Which function in vertex form is equivalent to f(x) = 4 + x2 – 2x?

Answers

Answer 1
Answer: The question is asking us to find which function in the vertex form is equivalent to f ( x ) = 4 + x^2 - 2 x. We have to add 1 to make a squared binomial ( and also to subtract 1 ). f ( x ) = ( x^2 - 2 x + 1 ) - 1 + 4 = ( x - 1 )^2 + 3. Then we have the vertex point ( 1, 3 ). Answer: The function in vertex form is: f ( x ) = ( x - 1 ) ^2 + 3.
Answer 2
Answer:

Answer:

Vertex form of the function will be f(x) = (x - 1)² + 3.

Step-by-step explanation:

Vertex form of a quadratic function is given by f(x) = a(x - h)² + k

where (h, k) is the vertex of the given parabola.

Now we will convert the function in the vertex form.

f(x) = x² - 2x + 1 + 3

     = (x - 1)² + 3

Therefore, the vertex form of the function will be f(x) = (x - 1)² + 3

and the vertex will be (1, 3).


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Find the area of the polygon with the coordinates (1, 2), (3, 2), (3, 0), and(1,0).
2 sq. units
8 sq. units
4 sq. units
16 sq. units

Answers

Answer:

4 sq. units

Step-by-step explanation:

Since the polygon has 4 vertices, hence the polygon is a quadrilateral with four sides and four angles.

We can see that for this polygon, opposite sides are parallel and equal to each other.

To find the area of the polygon, we have to first get the length of the polygon and then the width of the polygon, hence:

The length is the distance between (1, 2) and (3, 2):

length=√((3-1)^2+(2-2)^2) =2\ units\n

The breadth is the distance between (3, 2) and (3, 0):

length=√((3-3)^2+(0-2)^2) =2\ units\n

Since length = breadth, hence this is a square.

Area= length * breadth = 2 * 2 = 4 sq. units

In the equation 2x - y = 4, the x-intercept is 2 and the y-intercept is -4.

Answers

Graph c best represents that statement

The sum of two numbers is 52 . The larger number is 2 less than twice the smaller number .What are the numbers

Answers

Answer:

35.34 and 16.66

Step-by-step explanation:

Given data

let the numbers be x and y

the smaller number = x

the larger number = y

x+y=52--------1

The larger number is 2 less than twice the smaller number

y=2x-2-------2

put y= 2x-2 in eqn 1

x+2x-2=52

3x-2=52

3x=52-2

3x=50

x= 50/3

x= 16.66

put x=16.66 in eqn 1 to find y

x+y=52

16.66+y= 52

y=52-16.66

y= 35.34

Hence the numbers are

35.34 and 16.66

Check

35.34+16.66= 52

Find the measure of angle ABC

Answers

In every triangle, the sum of the interior angles is 180°. The sum of the angles of this triangle is

32+(2x-15)+(x-5) = 2x+x+32-15-5 = 3x+12

and we want this sum to be 180, so we can write the following equation:

3x+12 = 180

subtract 12 from both sides:

3x = 168

divide both sides by 3:

x = \cfrac{168}{3} = 56

Now we can plug this value for x in the expressions for the two unknown angle to get their value:

B = x-5 = 56-5 = 51,\quad C = 2x-15 = 2\cdot 56-15 = 112-15 = 97

you will get x as 56 and angle ABC as 51°

Can u help me in this algebra problem??

Answers

40.
ok so
1 part almods
2 parts walnuts
3 part rasins
multiply them
almonds=12 per pound
walnuts=9 per pound
rasins=5 per pound

therefor
12 times 1+9 times 2+5 times 3=cost of ratio=45
45=a ratio with 1lb almond, 2lb walnuts, 3lb rasins

we need it to get down to 15
45/x=15
x=3

$45=1a+2w+3r
divide both sides by 3
$15=1/3a+2/3w+1r

we need to find total so add them
1/3+2/3+1=2

answer is 2lb




41.
repair
so he has to pay the employees so that is a minus from his income
therefor
8600-22x
8600 is his income
-22x is the amount he has to pay his employees

they are paid 22 dollars an hour and that is taken from his income so
-22 times number of hour=amoont to pay employee
therefor x=number of hours worked per week

answer is 2











40. 2lb
41. no. 2  'hours worked per week'

alan participated ina car race in which he had to cover a distance of at least 50 kilometers. he had fuel in his car for a maximum distance of 53 kilometers. if the distance is given by S (t) = 3t + 47, where t is the time in hours, find the minimum and maximum number of hours for which alan can drive his car.

Answers

This problem has more holes than swiss cheese.

ASSUME that the time he drives only depends on the distance he covers,
and has nothing to do with his speed or how he drives.

The race rules say he has to cover at least 50 km,
so the minimum time he can drive is the solution to
[ 50 = 3t + 47 ]
Subtract 47 from each side:
3 = 3t
Divide each side by 3 :
1 = t minimum

He has fuel for exactly 53 km, so the maximum time
he can drive is the solution to
[ 53 = 3t + 47 ]
Subtract 47 from each side :
6 = 3t
Divide each side by 3 :
2 = tmaximum