The polynomial 10x3 + 35x2 − 4x − 14 is factored by grouping.10x3 + 35x2 − 4x − 14

5x2(____) − 2(____)

What is the common factor that is missing from both sets of parentheses?

−2x − 7
2x + 7
−2x2 + 7
2x2 + 7

Answers

Answer 1
Answer: If you would like to find the factor that is missing from both sets of parentheses, you can calculate this using the following step:

10x^3 + 35x^2 - 4x - 14 = 5x^2 * (2x + 7) - 2 * (2x + 7)

The correct result would be 2x + 7.
Answer 2
Answer:

The common factor that is missing from both sets of parentheses is 2x + 7

How to determine the missing factor

To determine the missing factor, we would divide 10x³ + 35x² − 4x− 14 by 5x² – 2 using long division method as illustrated below

           2x + 7        

5x² – 2|10x³ + 35x² − 4x − 14

           –(10x³ – 4x)

            35x² – 14

          –(35x² – 14)

                   0

The result obtained from the division is 2x + 7.

Therefore, the missing factor is 2x + 7

Check

(5x² – 2)(2x + 7) = 5x²(2x + 7) – 2(2x + 7)

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If an area in the form of a circle is to be roped off by a rope 10 m long, what will be the radius of this area? Round your answer to two decimal places. A. 1.59 m
B. 2.56 m
C. 3.18 m
D. 0.31 m

Answers

Answer:

A. 1.59 m

Step-by-step explanation:

To find the radius of the area we wil; simply use the formula; C = 2π R

where C is the circumference of the circle,  π is a constant that is always 3.14 approximately, except given otherwise   and R is the radius.

From the question, since the circle is formed by roping  off  a rope 10 m long, then it implies that the circumference (c) = 10

We can now proceed to substitute our values into the formula;

C  = 2π R

10 ≈ 2×3.14×R

10 ≈ 6.28R

Divide both-side of the equation by 6.28

(10)/(6.28) = (6.28 R)/(6.28)

(At the right-hand side of the equation 6.28 will cancel-out 6.28 leaving us with just R while at the left-hand side of the equation, 10 will be divided by 6.28)

1.592≈R

R≈1.59 m

Therefore, the radius of this area will be 1.59 m

Your answer is A. 1.59 m.

Hope this helps.

Suppose the auction house from the preceding problem sold 200 tickets at $1 each, and had 16 prizes of $10 each. What is the new expected value?A) $0
B) $0.2
C) –$0.2
D) $0.8

Answers

The new expected value is $0.8 if the auction house sold 200 tickets at $1 and had 16 prizes of $10 each.

What is expected value?

It is value which is calculated in the present but expect to come in future also.

How to calculate the expected value?

The expectedvalue will be calculated as under:

Value on 16 prizes=200/160=1.25

Expected value will be =(200+160)/1.25/160

=200.8

So the value expected will be $0.8.

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200/160=1.25

200+160=360/1.25/160=200.8

so your answer is 0.8

Would you please help me to solve this 9.1x10^-5)^-4

Answers

[( 91 * 10^-1 ) *10^ -5]^-4 = (91 * 10^-6)^-4 = 91^-4 * 10^24 = ( 10^24 )/ ( 91^4 ) =
10000000 ≈ 1458258211769

Mike and Kate plan to save money for their wedding over a 20 month period. They will need to save $8,000 to help pay for the wedding. They set aside the same amount each month. After a year they saved $4,000. Mike and Kate know they must adjust their plan in order to meet their goal, so they came up with the following options:Option A: Stay with saving the same amount they've been saving each month but postpone the wedding 2 months.
Option B: Increase the amount of money they save each month by $80 from what they've been saving.
Which of the following is a true statement?
a.
Only option A will allow them to meet their goal.
b.
Only option B will allow them to meet their goal.
c.
Both options A and B will allow them to meet their goal.
d.
Neither option A nor option B will allow them to meet their goal.



Please select the best answer from the choices provided


A
B
C
D

Answers

D is the correct answer. Mike and Kate require $8000 for their wedding and have saved $4000 already, so they need a further $4000. They have saved the money over 12 months, which means they have been saving $333.33 every month (4000/12). In Option A they have 10 months to save money - the original 8 months, plus the 2 months the wedding is postponed. This will give them the chance to save $3333.33 (333.33 x 10). In Option B, they can increase their monthly savings by $80, giving them total monthly savings of $413.33 (333.33 + 80). In the remaining 8 months before the wedding, they will be able to save $3306.66 (413.33 x 8). However, neither of these options give them the $4000 required to make their $8000 budget.

Answer:

d

Step-by-step explanation:

Rachel invested $15,000 in a nine-year CD giving 8.5% interest, but needed to withdraw $4,000 after two years. If the CD's penalty for withdrawal was six months' worth of interest on the amount withdrawn, how much money did Rachel have when the CD reached maturity, not including the amount she withdrew? Round answer to the nearest whole dollar

Answers

Given:
principal 15,000
term 9 years
rate 8.5%

Interest = Principal * Interest Rate * Term
I = 15,000 * 8.5% * 9
I = 11,475

Total = 15,000 + 11,475 = 26,475 on date of maturity

Interest = 15,000 * 8.5% * 2
I = 2,550

Total = 15,000 + 2,550 = 17,550

amount withdrawn = 4,000 

Penalty = 4,000 * 8.5 % * 6/12
P = 170

Net amount = 17,550 - 4,000 - 170 = 13,380

I = 13,380 * 8.5% * (8-2)
I = 6,823.80

Total = 13,380 + 6,823.80 = 20,203.80 total amount on maturity.

Identify the expression equivalent to 4(x + x + 7) − 2x + 8 − 4 by substituting x = 1 and x = 2.

Answers

4(x+x+7)-2x+8-4 X=1
4(1+1+7) -2(1) +8-4
4(9)+2
38

4(x+x+7)-2x+8-4  X=2
4(2+2+7) -2(2)+4
4(11)-4+4
44

Answer:

44

Step-by-step explanation:

So if we do 4(x+x+7)-2x+8-4 X=1

then 4(1+1+7) -2(1) +8-4

and 4(9)+2

it would be 38

then if we do 4(x+x+7)-2x+8-4  X=2

and 4(2+2+7) -2(2)+4

also 4(11)-4+4 it would be 44