How many grams of calcium phosphate can be produced when 89.3 grams of calcium chloride reacts with excess sodium phosphate? Unbalanced equation: CaCl2 + Na3PO4 → NaCl + Ca3(PO4)2

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Answer 1
Answer:

 The grams  of calcium phosphate  that can be  produced when  89.3  grams  of calcium chloride  reacted  with   excess  sodium phosphate is

     83.08  grams  of calcium phosphate

   calculation

Step 1: write a balanced chemical equation

3CaCl₂  + 2Na₃Po₄ →6NaCl + Ca₃(PO₄)₂

step 2: find the moles of CaCl₂

moles  = mass÷  molar mass

from periodic table the molar mass  of CaCl₂ = 40 +( 2 x 35.5) =111 g/mol

moles = 89.3 g÷111 g/mol = 0.805  moles

Step 3: use the  mole ratio to determine the moles of Ca₃(PO₄)₂

CaCl₂: Ca₃(PO₄)₂  is  3:1 therefore the  moles of Ca₃(PO₄)₂ =0.805  x 1/3 =0.268  moles

Step 4: find mass  of Ca₃(PO₄)₂

mass = moles x  molar mass

from periodic table the molar mass of Ca₃(PO₄)₂ = (40 x3) +[ 31 +(16 x4)]2 =310 g/mol

mass is therefore =0.268  moles x 310 g/mol =83.08 grams



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The latent heat of vaporization of ethanol is 200 calories/gram. This means that _____. about 200 calories of heat must be added to 1 gram of ethanol to change its temperature about 200 calories of heat must be added to 1 gram of ethanol to convert it from a solid to a liquid about 200 calories of heat must be added to 1 gram of ethanol to convert it from a liquid to a gas

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I hope this helps.  Let me know if anything is unclear.

Answer:

about 200 calories of heat must be added to 1 gram of ethanol to convert it from a liquid to a gas

Explanation:

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Answer:

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Explanation:

Have a great day!

It has been determined that the body can generate 5500 kJ of energy during one hour of strenuous exercise. Perspiration is the body’s mechanism for eliminating this heat. What mass of water would have to be evaporated through perspiration to rid the body of the heat generated during 2 hours of exercise? (The heat of vaporization of water is 40.6 kJ/mol.)

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Answer:

4.88 kg

Explanation:

Amount of energy generated in 1 hour of exercise = 5500 kJ

Thus,

Amount of energy generated in 2 hours of exercise = 5500*2 kJ

So,

Amount of energy generated in 2 hours of exercise = 11000 kJ

Heat of vaporization of water = 40.6 kJ/mol

40.6 kJ of energy is required to vaporize 1 mole of water

Also,

11000 kJ of energy is required to vaporize (1/40.6) * 11000 mole of water

Moles of water = 270.936 moles

Molar mass of water = 18 g/mol

Mass = Moles * Molar mass = 270.936 * 18 g = 4876.8473 g

Also,

1 g = 0.001 kg

So, mass of water = 4.88 kg

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