Brenda earns $1,700 per month after taxes. She is working on her budget and has the first three categories finished. Housing $612
Food $238
Transportation $370

What is the problem with this budget?

Select the best answer from the choices provided.

She is budgeting too much for transportation.

She has used the highest recommended percentages for the three categories.

She has allotted more than 36% of her income for housing.

She is budgeting too little for transportation.

Answers

Answer 1

Answer: Brenda earns $1,700 per month after taxes. She is working on her budget and has the first three categories finished.Housing $612
Food $238
Transportation $370
What is the problem with this budget?
The answer is => She has allotted more than 36% of her income for housing

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Consider the functions f(x) = x2 − 13 and g(x) = x + 5. What is the value of (f − g)(−4)? ...?

Answers

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

f(x) = x2 - 13
g(x) = x + 5

and are asked to compute "f-g" when x=-4. there are two ways of doing this. you can either first find f(-4) and g(-4) and then substract one from other like so:

f(−4)=(−4)2−13=16−13=3
g(−4)=−4+5=1

f(−4)−g(−4)=3−1=2

or you can create a new function that represents "f-g", call it "h", and work out h(-4) as follows:

h(x)=f(x)−g(x)=(x2−13)−(x+5)=x2−13−x−5=x2−x−18
h(−4)=(−4)2−(−4)−18=16+4−18=2

Answer- The Answer is -12

Step-by-step explanation:

I took the test

Please help me as soon as possible ...

Answers

Answer: see proof below

Step-by-step explanation:

Use the following identities

tan (A + B) = (tan A + tan B)/(1 - tan A · tan B) --> $(tanA+tanB)/(1-tanA\cdot tanB)$

tan 60° = √3

tan 120° = -√3

tan 3A = (3tanA - tan³A)/(1 - 3 tan²A) --> $(3tanA-tan^3A)/(1-3tan^2A)$

Proof LHS → RHS

Given: tan Ф + tan(60° + Ф) + tan(120° + Ф)

Sum Difference: tan Ф + (tan 60° + tanФ)/(1-tan60°·tanФ) + (tan 120° + tanФ)/(1-tan120°·tanФ)

(latex) $tan\theta+(tan60^o+tan\theta)/(1-tan60^o\cdot tan\theta)+(tan120^o+tan\theta)/(1-tan120^o\cdot tan\theta)$

Substitute: tan Ф + (√3 + tanФ)/(1-√3·tanФ) + (-√3 + tanФ)/(1+√3°·tanФ)

(latex) $tan\theta+(\sqrt3+tan\theta)/(1-\sqrt3 tan\theta)+(-\sqrt3+tan\theta)/(1+\sqrt3tan\theta)$

Common Denominator: [tan Ф(1-3tan²Ф)+8tanФ]\(1-3tan²Ф)

(latex) $(tan\theta(1-3tan^2\theta)+8\theta)/(1-3tan^2\theta)$

Distribute: (tan Ф - 3tan³Ф + 8Ф)\(1 - 3 tan²Ф)

(latex) $(tan\theta-3tan^3\theta+8\theta)/(1-3tan^2\theta)$

Simplify: (9Ф - 3tan³Ф)\(1 - 3 tan²Ф)

3(3Ф - tan³Ф)\(1 - 3 tan²Ф)

(latex) $(9\theta - 3tan^3\theta)/(1-3tan^2\theta)$

$(3(3\theta - tan^3\theta))/(1-3tan^2\theta)$

Triple Angle Identity: 3 tan 3Ф

3 tan 3Ф = 3 tan 3Ф $\checkmark$

Your question has been heard loud and clear.

tanθ+tan(60∘+θ)+tan(120∘+θ)

=tanθ+3–√+tanθ1−3–√tanθ+−3–√+tanθ1+3–√tanθ

[tanθ(1−3tan2θ)+(3–√+tanθ)(1+3–√tanθ)

=+(−3–√+tanθ)(1−3–√tanθ)1−3tan2θ

=9tanθ−3tan3θ1−3tan2θ=3tan3θ

Thank you.

How to solve this step by step

Answers

yo has to factor since we assume that
if you have xy=0, x and y=0

7n^2-48n+36=0
trial and error
(7n-6)(n-6)=0

set each to zero
7n-6=0
add 6
7n=6
divide 7
n=6/7

n-6=0
add 6
n=6

n=6/7 or 6

Write the expression in factored form

Answers

$2.)\n \n n^2 - 9n +14 = 0 \n \n a=1 , \ b = -9, \ c = 14 \n \n\Delta =b^2-4ac = (-9)^2 -4\cdot1\cdot 14 = 81 -56 = 25 \n \nn_(1)=(-b-√(\Delta) )/(2a)=(9-√(25))/(2 )=( 9-5)/(2)=(4)/(2)= 2$

$n_(2)=(-b+√(\Delta) )/(2a)=(9+√(25))/(2 )=( 9+5)/(2)=(14)/(2)= 7 \n \n Answer : \ n^2 - 9n +14 =(n-2)(n-7)$

$3.)\n \n n^2 + 4n - 12 =0 \n \n a=1 , \ b = 4, \ c = -12 \n \n\Delta =b^2-4ac = 4^2 -4\cdot1\cdot (-12) = 16+48=64 \n \nn_(1)=(-b-√(\Delta) )/(2a)=(-4-√(64))/(2 )=( -4-8)/(2)=(-12)/(2)= -6$

$n_(2)=(-b+√(\Delta) )/(2a)= (-4+√(64))/(2 )=( -4+8)/(2)=(4)/(2)=2\n \n Answer : \ n^2 +4n -12 =(n+6)(n-2)$

second way :

$2.)\n \n n^2 - 9n +14 = n^2 - 9n+2n -2n +14 = n^2 - 7x -2n +14 =\n \n = n(n-7)-2(n-7)=(n-7)(n- 2)\n \n \n Answer : \ n^2 - 9n +14 =(n-2)(n-7)$

$3.)\n \n n^2 + 4n - 12 = n^2 + 4n +2n - 2n - 12 = n^2 + 6n - 2n - 12 =\n \n = n(n+6) -2(n+6)=(n+6)(n-2) \n \n \n Answer : \ n^2 +4n -12 =(n+6)(n-2)$

n^2-9n +14
n^2-7n-2n+14
n(n-7) -2(n-7)
(n-2)(n-7)

10 x 4 ones = how many ones

Answers

The product will be 40 I believe?

The Venus flytrap closes in 0.3 second and the waterwheel plant closes in 0.2 second what decimal in halfway between 0.2 and 0.3 ?

Answers

In order to find the number in between two numbers you need to calculate their mean. This can be done by adding them up then dividing by 2. In this case, 0.2+0.3 = 0.5. You can then divide this by 2 to give 0.25
Thus the decimal in between 0.2 and 0.3 is 0.25.

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