PHYSICS COLLEGE

Last night, Shirley worked on her accounting homework for one and one half hours. During that time, she completed 6 problems. What is the velocity in problems per hour? a. 6 per hour
b. 4 per hour
c. 10 per hour
d. 0.67 per hour
e. 15 per hour

Answers

Answer 1
Answer:

Answer:

velocity in problems per hour = 4 per hour

so correct option is b. 4 per hour

Explanation:

given data

worked on  homework time = 1.5 hour

completed = 6 problems

to find out

What is the velocity in problems per hour

solution

we know that Shirley solve complete 6 accounting homework problem in 1.5 hour so her velocity  in problems per hour will be as

velocity in problems per hour =  (complete\ problem)/(time\ taken)   ..................1

put here value we will get

velocity in problems per hour =  (6)/(1.5)

velocity in problems per hour = 4 per hour

so correct option is b. 4 per hour
Answer 2
Answer:

Answer:

option (b) is correct

Explanation:

time t = 1 and half hour = 1.5 hour

Number of problems, n = 6

So, the velocity in problems

v = n / t

v = 6 / 1.5

v = 4

So, the rate is 4 problems per hour.

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Answers

Final answer:

The net magnetic force exerted by the external magnetic field on a current-carrying wire formed into a loop in a uniform magnetic field is absolutely zero since the individual forces on each section of the loop cancel each other out.

Explanation:

The force exerted by a magnetic field on a current carrying wire is given by Lorentz force law, which says that the force is equal to the cross product of the current and the magnetic field. However, in this case, where the wire is formed into a loop with current flowing in a counter-clockwise direction in presence of an external magnetic field, the individual forces on each infinitesimal section of the loop cancel each other out. Therefore, the net magnetic force exerted by the external field on the entire loop is zero.

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Final answer:

The magnetic force exerted on a current-carrying wire loop by an external magnetic field can be calculated using the equation F = I * R * B.

Explanation:

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A large rectangular tub is filled to a depth of 2.60 m with olive oil, which has density 915 kg/m3 . If the tub has length 5.00 m and width 3.00 m, calculate (a) the weight of the olive oil, (b) the force of air pressure on the sur- face of the oil, and (c) the pressure exerted upward by the bottom of the tub.

Answers

Answer:

weight is 3.50 x 10^5 N

force is 1.52 * 10^6 N

pressure is 1.25 * 10^5 Pa

Explanation:

given data

Given data

depth = 2.60 m

density = 915 kg/m3

length = 5.00 m

width = 3.00 m

to find out

weight of the olive oil, force of air pressure and the pressure exerted upward

solution

we know density = mass / volume

mass = density* width *length *depth

mass = (915)(3)(5)(2.60)

mass = 3.57 x 10^4 Kg

so weight = mg = 3.57 x 10^4 (9.81) = 3.50 x 10^5 N

weight is 3.50 x 10^5 N

and

we know force = pressure * area

area = 3 *5 = 15 m²

and we know atmospheric Pressure is about 1.01 * 10^5 Pa

so force = 1.01 * 10^5 (15) = 1.52 x 10^6 N

force is 1.52 * 10^6 N

and

we know Fup - Fdown = Weight

so

Fup = 1.52 *  10^6 + 3.50 *  10^5

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so pressure = Fup / area

pressure =  1.87 * 10^6  / 15

pressure is 1.25 * 10^5 Pa

The deflection plates in an oscilloscope are 10 cm by 2 cm with a gap distance of 1 mm. A 100 volt potential difference is suddenly applied to the initially uncharged plates through a 1025 ohm resistor in series with the deflection plates. How long does it take for the potential difference between the deflection plates to reach 55 volts?

Answers

Explanation:

Given data:

Area A = 10 cm×2 cm = 20×10⁻⁴ m²

Distance d between the plates = 1 mm = 1×10⁻³m

Voltage of the battery is emf = 100 V

Resistance = 1025 ohm

Solution:

In RC circuit, the voltage between the plates is related to time t. Initially the voltage is equal to that of battery V₀ = emf = 100V. But After time t the resistance and capacitor changes it and the final voltage is V that is given by

V = V_(0)(1-e^{(-t)/(RC) } )\n(V)/(V_(0) ) = 1-e(^{(-t)/(RC) }) \ne^{(-t)/(RC) } = 1- (V)/(V_(0) )

Taking natural log on both sides,

e^{(-t)/(RC) } = 1- (V)/(V_(0) ) \n(-t)/(RC) = ln(1-(V)/(V_(0) ) )\nt = -RCln(1 - (V)/(V_(0) ))

t = -RC ln (1-(V)/(V_(0) ))        (1)

Now we can calculate the capacitance by using the area of the plates.

C = ε₀A/d

  = ((8.85*10^(-12))) (20*10^(-4)) )/(1*10^(-3) )

  = 18×10⁻¹²F

Now we can get the time when the voltage drop from 100 to 55 V by putting the values of C, V₀, V and R in the equation (1)

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 = -(1025Ω)(18×10⁻¹² F) ln( 1 - 55/100)

 = 15×10⁻⁹s

= 15 ns

A certain lightning bolt moves 50.0 c of charge. how many fundamental units of charge (qe) is this?

Answers

The lightning bolt that moves 50.0 C of charge is converted to qe units. The conversion factor is 1 coulumb is equivalent to 6.24150975·10^18 e. Thus, converting 50 C to e is:

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Explanation:

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Answers

Answer:

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Explanation:

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Note :The hole 2 is sited below the workpiece when viewed from the front view while the Datum B is positioned on the left end of the workpiece also note that the diameter is

What explains why a prism separates white light into a light spectrum?A. The white light, on encountering the prism, undergoes both reflection and refraction; some of the reflected rays re-enter the prism merging with refracted rays changing their frequencies.
B. The white light, on entering a prism, undergoes several internal reflections, forming different colors.
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D. The different colors that make up a white light are wavelengths that are invisible to the human eye until they pass through the prism.
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Answers

Answer :

QUESTION①)

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Answer:

I think the answer probably be B
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