MATHEMATICS HIGH SCHOOL

A las 9 de la mañana,la temperatura en Valcorto era de -8 grados . A las 12 horas era dos grados mayor ,a las 15 horas tres grados mas que a las 12 ,y a las 21 horas nueve grados menos que a las 15 ¿que temperatura habia cada hora citada?

Answers

Answer 1

Answer:

Answer:

$T_(9hr)=-8 C$

$T_(12hr)=-6 C$

$T_(15hr)=-3 C$

$T_(21hr)=-12 C$

Step-by-step explanation:

The initial temperature at 9 am:

$T_(9hr)=-8 C$

At 12 hr is 2 degrees higher:

$T_(12hr)=T_(9hr)+2 C=-6 C$

At 15 hr is 3 degrees higher than 12hr:

$T_(15hr)=T_(12hr)+3 C=-3 C$

Finally, at 21 hr, is 9 degrees lower than 15 hr:

$T_(21hr)=T_(15hr)-9 C=-12 C$

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Sean began jogging to live a healthier lifestyle. On his first run, he ran one-half mile. He increased his workouts by adding two miles a month to his run. He wrote the equation f(x)= 0.5 + 2x to model his progress

Answers

The variable x represents the number of months he runs.

Answer:

b. months he runs :)

Rory is staying in a cabin on a hill 300 feet above sea level. She walks down the hill to the water’s edge. The equation of her average change in elevation over time is e = 300 – 10t, where t is the time in minutes since she left the cabin, and e is her elevation with regard to sea level. Which values are viable points, and what are their values in the table relating t and e

Answers

The correct answer :

a = not viable

b = 265

c = 0

Answer: a=Not viable,b=265,c=0

Step-by-step explanation: Just did it.

2. Another wooden plank is leaning against an outside wall of a building. The bottom of the plank is 9 ft from the wall. The length of the plank is 41 ft. Find each of the following values, and show all your work.(a) Find the value of x. Round to the nearest tenth of a degree.
(b) Find the height above the ground where the plank touches the wall. Round to the nearest foot.
Please someone help

Answers

(A) Find the value of x. Round to the nearest tenth of a degree
Given that the distance of the ground is 9ft.
Length of the plank is 41 ft

In order to get the angle formed between the ground and the foot of the plank,

cos (theta) = ground / plank
cos (theta) = 9 / 41
cos (theta) = 0.21951...
theta = cos^-1(0.21951...)
theta = 77.3 degrees

(b) Find the height above the ground where the plank touches the wall. Round to the nearest tenth of a foot.

Height = square root (plank^2 - ground^2)
Height = square root (41^2 - 8^2)
Height = square root (1600)
Height = 40

(A) 77.1 Degrees
(B) 40 feet

What is the value of h when the function is converted to vertex form?
g(x) = x^2 – 6x + 14

Answers

Hello,

g(x)=x²-6x+14=x²-2*3x+9+14-9=(x-3)²+5
h=3, k=5

Evaluate S5 for 300 + 150 + 75 + … and select the correct answer below. 18.75 93.75 581.25 145.3125

Answers

It's a geometric sequence.

$300, 150, 75,... \n \n a_1=300 \n r=(a_2)/(a_1)=(150)/(300)=(1)/(2) \n \n S_n=(a_1 (1-r^n))/(1-r) \n \Downarrow \n S_5=(300(1-((1)/(2))^5))/(1-(1)/(2))=(300(1-(1)/(32)))/((1)/(2))=(300 * (31)/(32))/((1)/(2))=(75 * (31)/(8))/((1)/(2))=((2325)/(8))/((1)/(2))=(2325)/(8) * 2= \n=(2325)/(4)=581 (1)/(4)=581.25$

The answer is 581.25.

we have that

$300 + 150 + 75 +...$

Let

$a1=300\n a2=150\n a3=75$

we know that

$(a2)/(a1) =(150)/(300) \n\n (a2)/(a1)=0.5 \n \n a2=a1*0.50$

$(a3)/(a2) =(75)/(150) \n\n (a3)/(a2)=0.5 \n \n a3=a2*0.50$

$a(n+1)=an*0.50$

Is a geometric sequence

Find the value of $a4$

$a(4)=a3*0.50$

$a(4)=75*0.50$

$a(4)=37.5$

Find the value of $a5$

$a(5)=a4*0.50$

$a(5)=37.5*0.50$

$a(5)=18.75$

Find $S5$

$S5=a1+a2+a3+a4+a5\n S5=300+150+75+37.5+18.75\n S5=581.25$

therefore

the answer is

$581.25$

Alternative Method

Applying the formula

$S_n=(a_1 (1-r^n))/(1-r) \n\na_1=300 \n r=(1)/(2)\n\n S_5=(300(1-((1)/(2))^5))/(1-(1)/(2))\n\n=(300(1-(1)/(32)))/((1)/(2))\n\n=(300 * (31)/(32))/((1)/(2))\n\n=(75 * (31)/(8))/((1)/(2))\n\n=((2325)/(8))/((1)/(2))\n\n=(2325)/(8) * 2\n\n=(2325)/(4)\n\n=581 (1)/(4)\n\n=581.25$

therefore

the answer is

$581.25$

Someone help 6th grade math i will mark brainliest

Answers

Answer:

B. -2 *4

Step-by-step explanation:

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