What is the slope of a line that is perpendicular to a line whose equation is −2y=3x+7 ?

Answers

Answer 1
Answer:

The slope of a line that is perpendicular to a line whose equation is −2y = 3x + 7 is (2)/(3)

Solution:

Given that we have to find the slope of the line that is perpendicular to a line whose equation is −2y = 3x + 7

The slope intercept form is given as:

y = mx + c

Where "m" is the slope of line and "c" is the y - intercept

Given equation is:

-2y = 3x + 7\n\n-y = (3)/(2)x + (7)/(2)\n\ny = (-3)/(2)x - (7)/(2)

On comparing the above equation with slope intercept form,

m = (-3)/(2)

We know that product of slope of a line and slope of line perpendicular to it is -1

Therefore,

(-3)/(2) * \text{ slope of line perpendicular to it } = -1\n\n \text{ slope of line perpendicular to it } = (2)/(3)

Thus slope of line that is perpendicular to given line is (2)/(3)


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Find the sum. Write in simplest form: 8 1/2 + 4 1/2

Answers

 the answer is 61 bro....

A music club has 35 drum players. If 25% of the total number of members in the club are drum players, what is the total number of members in the club?60
70
120
140

Answers

So,  all we have to do for this is 
1.  Turn the percent into a decimal. 25%=0.25
2.  Divide the whole number by the percent.  35/0.25=140

The answer is 140

Answer:

D is the correct answer.

Step-by-step explanation:


60 POINTSSSS Answer correctly please this depeneds on my dumb GRADE PLEASE I dont need a big explantion just give the correct answer if you get it wrong your banned I swear

Answers

Answer:

Option 4

Step-by-step explanation:

It's a geometric progression.

After t years,

500(1.1^t)

After 6 years,

500(1.1⁶) = 885.7805

What is the fifth term of a sequence whose first term is 5 and whose common ratio is 3?A. 243
B. 405
C. 1,215

Answers

The fifth term of a sequence whose first term is 5 and whose common ratio is 3 will be 405. Then the correct option is B.

What is a geometric sequence?

A series of non-zero integers where every term after the first is obtained by increasing the one before it by a constant, non-zero value known as the scale factor.

Let a₁ be the first term and r be the common ratio.

Then the nth term of the geometric sequence is given as,

aₙ = a₁ · (r)ⁿ⁻¹

The first term is 5 and its common ratio is 3. Then the formula is given as,

aₙ = 5 · (3)ⁿ⁻¹

The fifth term of a sequence will be given as,

a₅ = 5 · (3)⁵⁻¹

a₅ = 5 · (3)⁴

a₅ = 5 · 81

a₅ = 405

The fifth term of a sequence whose first term is 5 and whose common ratio is 3 will be 405. Then the correct option is B.

More about the geometric sequence link is given below.

brainly.com/question/11266123

#SPJ2

a=first term
r=common ratio
n=the term 
a(5)=5*3(5-1)
a(5)=5*81
a(5)=405
The answer is B)

Multiply. 3√2⋅2√8⋅√3⋅√6

explanation would be lit

Answers

When two the same numbers under the square root multiply, they are equal to the value under the square root, for example √2⋅√2 = 2. So then we have:

3√2⋅2√8⋅√3⋅√6 = 3⋅√2⋅2⋅√(2⋅2⋅2)⋅√3⋅√(3⋅2) = 3⋅2⋅√2⋅√2⋅√2⋅√2⋅√2⋅√3⋅√3 = 3⋅2⋅2⋅√2⋅3 = 36⋅√2

or if the bolded 2 from above is also the square root, then the solution is:

3√(2⋅2)√(2⋅2⋅2)⋅√3⋅√(3⋅2) = 54

Answer:

72√2

Step-by-step explanation:

simplify all of the radicals into their factors, then pull out integers.  If you do this, only √2 remains.  Then, multiply all the integers.

Find the inverse of the following f(x)=-3x^2+3 X>0

Answers

Answer

f^-1(x) =√[(3-x)÷3]

Step-by-step explanation:

y=-3x^2+3

interchange 'y' with 'x'

x=-3y^2+3

make y the subject

3y^2=3-x

divide by '3' both sides

y^2=(3-x)÷3

apply square root both sides

√(y^2)=√[(3-x)÷3]

y=√[(3-x)÷3]

f^-1(x) =√[(3-x)÷3]

the inverse of the given function is

f^-1(x)=√[(3-x)÷3]