What does the law of cosines reduce to when dealing with a right triangle

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Answer 1
Answer:

Answer:

Pythagoras Theorem

Step-by-step explanation:

For any triangle ABC, the law of cosine is given by

c^2=a^2+b^2-2ab\cos C

Now, let us suppose the triangle ABC is a right triangle having right angle at C.

Thus, C = 90°

Substituting this value in above formula

c^2=a^2+b^2-2ab\cos 90

We know that cos 90°= 0

Thus, the equation becomes

c^2=a^2+b^2-2ab\cdot0\n\nc^2=a^2+b^2

We can see that it reduces to Pythagoras Theorem.

Hence, we can conclude that law of cosines reduce to Pythagoras Theorem when dealing with a right triangle


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Answers

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Step-by-step explanation:

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Find the value of the angle and stating the angle pair

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