Probability theory predicts that there is a 16.2% chance of a particular basketball player making 5 free throws in a row. If the basketball player taking 5 free throws is simulated 5000 times, in about how many of the simulations would you expect at least 1 missed free throw?

Answers

Answer 1

Answer: There is a 83.8% chance that the player will have at least 1 missed free throw.
5000 · 0.838 = 4190 simulations

Answer 2

Answer:

Answer:

4190

Step-by-step explanation:

Given that,

Probability theory predicts that there is a 16.2% chance of a particular basketball player making 5 free throws in a row.

Let us assume that, A be the event that, 5 free throws happen. So

$P(A)=0.162$

So the probability of the event of not happening the event A or event of missing at least 1 free throw will be,

$P(A^c)=1-0.162=0.838$

So, in 5000 trial, number of missed free throw will be,

$=0.838* 5000=4190$

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Answers

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Answers

An 1 1/2 minus 1/4 is equal to 1 1/4 or 1.25 as a decimal.

To subtract fractions, they must have a common denominator the common denominator is 4. Let's find the equivalent fractions with a denominator of 4:

1 1/2 is the same as 1 + 1/2, and convert 1/2 to have a denominator of 4:

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Now, subtract 1/4:

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To know more about decimal here

brainly.com/question/33109985

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1 1/2 - 1/4
You have to have a common denominator which is 4 in this istance.
That makes it 1 2/4 - 1/4. That equals 1 3/4.

Hope that this helped! :)

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Answers

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