MATHEMATICS MIDDLE SCHOOL

16. FINANCIAL LITERACY A specific car's fuel economy in miles per gallon can beapproximated by f(x) = 0.00000056x4 - 0.000018x3 - 0.016x2 + 1.38x - 0.38,

where x represents the car's speed in miles per hour. Determine the fuel economy

when the car is traveling 40, 50, and 60 miles per hour.

Answers

Answer 1
Answer:

Answer:

a) 29.50 miles per gallon    b) 29.87 miles per gallon     c) 28.19 miles per gallon

Step-by-step explanation:

A specific car fuel economy (miles/gallon) = f(x) = 0.00000056x^4 - 0.000018x^3 - 0.016x^2 + 1.38x - 0.38

where x represents the car speed in miles per hour.

when x = 40 miles per hour

A specific car fuel economy (miles/gallon) = f(x) = 0.00000056(40)^4 - 0.000018(40)^3 - 0.016(40)^2 + 1.38(40) - 0.38 = 1.4336 - 1.152 - 25.6 + 55.2 - 0.38 = 29.50 miles per gallon

Similarly,

when x = 50

A specific car fuel economy (miles/gallon) = f(x) = 0.00000056(50)^4 - 0.000018(50)^3 - 0.016(50)^2 + 1.38(50) - 0.38 = 3.5 - 2.25 - 40 + 69 - 0.38 = 29.87 miles per gallon

Similarly,

when x = 60

A specific car fuel economy (miles/gallon) = f(x) = 0.00000056(60)^4 - 0.000018(60)^3 - 0.016(60)^2 + 1.38(60) - 0.38 = 7.26 - 3.89 - 57.6 + 82.8 - 0.38 = 28.19 miles per gallon

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