Carbon disulfide (CS2) undergoes a single displacement reaction with O2 to form CO2. If 100 grams of CS2 reacts with 38 grams of O2, what will the limiting reagent be?CS2 + O2 CO2 + 2S

Answers

Answer 1
Answer: The balanced chemical reaction is:

CS2 + O2 = CO2 + 2S

We are given the amounts of the reactants. These amounts will be the starting point for the calculations. First, we convert these amounts into moles.

100 g CS2 (1 mol / 76.15 g ) = 1.3132 mol CS2
38 g O2 (1 mol / 32 g) = 1.1875 mol O2

From the reaction, the mole ratio of the reactants is 1:1. Therefore, the limiting reactant is CS2.

Answer 2
Answer:

Answer: O_2

Explanation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Moles of CS_2=(100g)/(76g/mol)=1.3moles

Moles of O_2=(38g)/(32g/mol)=1.2moles

For the given chemical reaction, the equation follows:

CS_2+O_2\rightarrow CO_2+2S

By Stoichiometry:

1 mole of  oxygen reacts with 1 mole of carbon disulphide

So, 1.2 moles of oxygen reacts with = (1)/(1)* 1.2=1.2moles of carbon disulphide

As, the required amount of carbon disulphide is more than the required amount. Hence, it is considered as the excess reagent.  (1.3-1.2)= 0.1 mole will be left unused.

Oxygen is considered as a limiting reagent because it limits the formation of product.


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Compounds that do not conduct an electric current in either aqueous solution or when molten are referred to as _____.a. electrolyte b. nonelectrolyte c. not listed d. ionic

Which compound is a saturated hydrocarbon?

Answers

Saturated hydrocarbons are organic compounds that contain only single bonds between the carbon atoms. They are known to be the simplest organic compounds. They are termed as such because they are saturated with water. Examples are the alkanes (ethane, methane, propane, butane, etc.).

_______ is a media that consists of natural or synthetic mineral or plant substances that deposit crystalline or splinter-like fragments in the paper fibers.a. Dry media
c. Silverpoint
b. Ink painting
d. Liquid media

Answers

Answer : Option A) Dry media


Explanation : i) Dry media is a media that deposits graphite, charcoal, pastels, ordinary pencils, then moistened with a wet brush to get various painterly effects on the paper fibers.


ii) Silverpoint - Silverpoint media uses red chalk or traces of black pencil on white-coated paper usually the manuscripts,


iii) Ink Painting - Uses various inks on the paper.


iv) Liquid media - uses liquid pigments suspended in some base which in liquid state that soaks the paper.

Dry media is a media that consists of natural or synthetic mineral or plant substances that deposit crystalline or splinter-like fragments in the paper fibres. 

What is a bond called that shares electrons between two neutral atoms?A. Polar bond
B. Covalent bond
C. Metallic bond
D. Ionic bond

Answers

ionic bonds is a type chemical bond formed through an electrostatic attraction between two opposite charged ions.

covalent bond involves a pair of electrons being shared between atoms. 

Answer

B. covalent bond

The molar mass of nitrogen (N2) is 28.02 g/mol. What is the mass, in grams, of 4.60 mol of N2?0.164
6.09
23.4
129

Answers

Molar mass nitrogen ( N2 ) = 28.02 g/mol

1 mol N2 -------> 28.02 g
4.60 mol ---------> x g

x = 4.60 * 28.02

x = 129 g of N2

hope this helps!.



Answer:

Option D: 129 grams

Explanation:

edge! hope this helps

Many laboratory gases are sold in steel cylinders with a volume of 43.8 L. What mass (in grams) of argon is inside a cylinder whose pressure is 17615kPa at 23∘C?

Answers

It's very simple... if we remember value of Universal Gas Constant R and Ideal Gas Law, so...

Ideal Gas Law
pV = nRT, where:
p - pressure (in kPa),
V - volume (in L),
n - number of moles (in mol),
R - universal cas constant (in kPa * L / mo l* K),
T - temperature (in K)

n = m/M, where:
n - number of moles,
m - mass (in grams),
M - molar mass of ingredient (in g/mol) - you find this at Periodic Table.

pV = nRT ---> pV = mRT/M ---> pVM = mRT ---> pVM/RT = m

p = 17615 kPa
T = 273.15 + 23 = 296.15 K
V = 43.8 L
R = 8.314 kPa * L / mol * K
M (for argon) = 39.948 g/mol

and

m = (17615 kPa * 48.3 L * 39.948 g/mol) / (296.15 K * 8.314 kPa * L / mol * K)
m = 13803.93 grams of Argon

State one conclusion from Rutherford experiment that contradicted one conclusion made by Thompson

Answers

One conclusion from Rutherford's experiment that greatly contradicted Thompson's experiment is that 'atoms are mostly empty space, with positively charged nucleus'. While Thompson concluded that there are negatively charged particles as part of the internal structure of the atoms. 

Answer:

One conclusion from Rutherford's experiment that greatly contradicted Thompson's experiment is that 'atoms are mostly empty space, with positively charged nucleus'.

Explanation: