PHYSICS HIGH SCHOOL

You put the wet leaves in the container and turn the crank to spin off the water. The radius of the container is 13.2 cm. When the cylinder is rotating at 1.63 revolutions per second, what is the magnitude of the centripetal acceleration at the outer wall?

Answers

Answer 1

Answer:

Answer:

centripetal acceleration $(a_(c))=13.8m/s^(2)$

Explanation:

convert 1.63rev/sec to rpm by multiplying by 60

= 1.63*60=97.8rpm

Convert this to rad/sec

1rpm =π/30 rad/sec

97.8rpm = 97.8 * (π/30 rad/sec)

=10.25rad/sec

linear velocity= angular velocity *radius

radius =13.2cm=13.2/100=0.132m

v=rω

v= 0.132*10.25

v=1.35m/s

centripetal acceleration = $(v^(2) )/(r)$

$a_(c)=(1.35^(2) )/(0.132)$

$a_(c)=13.8m/s^(2)$

Answer 2

Answer:

Answer:

$a_(c)$ = 13.8 m/s².

Explanation:

The acceleration centripetal $a_(c)$ is given by:

$a_(c) = (v^(2))/(r)$ (1)

where v: is the tangential speed and r: is the container radius

The tangential speed is equal to:

$v = \omega \cdot r$ (2)

where ω: is the angular velocity

Since 1 revolution is equal to 2π rad, the velocity (equation 2) is:

$v = 1.63 (rev)/(s) \cdot (2\pi rad)/(1rev) \cdot 0.132m = 1.35m/s$

Now, by entering the velocity value calculated into equation (1) we can find the acceleration centripetal:

$a_(c) = ((1.35m/s)^(2))/(0.132m) = 13.8m/s^(2)$

I hope it helps you!

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C. with smaller amplitudes than the molecules in a longitudinal wave.
D. in the direction in which the wave travels

Answers

So we wan't to know how the molecules of the medium vibrate when a transverse wave propagates trough that medium. A transverse wave is a wave whos oscilations are perpendicular to the direction of it's propagation. So the molecules in a medium will vibrate perpendicular to the direction of propagation of the wave. So if the wave is moving in the x-direction, the molecules will vibrate in the y-z plane. The correct answer is A. at right angles to the direction in which the wave propagates.

Ask a questioWhat are powers called that the framers of the Constitution felt existed and were expected to be held by the national government due to historical precedence and common practice?a. expressed
b. implied
c. intended
d. inherent n here.

Answers

The powers that the framers of the Constitution felt existed and were expected to be held by the national government due to historical precedence and common practice were called D) inherent.

Why gravitational force at the center og earth is zero

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F = G Mm/r²
mg = G Mm/r²
g = GM/r²
At centre of earth, r=0
g = GM/0
g =0

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Why value of 'g' is zero at center of Earth?

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When we move towards centre of earth, the mass is equally distributed in all directions.

The mass beneath you = Mass in front of you = Mass behind you

Thus, all the gravitational forces applied cancel each other and acceleration due to gravity (g) at centre of earth on centre of earth becomes zero (0).

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The general equation of acceleration due to gravity is;-

g = $(GM)/(r^2)$

Assuming earth to be a perfect sphere and considering its uniform density.

We make the following adjustments in the following equation.

g = $(GM)/(r^2)$

Multiplying and dividing RHS by volume 'V'.

g = $(GM)/(V) × V × (1)/(r^2)$

We know that;-

$(M)/(V)$ = Density, ρ

Therefore,

g = $(ρGV)/(r^2)$

For sphere;-

V = $(4)/(3)$ π $r^(3)$

This makes

g = $(4)/(3)$ π $r^(3)$ × $(ρG)/(r^2)$

g = $(4πρG)/(3)$

So, at center of Earth

since, r = 0

so, g = 0.

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Resolve the following two forces into horizontal and vertical components.

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All components of both forces have zero magnitudes.

A ping pong ball rolls off a 5.Om high table and lands on the floor, 3.0maway from the table. How long is the ball in the air?

Answers

Answer:

The ball was 1.01 seconds in the air

Explanation:

Horizontal Motion

When an object is thrown horizontally with a speed v from a height h, the range or maximum horizontal distance traveled by the object can be calculated as follows:

$\displaystyle d=v\cdot\sqrt{\frac {2h}{g}}$

If we know the value of d and h, we can solve the equation for v:

$\displaystyle v=d\cdot\sqrt{\frac {g}{2h}}$

Since the horizontal speed is constant, we can calculate the time the ball was in the air by using the equation:

$\displaystyle t=(d)/(v)$

The ping pong ball rolls from a height of h=5 m and lands on the floor a distance of d= 3 m away from the table. Calculate the speed:

$\displaystyle v=3\cdot\sqrt{\frac {9.8}{2\cdot 5}}$

$\displaystyle v=3\cdot\sqrt{\frac {9.8}{10}}$

Calculating:

$v=2.97\ m/s$

Now calculate the time:

$\displaystyle t=(3)/(2.97)$

$t=1.01\ sec$

The ball was 1.01 seconds in the air

Note: The time does not depend on the distance d at all. If we borrow the equation from free-fall motion, the time can be calculated with:

$\displaystyle t=\sqrt{\frac {2h}{g}}=\sqrt{\frac {10}{9.8}}=1.01\ sec$

When a contact force acts between two objects, both objects experience the same size force, but in opposite directions. This is Newton's Third Law of Motion. Explain this sentence clearly and give real life example.?

Answers

Answer:

These two forces are called action and reaction forces and are the subject of Newton's third law of motion. Formally stated, Newton's third law is: For every action, there is an equal and opposite reaction.

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