Two large populations of horses are being systematically crossed (mares from one population bred to stallions of the other and vice versa). Coat color is not a factor in determining which animals are selected and which individual matings are made (random matings). Frequencies of coat color genes at the C locus for population 1 are.85 for Cand.15 for c. Frequencies for Care.6 and care.4 for population 2. Given these values, what are the gene and genotypic frequencies of the F1? a. p=0.725, q = 0.275: P=0.51, H=0.43, Q=0.06
b. p=0.725.q = 0.275; P=0.06. H=0.56, Q=0.51
c. p=0.4.q = 0.6: P=0.12. H=0.56, Q=0.32
d. p=0.725.q = 0.275: P=0.34. H=0.57. Q=0.09

Answers

Answer 1
Answer:

Answer:

a. p=0.725, q = 0.275: P=0.51, H=0.43, Q=0.06

Explanation:

Let state our given parameters from the question:

Frequencies of coat color genes at the C locus for population 1 are .85 for C

This implies that the Allelic frequency C for population p1 =0.85

Frequencies of coat color genes at the c locus for population 1 are .15 for c

This implies that the Allelic frequency c for population q1 = 0.15

Frequencies for Care .6 i.e p2= 0.6

Frequencies for care .4 i.e, let that be q2= 0.4

The table below shows a diagrammatic representation of the above expression:

Alllelic Frequency                      C                                          c

Population 1                        (p1)   0.85                              (q1)   0.15

Population 2                       (p2)   0.6                               (q2)   0.4

Now, from above: let think of the table as a punnet square and then cross it together;

                                            (p1)  = 0.85                              (q1) =  0.15

p2 = 0.6                               p1p2                                       p2q1

                                            = 0.6 × 0.85                           = 0.15 × 0.6

                                            = 0.51 (P)                                = 0.09 (H)              

                                                                                                   

q2 = 0.4                               p1q2                                       q1p2

                                            = 0.85 × 0.4                           = 0.4 × 0.15

                                            =0.34 (H)                                = 0.06 (Q)

From the above table, the heterozygous are represented by (H)

Frequency of heterozygous can be calculated as:

= 0.09 + 0.34

= 0.43

Thus, we can conclude that the progenyF1 genotypic frequencies are:

P= 0.51

H= 0.43

Q= 0.06

Now, let us calculate the allelic frequencies, p and q in F1

p = P + 1/2 × (H)

= 0.51 + (1/2 × 0.43)

= 0.51 + 0.215

= 0.725

q =Q + 1/2× (H)

= 0.06 + (1/2 × 0.43)

= 0.06 × 0.215

= 0.275

Hence, p=0.725, q = 0.275: P=0.51, H=0.43, Q=0.06 , This makes option a the correct answer.


Related Questions

When compared to a cheek cell, a muscle cell contains more(A) vacuoles(B) ribosomes (C) mitochondria(D) chromosomes ​
An increase in cell size results in an increase in surface area to volume ration.a. trueb. false
Drosophila melanogaster have four pairs of chromosomes.a.what is the ploidy level at metaphase ii of meiosis?a. 8nb. 1nc. 4nd. 2ne. 0nb.what is the ploidy level at prophase of mitosis
PLEASE HELP!! i will mark brainliestWhich argument best explains the charge of an atomic nucleus? a. an atomic nucleus is positively charged because it is composed of neutrons b. an atomic nucleus is positively charged because it is composed of protonsc. An atomic nucleus is negatively charged because it is composed of electronsd. an atomic nucleus is negatively charged because it is composed of neutrons
When a piece of liver is dropped into hydrogen peroxide, the peroxide bubbles vigorously as the hydrogen peroxide (H2O2) decomposes into water (H2O) and oxygen (O2) This range change in reaction rate suggeststhat liver is a substrate for hydrogen peroxidethat liver contains lots of germsthe liver contains an enzyme that breaks down hydrogen peroxidethat hydrogen peroxide is a powerful enzyme

A student conducts an experiment to determine how the amount of water given to a plant affects its growth. What is the dependent variable for this experiment? a. the amount of water b. the height of the plant c. the amount of sunlight d. the amount of soil Please select the best answer from the choices provided

Answers

Answer: b. the height of the plant.

