Answer:
The specific heat capacity of the metal is 1.143 J/g°C
Explanation:
A typical excersise of calorimetry:
Q = m . C . ΔT
ΔT = Final T° - Initial T°
m = mass
In this case, the heat released by the metal is gained by the water to rise its temperature.
Qmetal = Qwater
(We consider that metal was at the same T° of water)
22.5 g . C . (65°C - 25.55°C) = 25 g . 4.184 J/g°C . (35.25°C - 25.55°C)
22.5 g . C . 39.45°C = 25g . 4.184 J/g°C . 9.7°C
887.625 g.°C . C = 1014.62J
C = 1014.62J / 887.625 g.°C
C = 1.143 J/g°C
Answer: 240
Explanation:
A serving of fish contains 236 kcal.
To find the number of kilocalories (kcal) in a serving of fish, we need to calculate the energy from protein and fat separately and then add them together. The energy from protein is calculated by multiplying the amount of protein by its caloric value of 4 kcal/g. So, 50 g of protein provides (50 g) x (4 kcal/g) = 200 kcal. The energy from fat is calculated in the same way, so 4 g of fat provides (4 g) x (9 kcal/g) = 36 kcal. Finally, we add the energy from protein and fat together, resulting in a total of 200 kcal + 36 kcal = 236 kcal in the serving of fish.
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1)Cu
2)PO4-3
3)SO2
Answer:
Explanation: the answer is B. PO4-3
Silver gets oxidized when electroplating silver (Ag) on iron (Fe).
Electroplating is basically the process of plating a metal onto the other by hydrolysis mostly to prevent corrosion of metal or for decorative purposes.
Silver gets oxidized when electroplating silver (Ag) on iron (Fe).
In the process of putting a sliver coating on iron, the iron is the cathode on which the silver ions get reduced.
Learn more about electroplating here:
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