12
x

8
y
=
24
6
x

y
=
21

Answers

Answer 1
Answer:

Answer: x=4

              y=3

Step-by-step explanation:

12x-8y=24

6x-y=21

---------------------

y=6x-21

12x-8(6x-21)=24

12x-48x+168=24

-36x=-144

x=144/36

x=4

y=24-21

y=3


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1,522,968 in word form

Answers

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Can someone help me please

Answers

Area of rhombus = length x height = 6 x 4 = 24 units²



Answer: 24 units²

4(x + 3) + 2x = 6(x + 2)5 + 2(3 + 2x) = x + 3(x + 1)

5(x + 3) + x = 4(x + 3) + 3

4 + 6(2 + x) = 2(3x + 8)

which one has no solutions ?

Answers

The second option is your answer. 

5 + 2(3 + 2x) = x + 3(x + 1)
5 + 6 + 4x = x + 3x + 3
11 + 4x = 4x + 3

Subtract 4 from both sides. You are left with an untrue statement:
11 = 3
11 ≠ 3 so therefore your answer is no solution. 
Let’s try to look at each one.

First one:
4(x+3)+2x=6(x+2)
We can multiply.
4x+12+2x=6x+12
By looking at this, you can tell it’s equal due to the fact when you add like terms, they will have to same answer.

Second one:
5+2(3+2x)=x+3(x+1)
Let’s multiply.
5+6+4x=x+3x+1
I can already tell this isn’t equal. One has +11 and the other has +1. To make sure, let’s have x=1
5+2(3+2)=1+3(1+1)
5+2(5)=1+3(2)
5+10=1+6
15=7
7 and 15 are not the same number, so the second one doesn’t have any solutions.

What is 6 divided by 3.45?
What is 12 divided by 5.25?
What is 24 divided by 10.99?

Answers

6 divided by 3.45 is 1.73912 divided by 5.25 is 2.28524 divided by 10.99 is 2.183

6 ÷ 3.45 = 1.739

12 ÷ 5.25 = 2.285

24 ÷ 10.99 = 2.183

Brainlest please!

What are the cofficients in the expression 8y2 +12x-5y+7

Answers

the coefficients are 8,12 and 5

Find the enthalpy change per mole of sodium when sodium reacts with water 8 grams of sodium reacts with 227 cm of water, producing a temperature change from 298Kto 308.4 K The specific heat capacity of water is 4.18 J/K 9.

Answers

Answer:

The enthalpy change per mole of sodium when sodium reacts with water is 28.36 kJ

Step-by-step explanation:

The given parameters are;

Mass of sodium = 8 grams = 0.008 kg

Volume of water = 227 cm³ = 0.000227 m³

Initial water temperature, T₁ = 298 K

Final water temperature, T₂ = 308.4 K

Specific heat capacity of water = 4.18 J/(K·g)

Density of water = 1000 kg/m³

Mass of water = 1000×0.000227 = 0.227 kg = 227 g

Heat change, ΔH = m×c×ΔT = m×c×(T₂ - T₁)

ΔH = 227*4.18*(308.4 - 298) = 9868.144 J = 9.868 kJ

Molar mass of sodium = 22.989769 g/mol

Therefore, 8 grams contains;

8/22.989769 = 0.348 moles of Na

Which gives the enthalpy change per 0.348 moles of Na when sodium reacts with water = 9.868 kJ

Therefore, when one mole of Na reacts with water we have;

The enthalpy change per 0.348/0.348 = 1 mole of Na when sodium reacts with water = 9.868 kJ/0.348 = 28,358.3 J = 28.36 kJ.