If 20% of a number is 8, what is 25% of the number?
Answers
20% = 2/10
2/10*x = 8 |(*10/2)
2/10*10/2*x= 8 * 10/2 2/10*10/2 =>1
1*x = 80/2
x=40
25% from 40 is 10
25% = 1/4
1/4 * 40 = 40/4 = 10
Answer:
Set up an equation as 0.2x = 8, which means 20 percent of x equals 8. Solve the equation by dividing each side by 0.2. Dividing 0.2 from each side results in x = 40. Eight is 20 percent of 40.
Step-by-step explanation:
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There are 8 players in a chess tournament. after the tournament each player has to shake hands with e
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t represents time ( in years ).
In 6 years :
Answer:
B ) t represents the number of year; 192 people were recruited in 6 years.
Answer:
B. t represents the number of years ; 192 people were recruited in 6 years
Step-by-step explanation:
b. eight tens
c. eight tenths
d.eight thousandths
Answers
Answers
We are trying to figure out how much time he loses if he is unable to run for three days. 3 * 3 = 9. This means he loses 9 hours of training while he is unable to run.
If he runs 3 hours a day, then in 3 days he would have ran 9 hours (3*3).
He loses 9 hours of training if he doesn't run for 3 days.
Which of the following options is an equivalent function to f(x) = 2(5)2X? (2 points)
a. f(x) = 50x
b. f(x) = 100x
c. f(x) = 2(25)
d. f(x) = 4(25)
Answers
Answer:
C is the correct answer
Answer:
the correct answer will be
c. f(x) = 2(25)^x
Step-by-step explanation:
Answers
Answer:
Step-by-step explanation:
2k(7-5k)+11=6k+3(k^2-1)
with work please.
Answers
⇒ (2k)* 7 - (2k)* (5k) +11= 6k+ 3* k^2- 3*1 (distributive property)
⇒ 14k -10k^2 +11= 6k+ 3k^2 -3
⇒ (14k -14k) +(-10k^2 +10k^2)+ (11-11) = (6k-14k)+ (3k^2+10k^2)+ (-3-11)
⇒ 13k^2- 8k- 14= 0
⇒ 13 (k^2- 8/13k- 14/13)=0
⇒ (k- ((4+3*sqrt(22))/13))* ((k- ((4-3*sqrt(22))/13))= 0
⇒ k= (4+3*sqrt(22))/13 or k= (4-3*sqrt(22))/13).
Hope this helps~
Answer:
k= (4+3*sqrt(22))/13 or k= (4-3*sqrt(22))/13).
Step-by-step explanation:
2k(7-5k)+11=6k+3(k^2-1)
We move all terms to the left:
2k(7-5k)+11-(6k+3(k^2-1))=0
We add all the numbers together, and all the variables
2k(-5k+7)-(6k+3(k^2-1))+11=0
We multiply parentheses
-10k^2+14k-(6k+3(k^2-1))+11=0
We calculate terms in parentheses: -(6k+3(k^2-1)), so:
6k+3(k^2-1)
We multiply parentheses
3k^2+6k-3
Back to the equation:
-(3k^2+6k-3)
We get rid of parentheses
-10k^2-3k^2+14k-6k+3+11=0
We add all the numbers together, and all the variables
-13k^2+8k+14=0
a = -13; b = 8; c = +14;
Δ = b2-4ac
Δ = 82-4·(-13)·14
Δ = 792
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
k1=−b−Δ√2ak2=−b+Δ√2a
The end solution:
Δ−−√=792−−−√=36∗22−−−−−−√=36−−√∗22−−√=622−−√
k1=−b−Δ√2a=−(8)−622√2∗−13=−8−622√−26
k2=−b+Δ√2a=−(8)+622√2∗−13=−8+622√−26