MATHEMATICS MIDDLE SCHOOL

2 PointsIn A Raisin in the Sun, what does Mama want to have someday?
O
A. Her own house
O
B. A grandchild
O C. Her own business
O
D. A college education

Answers

Answer 1

Answer:

Answer:

The Answer is her own house

Step-by-step explanation:

I guessed and it was correct

Answer 2

Answer:

Final answer:

In A Raisin in the Sun, Mama, also known as Lena Younger, dreams of having 'A. Her own house' someday to provide a better life and future for her family.

Explanation:

In the play A Raisin in the Sunby Lorraine Hansberry, Mama, also known as Lena Younger, has a dream of owning her own house someday. Her character places great importance on having a physical space from which the family can grow and prosper. Her longing for a home is born out of her desire to improve her family's living conditions and to provide a better future for them. So, the correct answer is A. Her own house.

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A teacher surveyed his class about how many wore watches and how many wore rings. The Venn diagram shows her results. If a person from the class is randomly selected, what is the probability that person wears a watch given that they wear a ring? P( watch | ring )

A. 7/12
B. 1/6
C. 1/12
D. 2/7
URGENT PLEASE HELP

Answers

I think it’s C I hope that helps

Answer:

Step-by-step explanation:

Person who wears a watch + ring

Lets say the fraction of people wearing the rings is 1/X

Lets say the fraction of people wearing a watch is 2/y

The formula is multiplication for both (Key words: and)

The formula is add for one or the either (key words: or)

The question says that person wears a watch given that they wear a ring

It mean that they wear a watch + a ring.

THat mean multiplication!

Lets use the example: 1/x · 2/y = 2/xy

This makes 2/xy your answer for the example.

Now lets do another example:

Lets say the fraction of people wearing the rings is 1/3

Lets say the fraction of people wearing a watch is 2/3

Multiplication!!!!

1/3 x 2/3 = 2/9

This makes 2/9 your answer to this example!!!!

Hope I helped a lot!!!!!!!!!!!!!!!!!!

Express 30 minutes per day as a ratio in simplest form.

Answers

1 Day= 24 hours
= 24 ×60 minutes
= 1440
30:1440
=1:48

I believe it's 30:365 or you can write it as 30/365 as a fraction or just 30 to 365 .

How do you solve for L?

L=5B
L+7=3(B+7)

Answers

remember
a(b+c)=ab+ac
and you can do ANYTTHING to be
L=5B
divide both sides by 5
L/5=B
sub L/5 for B in other equation
L+7=3((L/5)+7)
distribute
L+7=(3L)/5+21
minus 7 both sides
L=(3L)/5+14
time boths sides by 5
5L=3L+70
minus 3L both sides
2L=70
divide 2
L=35

You first plug in 5B for L in the 2nd equation and you get 5B+7=3B+21 (distributive property). Then you simplify and you get B = 7. Then you plug 7 back in the first equation and get L = 35.

What is 2t ^ 3 + 6t ^ 2 - 80t in completely factored form ?

Answers

Answer:

The completely factored from

Step-by-step explanation:

is 20

How many thousands are in 600 tens?

Answers

The number of thousands in 600 tens is A = 6 thousands

What is rounding up numbers?

There are basically two rules while rounding up numbers

If the number you are rounding is followed by 0, 1, 2, 3, or 4, round the number down and if the number you are rounding is followed by 5, 6, 7, 8, or 9, round the number up.

Non-zero digits are always significant

Zeros between non-zero digits are always significant

Leading zeros are never significant

Trailing zeros are only significant if the number contains a decimal point

Given data ,

Let the number be represented as A

Now , the value of A = 600 tens

There are 60 tens in 600 because 10 x 60 = 600.

To convert from tens to thousands, we need to divide by 100, since there are 100 tens in one thousand.

On rounding , we get

So to find out how many thousands are in 600 tens, we can divide 600 by 100:

600 / 100 = 6

Hence , there are 6 thousands in 600 tens

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600*10=6000

there are 6 thousands in 600 tens

Identify the sequence of transformations that will reflect a figure over the x−axis and then dilate it by a scale factor of 3.A (x, y) --------> (x, −y); (x, y)--------> (3x, 3y)
B (x, y)---------> (x, −y); (x, y)--------> (3x, y)
C (x, y---------->)(−x, y); (x, y)-------->(3x, 3y)
D (x, y)---------->(−x, y); (x, y)-------->(x, 3y)