CHEMISTRY MIDDLE SCHOOL

A gas is 90.82L at 29.8 atm and 99.9°C. What volume would the gas be at standard temperature and pressure.

Answers

Answer 1
Answer:

Answer:

1981.38L

Explanation:

P=29.8atm;

T=273+99.9=372.9⁰K

V=90.82L

P₀=1atm

T₀=273⁰K

V₀-?

PV/T=P₀V₀/T₀

V₀=PVT₀/P₀T=

= (29.8 * 90.82 * 273)/(1 * 372.9) = 1981.38l

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Hope this helps. :)

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All of these technologies are very similar to each other... this was a good question

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