MATHEMATICS MIDDLE SCHOOL

Find the minimum value of C=2x+y subject to the following constraints:
Please help!!!

Answers

Answer 1

Answer:

Answer:

The minimum value of C is 20

Step-by-step explanation:

Sketch the constraints, that is sketch

2x + 3y = 24

with intercepts (0, 8 ) and (12, 0 )

4x + y = 38

with intercepts (0, 38 ) and (9.5, 0 )

The solutions lie above both lines

Solve 2x + 3y = 24 and 4x + y = 38 simultaneously to find point of intersection at (9, 2 )

The vertices of the feasible region are at

(0, 38), (9, 2) and (12, 0)

Evaluate the objective function for each of these vertices

C = 2(0) + 38 = 0 + 38 = 38

C = 2(9) + 2 = 18 + 2 = 20

C = 2(12) + 0 = 24 + 0 = 24

The minimum value of C is 20 when x = 9 and y = 2

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Answers

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5,816-(382+298)=(5,816-382)-298

Answers

Both problems equal 5,136

Please, I need help with this problem, what is 1/3 of 60

Answers

It's 20 because 1/3 x 60
60/3=20

1/3 of 60 is 20 b/c 20x3=60 blah blah blah I cant explain that's the correct answer anyhow

Two brothers have a combined age of 21 years. Roger is twice as old as Bill was when Roger was as old as Bill is now. How old are they?

Answers

Roger is 14 and Bill is 7

Answer: I suggest you try and work this answer out rather than cheating for school quiz!!

Step-by-step explanation:

what are 3 non-equivalent fractions with values between the square root of 56 and the square root of 58

Answers

square root of 56 = 7.483314774
square root of 58 = 7.615773106

so we just need to come up with fractions that are between about 7.4833 and 7.6158

7.5 = 7 1/2 or 15/2
7.55 = 7 11/20 or 151/20
7.6 = 7 3/5 or 38/5

15/2
151/20
38/5
are your fractions

*Note: there are many other possible answers, I was just exemplifying a few.

$√(56) \approx7.48\n√(58) \approx7.62$

So these fraction can be:
$7.5=7(5)/(10)=7(1)/(2)=(15)/(2)\n7.56=7(56)/(100)=7(14)/(25)=(189)/(25)\n7.6=7(6)/(10)=7(3)/(5)=(38)/(5)$

Solve for x:
log5 (5x – 14) = log5 (8x + 4)