A 50.0-g hard-boiled egg moves on the end of a spring with force constant k = 25.0 N/m. It is released with an amplitude 0.300 m. A damping force F_x = -bv acts on the egg. After it oscillates for 5.00 s, the amplitude of the motion has decreased to 0.100 m.Calculate the magnitude of the damping coefficient b.Express the magnitude of the damping coefficient numerically in kilograms per second, to three significant figures.

Answers

Answer 1
Answer:

Answer

given,

mass of the boiled egg = 50 g = 0.05 Kg

spring constant, k = 25 N/m

initial Amplitude, A₁ = 0.3 m

final amplitude, A₂ = 0.1 m

time, t = 5 s

considering the amplitude of damped harmonic oscillation to calculate damping factor.

A_2 = A_1 e^{-((b)/(2m))t}

b is the damping factor and t is the time.

e^{-((b)/(2m))t}=(A_2)/(A_1)

on solving

b= (2m)/(t)ln((A_1)/(A_2))

inserting all the given values

b= (2* 0.05)/(5)ln((0.3)/(0.1))

        b = 0.0219 Kg/s

damping coefficient in three significant figure

        b = 0.022 Kg/s


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1. A bicyclist starts at 2.5 m/s and accelerates along a straight path to a speed of 12.5 m/s ina time of 4.5 seconds. What is the bicyclist's acceleration to the nearest tenth of a m/s??

1. Towards the end of a 400m race, Faisal and Edward are leading and are both running at 6m/s. While Faisal is 72m from the finish line Edward is 100m from the finish line. Realising this and to beat Faisal, Edward decides to accelerate uniformly at 0.2 m/s2 until the end of the race while Faisal keeps on the same constant speed. Does Edward succeed in beating Faisal?

Answers

Answer:

  no

Explanation:

Faisal will finish the race in ...

  (72 m)/(6 m/s) = 12 s

In order to beat Faisal, Edward's average speed in those 12 seconds must exceed ...

  (100 m)/(12 s) = 8 1/3 m/s

To achieve that average speed, Edward's acceleration must be ...

  (8 1/3 m/s -6 m/s)/(12 s/2) = 7/18 m/s² ≈ 0.3889 m/s²

Accelerating at only 0.2 m/s², Edward will not beat Faisal.

_____

Additional comment

When acceleration is uniform, the average speed is reached halfway through the period of acceleration.

A heavy object and a light object are dropped from the same height. If we neglect air resistance, which will hit the ground first?

Answers

Answer:

None, both objects will hit ground at the same time.

Explanation:

  • Assuming no air resistance present, and that both objects start from rest, we can apply the following kinematic equation for the vertical displacement:

        \Delta h = (1)/(2)*g*t^(2)  (1)

  • As the left side in (1) is the same for both objects, the right side will be the same also.
  • Since g is constant close to the surface of the Earth, it's also the same for both objects.
  • So, the time t must be the same for both objects also.

Acetone, a component of some types of fingernail polish, has a boiling point of 56°C. What is its boiling point in units of kelvin? Report your answer to the correct number of significant figures.

Answers

Answer:

The boiling point of Acetone is 329K (in 3 significant figures)

Explanation:

Boiling point of Acetone = 56°C = 56 + 273K = 329K (in 3 significant figures)

Answer: using the formula 0°C + 273.15 = 273.15K the boiling point in units of kelvin to significant figures is 329.15k.

Explanation: The boiling point of a substance ( acetone) is the temperature at which the vapour pressure of the liquid substance equals the pressure surrounding it. The boiling point of acetone serves as it's characteristic physical properties. This is measured in degree Celsius (°C ) which can be converted to units of Fahrenheit or kelvin. To convert degree Celsius to kelvin this formula is used: 0°C + 273.15 = 273.15K . Given that acetone has boiling point of 56°C,from the formula 0°C is substituted for 56°C. This gives us:

56°C + 273.15= 319.15k.

Also,measurements given in Kelvin will always be larger numbers than in Celsius and the Kelvin temperature scale does not use the degree (°) symbol because Kelvin is an absolute scale, based on absolute zero, while the zero on the Celsius scale is based on the properties of water. I hope this helps. Thanks

A 1000-kg car rolling on a smooth horizontal surface ( no friction) has speed of 20 m/s when it strikes a horizontal spring and is brought to rest in a distance of 2 m What is the spring’s stiffness constant?

Answers

Explanation:

kinetic energy was converted to potential energy in the spring.

the answer is in the above image

A piccolo and a flute can be approximated as cylindrical tubes with both ends open. The lowest fundamental frequency produced by one kind of piccolo is 522.5 Hz, and that produced by one kind of flute is 256.9 Hz. What is the ratio of the piccolo's length to the flute's length?

Answers

Answer:

ratio of the piccolo's length to the flute's length is 0.4916

Explanation:

given data

frequency of piccolo = 522.5 Hz

frequency of flute = 256.9 Hz

to find out

ratio of the piccolo's length to the flute's length

solution

we get here length of tube that is express as

length of tube = velocity of sound ÷ fundamental frequency .......................1

so here ratio of Piccolo length to flute that is

(L\ picco)/(L\ flute)  = (f\ flute)/(f \ piccolo)

(l \ piccolo)/(L\ flute) = (256.9)/(522.5)  =  0.4916

so ratio of the piccolo's length to the flute's length is 0.4916

Select the correct answer.If the coefficient of static friction is 0.35 and the normal force is 80 newtons, what is the maximum frictional force of the surface acting on the object?
O A.
B.
C.
OD.
OE
9.8 newtons
28 newtons
80 newtons
23 newtons
35 newtons

Answers

Final answer:

The maximum frictional force acting on the object is 28 newtons.


Explanation:

The maximum frictional force acting on an object can be calculated using the formula:

Frictional force = coefficient of static friction x normal force

Given that the coefficient of static friction is 0.35 and the normal force is 80 newtons, we can calculate the maximum frictional force as follows:

Maximum frictional force = 0.35 x 80 = 28 newtons


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