PHYSICS COLLEGE

A proton and an alpha particle (helium nucleus consisting of two protons and two neutrons) are accelerated from rest across the same potential difference. Assume the proton mass and the neutron mass are roughly the same and neglect any relativistic effect. Compared to the final speed of the proton, the final speed of the alpha particle is?1. less by a factor of 22. less by a factor of √ 23. less by a factor of 44. greater by a factor of 25. the same

Answers

Answer 1

Answer:

Answer:

option B

Explanation:

we know,

change in energy is equal to

$W = (1)/(2)m(v^2 - u^2)$

$W = (1)/(2)m(v^2 - 0^2)$

$W = (1)/(2)m v^2$

$q = (1)/(2)m v^2$

proton mass and the neutron mass are roughly the same

so,

$q \alpha m v^2$

now,

$(q_p)/(q_(\alpha)) = (m_p v_p^2)/(m_(\alpha)v_(\alpha)^2)$

$(q_p)/(q_(\alpha)) = (m_p v_p^2)/(2 m_pv_(\alpha)^2)$

we know,

mass of alpha particle is four times mass of the mass of proton.

mα = 4 m_p

$(e)/(2e) = ( v_p^2)/(4 v_(\alpha)^2)$

$( v_p^2)/(v_(\alpha)^2) = 2$

$v_(\alpha)^2 =( v_p^2)/(2)$

$v_(\alpha)=( v_p)/(√(2))$

less by a factor of √2

Hence, the correct answer is option B

Related Questions

A crystalline grain of nickel in a metal plate is situated so that a tensile load is oriented along the [111] crystal direction (a) If the applied stress if 0.45 MPa, what will be the resolved shear stress, tRss, along the [101] direction within the (11 T) plane? (b) What tensile stress is required to produce a critical resolved shear stress, TcRss of 0.242 MPa
At the instant the traffic light turns green, a car that has been waiting at an intersection starts ahead with a constant acceleration of 3.60 m/s^2 . At the same instant a truck, traveling with a constant speed of 23.5 m/s , overtakes and passes the car. a. How far beyond its starting point does the car overtake the truck?b. How fast is the car traveling when it overtakes the truck?
A train of 150 m length is going toward north direction at a speed of 10 ms–1 and a parrot is flying towards south direction parallel to the railway track with a speed of 5 ms–1. The time taken by the parrot to cross the train is equal to.?
A propeller is modeled as five identical uniform rods extending radially from its axis. The length and mass of each rod are 0.777 m and 2.67 kg, respectively. When the propellor rotates at 573 rpm (revolutions per minute), what is its rotational kinetic energy?
A disgruntled autoworker pushes a small foreign import offacliff with a height of h. the vehicle lands a distance awayfromthe cliff. Determine how fast the vehicle was pushed offthecliff.

Imagine two billiard balls on a pool table. Ball A has a mass of 2 kilograms and ballB has a mass of 3 kilograms. The initial velocity of ball A is 9 meters per second to
the right, and the initial velocity of the ball B is 6 meters per second to the left. The
final velocity of ball A is 9 meters per second to the left, while the final velocity of
ball B is 6 meters per second to the right.

1. Explain what happens to each ball after the collision. Why do you think this
occurs? Which of Newton’s laws does this represent?

Answers

This is an example of an elastic collision. The two objects collide and return to their original shapes and move separately. In such a collision, kinetic energy is conserved. I think we can agree that this represents Newton's third law by demonstrating conservation of momentum.

Answer:

Yes, the law of conservation of momentum is satisfied. The total momentum before the collision is 1.5 kg • m/s and the total momentum after the collision is 1.5 kg • m/s. The momentum before and after the collision is the same.

Explanation:

Why must the Ojibwe people pay close attention to the seasons? a.) they must be ready to move to a new place where they can hunt

b.) they only fish during the warmest times of the day

c. they must know the right time of year for Gathering certain foods

d.) they still catch walleye with the steering method

Answers

The Ojibwe people pay close attention to the seasons in order to know right

time of year for gathering certain foods.

The Ojibwe mostly hunt for fishes through the use of various techniques

such as:

Fishing at night

Use of flashlight

Why do they hunt for Fishes at night?

They hunt for fishes at night because they are usually docile during that time

which enables them to catch them easily as against during the day when

they are much active.

Read more about Ojibwe people here brainly.com/question/24963033

Answer:C. They must know the right time of year for gathering certain foods

Explanation:

I got it correct

A battery lighting a bulb is an example of _ energy converting to _ energy.

Answers

the power source is electrical ( whether the light is plugged in or has a battery)

the light bulb converts the electricity to light and heat.

in a fluorescent bulb, it is different, but the electricity is again converted to light, very little heat, though.

