+ 202 2H20 CO28. How many atoms are present in 3 moles of chromium?c. 1.80 x 1024 atomsa. 6.02 x 1023 atomsb. 1.80 x 1023 atomsd. 52.00 atoms
9. How many grams of CO2 are in 2.1 mol of the compound?a. 21.0 gc. 66.0 gb. 44.0 gd. 92.4 g

Answers

7) the answer is D.  You need to know that oxygen gas is O₂ which means that A and B can't be right.  Then you need to see which one is balanced and since D is and C is not, the correct answer has to be D.

8)  You need to know that 1 mole of anything contains 6.02×10²³ particles.  therefore you multiply 6.02×10²³ by 3 to get 1.806×10²⁴ atoms.

9) You need to multiply the number of moles of carbon dioxide by the molar mass of carbon dioxide (44g/mol).  2.1mol×44g/mol=92.4g.  Therefore the answer is 92.4g of CO₂.

I hope this helps.  Let me know if anything is unclear.
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