MATHEMATICS HIGH SCHOOL

If s(x) = x – 7 and t(x) = 4x2 – x + 3, which expression is equivalent to (t*s)(x)?4(x – 7)2 – x – 7 + 3

4(x – 7)2 – (x – 7) + 3

(4x2 – x + 3) – 7

(4x2 – x + 3)(x – 7)

Answers

Answer 1
Answer: The correct answer is 4(x-7)²-(x-7)+3.

Explanation:
When we find (t*s)(x), that is the same as t(s(x)). To evaluate this, we take the value of s(x), x-7, and substitute it in for every x in t(x). Instead of 4x², we have 4(x-7)²; instead of -x, we have -(x-7). This gives us 4(x-7)²-(x-7)+3.
Answer 2
Answer:

Answer:

(4x^2-x+3)(x-7)<strong>

D is the correct option.

Step-by-step explanation:

We have been given that

s(x)=x-7\text{ and }t(x)=4x^2-x+3

We have to find (t\cdot x)

which means we have to find the product of these two expressions.

We can rewrite (t\cdot x) as t(x)s(x)

Therefore, we have

(t\cdot x)\n\n=t(x)s(x)=(4x^2-x+3)(x-7)

Hence, the equivalent expression is

(4x^2-x+3)(x-7)

D is the correct option.

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Answers

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If h(x) = 6 – x, what is the value of (h h) (10)

–4
–2
10
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Answers