Electric energy converting into light and heat energy.

So, for the first blank electric, and the second blank the better answer is light.

You are watching an archery tournament when you start wondering how fast an arrow is shot from the bow. Remembering your physics, you ask one of the archers to shoot an arrow parallel to the ground. Unfortunately the archer stands on an elevated platform of unknown height. However, you find the arrow stuck in the ground 67.0 m away, making a 3.00 ∘ angle with the ground.How fast was the arrow shot?

Answers

To develop this problem it is necessary to apply the kinematic equations that describe displacement, velocity and clarification.

By definition we know that velocity is defined as the change of position due to time, therefore

$V = (d)/(t)$

Where,

d = Distance

t = Time

Speed can also be expressed in vector form through its components $V_x$ and $V_y$

In the case of the horizontal component X, we have to

$V_x = (d)/(t)$

Here d means the horizontal displacement, then

$t = (d)/(V_x)$

$t = (67)/(V_x)$

At the same time we have that the vertical component of the velocity is

$V_y = gt$

Here,

g = Gravity

Therefore using the relation previously found we have that

$V_y = g (67)/(V_x)$

The relationship between the two velocities and the angle can be expressed through the Tangent, therefore

$tan\theta = (V_y)/(V_x)$

$tan \theta = (g (67)/(V_x) )/(V_x)$

$tan 3 = (9.8(67)/(V_x) )/(V_x)$

$tan 3 = (9.8*67)/(V_x^2)$

$V_x^2 = (9.8*67)/(tan 3)$

$V_x= \sqrt{ (9.8*67)/(tan 3)}$

$V_x = 111.93m/s \hat{i}$

This is the horizontal component, we could also find the vertical speed and the value of the total speed with the information given,

Then $V_y,$

$V_y = g (67)/(V_x)$

$V_y = 9.8*(67)/(111.93)$

$V_y = 5.866m/s\hat{j}$

$|\vec{V}| = √(111.93^2+5.866^2)$

$|\vec{V}| = 112.084m/s$

Bailey wants to find out which frozen solid melts the fastest: soda, ice, or orange juice. She pours each of the three liquids into the empty cubes of an ice tray, and then places the ice tray in the freezer overnight. The next day, she pulls the ice tray out and sets each cube on its own plate. She then waits and watches for them to melt. When the last part of the frozen liquid melts, she records the time.

Answers

Answer:

its 45 over 6

Explanation:the answer is in the question

Answer: Only the melted cube's shape changed.

Explanation:

7: A 2 mA current passes through a 1.4 cm long solenoid producing a magnetic field of .162 G. How many turns are in the solenoid

Answers

Answer:

The number of turns is 64449395

Explanation:

The expression for the solenoid formula is stated below, and it is what we are going to use to solve for the number of turns

B= μ₀nl

where B= magnetic field

μ₀= permeability , 4π × 10⁻⁷ Henry

n= number of turns

l= length of coil

Given data

current I= 2 mA

length L= 1.4 cm to meter we have 0.014

magnetic field B= 0.162 T

From the expression we can make n subject of formula we have

n=B/μ₀l

Substituting we have

n= 0.162/4π × 10⁻⁷*2*10^-3

n= 0.162/8π × 10^⁻10

n= 0.162/2.5136*10^-9

n= 64449395

Other Questions

A physics cart has a projectile launcher mounted on top. While traveling on a straight track at 0.500 m/s, a projectile is fired. It lands back in the same place on top of the launcher after the cart has moved a distance of 2.30 m. In the frame of reference of the cart, (a) at what angle was the projectile fired and (b) what was the initial velocity of the projectile? (c) What is the shape of the projectile as seen by an observer on the cart? A physics student is watching the demonstration from a classroom seat. According to the student, (d) what is the shape of the projectile’s path, and (e) what is its initial velocity?

The predictions of Rutherford's scattering formula failed to correspond with experimental data when the energy of the incoming alpha particles exceeded 32MeV32MeV. This can be explained by the fact that the predictions of the formula apply when the only force involved is the electromagnetic force and will break down if the incoming particles make contact with the nucleus. Use the fact that Rutherford's prediction ceases to be valid for alpha particles with an energy greater than 32MeV32MeV to estimate the radius rrr of the gold nucleus.

Air trapped in the cooling system could create undesirable areas of combustion heat buildup in the engine called _____.

Two particles, one with charge -6.29 × 10^-6 C and one with charge 5.23 × 10^-6 C, are 0.0359 meters apart. What is the magnitude of the force that one particle exerts on the other?