On an intramural softball team, the proportion of hits to at bats for the entire team during the last season was 30% of 300 attempts. Estimate the true proportion of hits using a 90% CI. The answers need to be proportions (not percents) and rounded to the nearest hundredth (two (2) decimal places) to be counted as correct. (For example, if my CI is (0.1002, 0.2159) then they need to be input as 0.10 and 0.22 to be correct. **These are not the answers to this question :-) **)The lower bound is____ and the upper bound is ____

Answers

Answer 1
Answer:

Answer: The lower bound is 0.26 and the upper bound is 0.34.

Step-by-step explanation:

Formula to find the confidence interval for population proportion (p) is given by :_

\hat{p}\pm z^* \sqrt{\frac{\hat{p}(1-\hat{p})}{n}}

, where n= sample size

z* = Critical value. (two-tailed)

\hat{p} = Sample proportion.

Let p be the true population proportion of hits to at bats for the entire team during the last season.

As per given , we have

n= 300

\hat{p}=0.30

By z-table , the critical value for 90% confidence interval : z* = 1.645

Now , 90% confidence interval for the proportion of hits to at bats for the entire team during the last season:

0.30\pm (1.645) \sqrt{(0.30(1-0.30))/(300)}

0.30\pm (1.645) √(0.0007)

0.30\pm (1.645) (0.0264575131106)

\approx0.30\pm0.0435

=(0.30-0.0435,\ 0.30+0.0435)\n\n=(0.2565,\ 0.3435)\approx(0.26,\ 0.34)

The lower bound is 0.26 and the upper bound is 0.34.


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A study published in 1993 found that babies born at different times of the year may develop the ability to crawl at different ages! The author of the study suggested that these differences may be related to the temperature at the time the infant is 6 months old. (Benson and Janette, Infant Behavior and Development [1993]. The study found that 32 babies born in January crawled at an average age of 29.84 weeks, with a standard deviation of 7.08 weeks. Among 21 July babies, crawling ages averaged 33.64 weeks, with a standard deviation of 6.91 weeks. Is this difference significant?
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Write an equation in slope-intercept form of the line that passes through thegiven point and is parallel to the graph of the given equation. (-3, 12); y = -3x + 5

Write a verbal expression for each algebraic expression.2
1.) 9a

2.) c + 2d

3
3.) 7x - 1

Answers

1. nine(a)
2. c + two(d)
3. seven(x) - 1

What is 2 times 2..










Answers

Answer:

4

Step-by-step explanation:

2x2=4.

Answer:

1,000,000,000 JK its 4

2+2=4

so...

2x2=4

What value of b will cause the system to have an infinite number of solutions? V = 6x + b
-3 x + 1/2 V = -3

Answers

Answer:

-6

Step-by-step explanation:

V = 6x + b

 1/2 V -3 x = -3

V - 6x = -6

V - 6x  =  b

Allied Corporation is trying to sell its new machines to Ajax. Allied claims that the machine will pay for itself since the time it takes to produce the product using the new machine is significantly less than the production time using the old machine. To test the claim, independent random samples were taken from both machines. You are given the following results.New Machine Old Machine
Sample Mean 25 23
Sample Variance 27 7.56
Sample Size 45 36
As the statistical advisor to Ajax, would you recommend purchasing Allied's machine? Explain.

Answers

Answer:

z(s) is in the acceptance region. We accept H₀  we did not find a significantly difference in the performance of the two machines therefore we suggest not to buy a new machine

Step-by-step explanation:

We must evaluate the differences of the means of the two machines, to do so, we will assume a CI  of 95%, and as the interest is to find out if the new machine has better performance ( machine has a bigger efficiency or the new machine produces more units per unit of time than the old one) the test will be a one tail-test (to the left).

New machine

Sample mean                  x₁ =    25

Sample variance               s₁  = 27

Sample size                       n₁  = 45

Old machine

Sample mean                    x₂ =  23  

Sample variance               s₂  = 7,56

Sample size                       n₂  = 36

Test Hypothesis:

Null hypothesis                         H₀             x₂  -  x₁  = d = 0

Alternative hypothesis             Hₐ            x₂  -  x₁  <  0

CI = 90 %  ⇒  α =  10 %     α = 0,1      z(c) = - 1,28

To calculate z(s)

z(s)  =  ( x₂  -  x₁ ) / √s₁² / n₁  +  s₂² / n₂

s₁  = 27     ⇒    s₁²  =  729

n₁  = 45    ⇒   s₁² / n₁    = 16,2

s₂  = 7,56   ⇒    s₂²  = 57,15

n₂  = 36     ⇒    s₂² / n₂  =  1,5876

√s₁² / n₁  +  s₂² / n₂  =  √ 16,2  + 1.5876    = 4,2175

z(s) = (23 - 25 )/4,2175

z(s)  =  - 0,4742

Comparing z(s) and  z(c)

|z(s)| < | z(c)|  

z(s) is in the acceptance region. We accept H₀  we did not find a significantly difference in the performance of the two machines therefore we suggest not to buy a new machine

The very hight dispersion of values s₁ = 27 is evidence of frecuent values quite far from the mean

Question 6/6What is the 100th term of the sequence with the following explicit rule: f(n) = 9n-1
А. 900
ОО
B. 899

Answers

Answer: 899

Explanation:

Replace n with 100 and simplify

f(n) = 9n-1

f(100) = 9(100)-1

f(100) = 900-1

f(100) = 899

The 100th term is 899

899

9(100)-1

900-1

899

Brainliest?

Sofia bought a clothes iron that was discounted 15% off of the original price of $35. What was the sale price of the clothes iron?

Answers

Answer:

35 - 0.15 * 35 so it is $29.75

Step-by-step explanation:

I got u

Answer:

$29.75

Step-by-step explanation:

15% = .15

.15 x 35 = 5.25

35 - 5.25 = 29.75