a baseball bat is in contact with a ball for 0.02 seconds, and exerts a force of 400 newtons. what is the impulse on the ball?​

Answers

Answer 1
Answer:

Answer:

I=8 Nw.s

Explanation:

Impulse

It is a physical magnitude that measures the force applied to an object by the time that force is acting. It produces a change in the momentum of the object, which is expressed in the following formula

I=\Delta p=m(v_2-v_1)=F.t

We know the bat applies a force on the ball of F=400 N during t=0.02 sec, thus the impulse is

I=(400) (0.02)=8\ Nw.s

\boxed{I=8\ Nw.s}


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What happens when an experiment with new information or new technology produces results that support an existing theory?

Answers

When an experiment with new information or new technology produces results that support an existing theory, and is confirmed empirically, then the theory will never be a theory now but a fact. But, the consequence here, it should have a strong evidence that will support the findings, otherwise it will be still considered as theory.

Answer:

The answer is b

"The theory is revised or updated"

Explanation:

A 2-kg bowling ball sits on top of a building that is 40 meters tall. Circle one: KE / GPE / both Show your work for finding the values of each type of energy the object has:2. A 2-kg bowling ball rolls at a speed of 5 m/s on the roof of the building that is 40 tall. Circle one: KE / GPE / both Show your work for finding the values of each type of energy the object has:

3. A 2-kg bowling ball rolls at a speed of 10 m/s on the ground. Circle one: KE / GPE / both Show your work for finding the values of each type of energy the object has:

1. A 1,000-kg car has 50,000 joules of kinetic energy. What is its speed?

2. A 200-kg boulder has 39,200 joules of gravitational potential energy. What height is it at?

3. A 1-kg model airplane has 12.5 joules of kinetic energy and 98 joules of gravitational potential energy. What is its speed? What is its height?

Answers

1. A2-kg bowling ball sits on top of a building that is 40 meters tall.Circle one: KE / GPE / both Show your work for finding the values ofeach type of energy the object has:

KE = 0 (because velocity is 0)

PE = mgh = 2kg*9.8m/s^2*40m= 784 joule

2. A 2-kg bowling ball rolls at a speed of 5 m/s on the roof of thebuilding that is 40 tall. Circle one: KE / GPE / both Show your work forfinding the values of each type of energy the object has:

Both
KE = [1/2]m*v^2 = [1/2](2kg)(5m/s)^2 =  25 joul
PE = mgh = 40 joule

3. A 2-kg bowling ball rolls at a speed of 10 m/s on the ground. Circleone: KE / GPE / both Show your work for finding the values of each typeof energy the object has:

KE = [1/2]m(v^2) = [1/2]2kg*(10m/s)^2 = 100 joule

GPE = mgh = 0

1. A 1,000-kg car has 50,000 joules of kinetic energy. What is its speed?

KE = [1/2]m(v^2) => v = √[2KE/m] = √[2*50,000joules/1000kg] = 10m/s

2. A 200-kg boulder has 39,200 joules of gravitational potential energy. What height is it at?

GPE = mgh => h = GPE / (mg) = 39,200 joules / (200kg * 9.8m/s^2) = 20m

3. A 1-kg model airplane has 12.5 joules of kinetic energy and 98 joulesof gravitational potential energy. What is its speed? What is itsheight?

KE = [1/2]m(v^2) => v = √ [ 2KE/m] = √[2*12.5 j / 1kg] = 7.9 m/s

GPE = mgh => h = GPE/(mg) = 98/(1kg*9.8m/s^2) = 10 m

Please help!!!!!!!!!!!!!

Answers

Answer:the answer is d

Explanation:

I believe the answer is letter B

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Answers

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Answers

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Answers

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