What is 6^2 in expanded form. A.12 b.2x2x2x2x2x2 c.36 d.6x6
Answers
6x6 is 6² in expanded form.
Given that, the expression 6² to expand the equation,
The expanded form of the given expression will be 6 multiplied by 6.
In another word, the expanded form of the given expression will be:
6² = 6*6
Therefore, option D is correct.
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Related Questions
A cab charges $1.75 for the first mile and $0.25 for each additional mile. Write and solve an inequality to determine how many miles Eddie can travel if he has $15 to spend.$1.75 + $0.25x ≤ $15; x ≤ 53 miles$1.75 + $0.25x ≥ $15; x ≥ 53 miles$0.25 + $1.75x ≤ $15; x ≤ 8 miles$0.25 + $1.75x ≥ $15; x ≥ 8 miles
The circumference of a circular painting is 28.26 feet. What is the diameter of the painting? Use 3.14 for π and do not round your answer.
Is the expression 42 undefined? If not, findthe quotient.-7
A recipe for salad dressing calls for 1/4 cup of vinegar. You have 4 cups of vinegar. How many batches of salad dressing could you with the vinegar?
Answers
Answer: a+6d will defines the series for seven terms i.e. 38.
Step-by-step explanation:
Since we have given that
Here, a = first term = 8
d = common difference is given by
So, we need to find the seven terms:
So, here n = 7
So, it becomes,
Hence, a+6d will defines the series for seven terms i.e. 38.
example
8+5= 13
13+5=18
18+5=23
23+5=28
28+5=33
and so on :)
Answers
In this case, 40 hectograms is equal to 4000 grams.
To convert hectograms to grams, we need to know that 1 hectogram (hg) is equal to 100 grams (g).
Now, let's calculate the number of grams in 40 hectograms:
1 hectogram = 100 grams
Therefore, 40 hectograms will be:
40 hectograms = 40 * 100 grams
40 hectograms = 4000 grams
So, there are 4000 grams in 40 hectograms.
In summary, to convert hectograms to grams, we use the conversion factor of 1 hectogram = 100 grams. By multiplying the number of hectograms by 100, we get the equivalent weight in grams. In this case, 40 hectograms is equal to 4000 grams. This conversion is based on the metric system, where prefixes like hecto- and kilo- represent multiples of 100 and 1000, respectively, making it easy to convert between different units of weight.
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K: Kilos
H: Hecto
D: Deka
B: Base (liters or grams etc.)
D: Deci
C: Centi
M: Milli
Now, since you are going from hectograms (hecto) to grams (base) you will move the decimal to the right 2 times (since base is 2 bellow hecto) So that means: There are 4,000 grams in 40 hectograms.
B. False
Answers
the answer is false
Quadratic expression
Cubic expression
Quartic expression
Answers
Answer:it is a linear expression
Step-by-step explanation:
Linear expressions or equations are expressions in which the highest power of the variable is one.
Quadratic expressions or equations are expressions in which the highest power of the variable is two.
Cubic expressions or equations are expressions in which the highest power of the variable is three.
Quartic expressions or equations are expressions in which the highest power of the variable is four.
From the expression, 5x + 2 given,
the highest power of x is one. So it is a linear expression.
Answers
Then, 3/5 = h/4.9
h = (3 x 4.9)/5 = 2.94
Therefore, the height of the Alter Stone is 2.94 meters
2x + y ≤ 8
2x - 5y < 20
Answers
Answer: answer below.
Step-by-step explanation:
To solve this system of linear inequalities, we can use a graphical method or algebraic method.
Let's start with the algebraic method.
First, let's rearrange the inequalities to solve for one variable in terms of the other.
From the first inequality, we have:
x ≤ 10 - 2y
From the second inequality, we have:
y ≤ 8 - 2x
From the third inequality, we have:
x ≤ (20 + 5y)/2
Now, let's plot the graphs of these inequalities on a coordinate plane.
Graphing the first inequality, x ≤ 10 - 2y, we start by drawing the line x = 10 - 2y. Since it is a "less than or equal to" inequality, we will draw a solid line.
Graphing the second inequality, y ≤ 8 - 2x, we start by drawing the line y = 8 - 2x. Again, since it is a "less than or equal to" inequality, we will draw a solid line.
Graphing the third inequality, x ≤ (20 + 5y)/2, we start by drawing the line x = (20 + 5y)/2. This time, since it is a "less than" inequality, we will draw a dashed line.
Now, we shade the region that satisfies all three inequalities. This region is the intersection of the shaded regions of the individual inequalities.
Finally, we can determine the solution by looking at the shaded region on the graph. The solution is the set of all points that lie within or on the boundary of the shaded region.
Alternatively, we can also solve the system of inequalities algebraically by finding the points where the lines intersect. We can then check if these points satisfy all three inequalities.