An 880 kg cannon at rest fires a 12.4 kg cannonball forward at 540 m/s. What is the recoil velocity of the cannon? (Unit m/s)

Answers

Answer 1

Answer:

Answer:

The recoil velocity vector of the cannon is $(7.609,0,0)(m)/(s)$

Explanation:

We can solve this problem by applying the Momentum Conservation Principle.

The principle of conservation of momentum states that when you have an isolated system with no external forces, we can use the following equation to calculate the final velocity of one object.

$m1.v1=m2.v2$ (I)

Where '' $m1$ '' and '' $v1$ '' are the mass and velocity of the first object.

And where '' $m2$ '' and '' $v2$ '' are the mass and velocity of the second object.

The momentum is a vectorial magnitude.

If we use the equation (I) with the data given :

$(880kg).v1=(12.4kg).(540(m)/(s))$

$v1=7.609(m)/(s)$

If we considered as negative the sense of the velocity vector from the cannonball, the cannon's velocity vector will have the same direction but opposite sense that the cannonball's velocity vector (It will be positive).

We can give it a vectorial character like this :

$v1=(7.609,0,0)(m)/(s)$

The velocity vector will be entirely in the x-axis.

Answer 2

Answer:

Answer:

7.61 m/s backwards

Explanation:

Initial momentum = final momentum

0 = (880 kg) v + (12.4 kg) (540 m/s)

v = -7.61 m/s

The cannon's recoil is 7.61 m/s backwards.

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Temperature and silica content determine the of magma.

Answers

I think the correct answer is that they can determine the viscosity of the magma. The viscosity of a magma is largely controlled by the temperature, composition and the gas content. Also, silica content can define a magma type. It is said that higher silica content magma has a higher viscosity than those with lower silica content.

As more lamps are put into a series circuit, the overall current in the circuit a. Increasesb. Decreasesc. Remains the same

Answers

Answer:

b. Decreases

Explanation:

The total resistance of a series circuit is equal to the sum of the individual resistances:

$R_T=R_1+R_2+...+R_n$ (1)

Therefore, as we add more lamps, the total resistance increases (because we add more positive tems in the sum in eq.(1).

The current in a circuit is given by Ohm's law:

$I=(V)/(R_T)$

where V is the voltage provided by the power source and $R_T$ is the total resistance. We notice that the current, I, is inversely proportional to the total resistance: therefore, when more lamps are added to the series circuit, the total resistance increases, and therefore the current in the circuit decreases.

A 1250 kg Nascar is at the starting line. The race starts and the car reaches a speed of 30m/s in 10 seconds. What is the force of the car? (Hint: Remember that acceleration
change in velocity / time.)

Answers

Answer:

force=1250kg * 30m/s+10

Explanation: it's a change in acceleration

If Mr. Kirwan’s pet Fluffy the Wonder Hamster rides his unicycle at a rate of 5m/s to thenorth on a flatbed train car. Under what conditions do you see him moving at 5 m/s?

Answers

The condition that would induced the seer or observer to see that the pet hamster is moving at 5 m/s is when the train is also moving at that speed. This is because the unicycle will only allow limited vision to the seer thinking that the pet hamster is not moving at that speed.

Suppose you are standing in front of a concave spherical mirror. Which of the following image properties are possible? Your image is upright.Your image is inverted.

Your image is enlarged.

Your image is reduced.

Your image is real.

Your image is virtual.

All of the above.

Answers

Answer:

All are correct

Explanation:

A concave spherical mirror produces both types of images real and virtual of an object.

The concave spherical mirror forms a real image when the object placed between the focus and infinity.

The concave spherical mirror forms a virtual image when the object is placed between focus and the pole of the mirror.

So, it forms real and virtual both types of images and it forms the image size is more than object size, equal to object size and less than the object image.

All the options are correct.

36 The height of a 30-story building is approximately(1) 10^0 m (3) 10^2 m
(2) 10^1 m (4) 10^3 m

Answers

An approximation used to measure building height is 10 feet per building level.

Converting from feet to meters using the equation:
1 ft = 0.3048m
10 ft = 3.048m

Multiplying that by 30 storeys, we get:
3 x 3.048m = 91.44m, which is near the answer of (3) 10^2 m or 100m.

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