Use the inner product〈f,g〉=∫10f(x)g(x)dxin the vector space C0[0,1] of continuous functions on the domain [0,1] to find 〈f,g〉, ∥f∥, ∥g∥, and the angle αf,g between f(x) and g(x) forf(x)=−10x2−6 and g(x)=−9x−4.〈f,g〉= ,∥f∥= ,∥g∥= ,αf,g .

Answers

Answer 1
Answer:

Answer:

a) <f,g> = 2605/3

b) ∥f∥ = 960

c) ∥g∥ = 790

d) α = 90  

Explanation

a) We calculate  <f,g> using the definition of the inner product:

<f,g> = \int\limits^1_0 {10(-10x^(2) -6)(-9x-4)} \, dx \n        \n        =\int\limits^1_0 {900x^(3)+400x^(2) +540x+240 } \, dx\n    \n      = (225x^(4) + (400x^(3) )/(3) + 270x^(2)   +240x)\n      = (2605)/(3)

b) How

∥f∥ = <f,f> then:

∥f∥ = <f,f> = \int\limits^1_0 {10(-10x^(2) -6)(-10x^(2) -6)} \, dx \n        \n        =\int\limits^1_0 {1000x^(4)+1200x^(2) + 360} \, dx\n    \n      = (200x^(5) + 400x^(3) +  360x)\n      = 960

c)

∥g∥ = <g,g>

∥g∥ = <g,g> = \int\limits^1_0 {10(-9x-4)(-9x-4)} \, dx \n        \n        =\int\limits^1_0 {810x^(2)+720x + 160} \, dx\n    \n      = (270x^(3) + 360x^(2) +  160x)\n      = 790

d) Angle between f and g

<f,g> = ∥f∥∥g∥cosα

Thus

\alpha = cos^(-1)((2605/3)/((790)(960)) )\n\n\alpha = 90

Answer 2
Answer:

Final answer:

The answer to this problem involves applying integrals, norms, and concepts of angles between vectors to the functions f(x) and g(x). The INNER PRODUCT is the integral of the products of the two functions, the norms are the square roots of the inner products of the functions with themselves, and the angle between the functions is calculated using the dot product and norms.

Explanation:

To find the inner product 〈f,g〉, the norms ∥f∥ and ∥g∥, and the angle αf,g between the functions f(x)=−10x2−6 and g(x)=−9x−4, we'll apply concepts from vector calculus. The inner product (also known as the dot product) is the integral from 0 to 1 of the products of the two functions. The norm of a function is the square root of the inner product of the function with itself. The angle between two vectors in a Vector Space, in this case the space of continuous functions C0[0,1], is given by cos(α) = 〈f,g〉/( ∥f∥∙ ∥g∥). Integrating and solving these equations will give us the desired values.

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QuestionThe area of a triangular painting is 50 square inches. The base is 20 inches. What is the height?
Provide your answer below:
inches
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MORE INSTRUCTION
Content attribution
The area of a triangular painting is 50 in.² the base is 20 inches what is the height

Answers

The height of the triangle is 5 inches.

Area of the triangle:  

The region occupied by a triangle within its sides is known as the area of the triangle. The area of a triangle can be calculated by the calculating product of the base and height of the triangle with a half i.e 1/2. The formula for the area of the triangle is given by

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Answers

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Step-by-step explanation:

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