PHYSICS MIDDLE SCHOOL

An airplane is moving at 350 km/hr. If a bomb isdropped from the airplane at 1.5 km, (a) with what
velocity does the bomb strike the earth? (b) How
long does it take the bomb to fall? (c) What is the
bomb's range?

Answers

Answer 1
Answer:

Answers:

a) -171.402 m/s

b) 17.49 s

c) 1700.99 m

Explanation:

We can solve this problem with the following equations:

y=y_(o)+V_(oy)t-(1)/(2)gt^(2)(1)

x=V_(ox)t(2)

V_(f)=V_(oy)-gt(3)

Where:

y=0 m is the bomb's final jeight

y_(o)=1.5 km (1000 m)/(1 km)=1500 m is the bomb'e initial height

V_(oy)=0 m/s is the bomb's initial vertical velocity, since the airplane was moving horizontally

t is the time

g=9.8 m/s^(2) is the acceleration due gravity

x is the bomb's range

V_(ox)=350 (km)/(h) (1000 m)/(1 km) (1 h)/(3600 s)=97.22 m/s is the bomb's initial horizontal velocity

V_(f) is the bomb's fina velocity

Knowing this, let's begin with the answers:

b) Time

With the conditions given above, equation (1) is now written as:

y_(o)=(1)/(2)gt^(2)(4)

Isolatingt:

t=\sqrt{(2 y_(o))/(g)}(5)

t=\sqrt{(2 (1500 m))/(9.8 m/s^(2))}(6)

t=17.49 s(7)

a) Final velocity

Since V_(oy)=0 m/s, equation (3) is written as:

V_(f)=-gt(8)

V_(f)=-(97.22)(17.49 s)(9)

V_(f)=-171.402 m/s(10) The negative sign ony indicates the direction is downwards

c) Range

Substituting (7) in (2):

x=(97.22 m/s)(17.49 s)(11)

x=1700.99 m(12)
Answer 2
Answer:

Final answer:

The bomb hits the earth at approximately 540.3 km/hr, it takes approximately 17.5 seconds for the bomb to hit the ground, and the bomb's range is approximately 1.36km.

Explanation:

To answer these questions, we're going to use the principles of kinematics that involve motion in a straight line with constant acceleration (that is the acceleration due to gravity in this case). (a) The velocity of the bomb when it strikes the earth can be calculated using the kinematic equation v = u + gt, where u is the initial velocity (0 m/s since the bomb was dropped, not thrown), g is the acceleration due to gravity (approximately -9.8 m/s²), and t is the time. However, we do not know the time yet, so we will use the equation v = sqrt(2×g×h), where h is the height (1500m), and this gives us approximately 540.3 km/hr. (b) The time it takes for the bomb to fall can be calculated using t = sqrt((2×h)/g) which gives approximately 17.5 seconds. (c) The range of the bomb is the horizontal distance it travels, which is the velocity of the plane multiplied by the time it takes for the bomb to hit the ground, or 350 km/hr × 17.5/3600 hr = approximately 1.36km.

Learn more about Kinematics here:

brainly.com/question/7590442

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Answers

Answer:

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Explanation:

The specific heat capacity of a substance is defined as the amount of energy needed to raise the temperature of 1 kg of a substance by 1^(\circ)C.

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Answers

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Answers

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Answers

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