In an experimental set up an independent variable is the one which can be manipulated or change to observe the effects of such changes or manipulation on dependent variable. For example, plant growth is a dependent variable because it is dependent on independent variables such as amount of sunlight available, amount of fertilizers and water provided.

In this experiment, it is to be determined that how the amount of water given to a plant affects its growth. Here, water is an independent variable which can be change in the experiment and the affect of change can be observed on plant growth which is a dependent variable. A height represents the growth of the plant therefore, height of the plant is the dependent variable.

I think the answer to this is the height of the plant. The amount of water is the independent variable and the amount of sunlight and soil arent included in this experiment. 

What is this bug called?

Answers

Answer:

ASSASSIN BUG  

Which statements compare meiosis I and meiosis II? Check all that apply.-The parent cell in meiosis I is diploid and has 2n chromosomes.
-Meiosis I produces two gametes that have exactly the same genetic make up.
-Meiosis II creates four daughter cells that are genetically different from one another.
-After meiosis I, two daughter cells with haploid number of sister chromatids are produced.
-Four gametes with haploid number of chromosomes and single chromatids result after meiosis II.

Answers

Answer:

after meiosis I two daughter cells with haploid number of sister chromatids are produced.

the parent cell in meiosis I is diploid and has 2n chromosomes.

four gametes with haploid number of chromosomes and single chromatids result after meiosis II.

Explanation:

Answer:

Meiosis II creates four daughter cells that are genetically different from one another.

After meiosis I, two daughter cells with haploid number of sister chromatids are produced.

Four gametes with haploid number of chromosomes and single chromatids result after meiosis II.

Explanation:

What occurs when people are exposed to substances that their bodies are sensitive to? histamines


allergies


antihistamines


allergens

Answers

B. allergies occur when people are exposed to substances that their bodies are sensitive to.

What happens to the immune system when a person is exposed to allergies?

The immune system overreacts by producing an antibody called immunoglobulin E (IgE). These antibodies migrate to the cells, which release chemicals and cause an allergic reaction. This reaction usually causes symptoms in the nose, lungs, throat, sinuses, ears, lining of the stomach, or skin.

Allergies occur when the immune system reacts to foreign substances such as pollen, bee venom, animal scales, or foods that do not cause a reaction in most people. Your immune system produces a substance known as an antibody.

Learn more about allergies here: brainly.com/question/2681615

#SPJ2

They can have allergic reactions

Solar energy is used to produce energy-rich compounds in which structure?A.A
B.B
C.C
D.D

Answers

Chloroplast is the site for photosynthesis in plants. Thus, option A is correct.

What are chloroplasts?

Chloroplasts are the cell organelles present in the plants. Chloroplasts are one such type of plastids.

Chloroplasts are green in colour. They contain a green coloured pigment called chlorophyll which traps the solar energy.

The solarenergy is converted into chemicalenergy by a process called photosynthesis. The organic molecules so produced are the energyrich compounds.

Chloroplasts are chiefly found in the mesophyll region of the leaves.

Chloroplast consists of grana and stroma regions. The grana contain disc shaped coin like structures called thylakoids. The matrix of chloroplasts constitutes stroma region.

Various enzymes, DNA, ribosomes etc are found within the chloroplasts. Hence, they are also referred as 'cellwithinthecell'.

Chloroplasts have unique feature of self-replication. Chloroplasts are similar in function to mitochondria in animal cells.

Therefore, chloroplasts are important plant structures for photosynthesis.

Learn more about chloroplasts, here:

brainly.com/question/2516251

#SPJ2

In plants, photosynthesis takes place in chloroplasts. Option A is correct.

What is Chloroplast ?

Plant, algae, and certain protist cells have membrane-bound organelles called chloroplasts.

So, They are in charge of the process known as photosynthesis, which turns light energy into chemical energy in the form of glucose in green plants and some other animals. Life on Earth is supported by this essential mechanism of energy conversion.

Therefore, In plants, photosynthesis takes place in chloroplasts.

Learn more about Chloroplast here : brainly.com/question/1741612

#SPJ3

12. What term describes the average weather conditions in a geographic area?O A. Weather
O B. Climate
O C. Precipitation
O D. Temperature

Answers

Answer:

The answer is B

Explanation:

Climate is the average weather conditions in a geographic area.