When 28 g of nitrogen and 6 g of hydrogen react, 34 g of ammonia are produced. If 100 g of nitrogen react with 6 g of hydrogen, how much ammonia will be produced? 106 g 34 g 128 g 40 g

Answers

Answer 1
Answer:

Answer:

34 g

Explanation:

Let's consider the following balanced equation.

N₂ + 3 H₂ → 2 NH₃

The theoretical mass ratio of N₂ to H₂ is 28g N₂ : 6g H₂ = 4.6g N₂ : 1g H₂.

The experimental mass ratio of N₂ to H₂ is 100g N₂ : 6g H₂ = 16.6g N₂ : 1g H₂.

As we can see, hydrogen is the limiting reactant.

According to the task, we 6 g of H₂ react completely, 34 g of ammonia are produced.


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Aqueous solutions of sodium hypoch lorite (NaOCI), best known as bleach, are prepared by the reaction of sodium hydroxide with chlorine: 2 NaOH (aq)Cl2(g)->NaOCI (aq)+ H20 (I)+ NaCl (aq) How many grams of NaOH are needed to react with 25.0 g of chlorine?

Answers

Answer:

28.2 g of NaOH

Explanation:

We need to calculate the grams of NaOH needed to react with 25.0 g of Cl₂ in the following reaction:

2 NaOH(aq) + Cl₂(g) → NaOCI(aq + H₂0(I) + NaCl(aq)

We are going to solve this by making use of the molar ratio between Cl₂ and NaOH given by the reaction equation where we see that every mol of Cl₂ will react with 2 moles of NaOH.

So first we need to convert the 25.0 g of Cl₂ to moles:

  • Molar Mass of Cl₂ = 2 x 35.45 = 70.90 g/mol
  • Moles of Cl₂ = 25.0 g / 70.90 g/mol = 0.3526 moles

Then we need to calculate the moles of NaOH needed to react with these moles of Cl₂ knowing that every mol of Cl₂ will react with 2 moles of NaOH:

  • moles of NaOH = 2 x moles of Cl₂ = 2 x 0.3526 moles = 0.7052 moles

Next we must convert these moles to grams:

  • Molar Mass of NaOH = 22.990 + 15.999 + 1.008 = 40.00 g/mol
  • Mass of NaOH = 0.7052 moles x 40.00 g/mol = 28.2 g

28.2 g are needed to react with 25.0 g of Cl₂ in the production of NaOCl

How many molecules are in 2NaO? please someone help i dont know this :')​

Answers

Answer:

One molecule

Explanation

But there is three different atoms forming this one NaOH. The three atoms are Na, O and H, that is one sodium, one oxygen, and one hydrogen.

How many molecules are in 4.27 mol of SiH4

Answers

Answer:

2.57 × 10²⁴ molecules

Explanation:

The number of molecules can be found by using the formula

N = n × L

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

N = 4.27 × 6.02 × 10²³

We have the final answer as

2.57 × 10²⁴ molecules

Hope this helps you

2 N H 3 ( g ) ⟷ N 2 ( g ) + 3 H 2 ( g ) K p = 0.83 Consider your answers above, if the initial pressures for all three species is 1 atm what is the equilibrium pressure of H2? (Hint: Your quadratic will have two solutions, which one is impossible?)

Answers

The equilibrium pressure of H2 is 0.96 atm and the impossible solution of the quadratic equation is -1.379.

Equilibrium pressure of H2

The equilibrium pressure of H2 is calculated by creating ICE table as follows;

            2 N H3 ( g ) ⟷ N2( g ) + 3H2

I:           1                         1              1

C:         -2x                      x             3x

E:        1 - 2x                    1 + x         1 + 3x

KP = ((N_2)(H_2)^3)/((NH_3)^2) \n\n0.83 = ((1 + x)(1 + 3x)^3)/((1 - 2x)^2)

0.83(1 - 2x)² = (1 + x)(1 + 3x)³

0.83(1 - 4x + 4x²) = (1 + x)((1 + 3x)³)

0.83 - 3.32x + 3.32x² = (1 + x)((1 + 3x)³)

0.83 - 3.32x + 3.32x² = 1 + 10x + 36x² + 54x³ + 27x⁴

27x⁴ + 54x³ + 32.68x² + 13.32x + 0.17 = 0

x = -1.379 or - 0.013

Partial pressure of H2 = 1 + 3x

H2 = 1 + 3(-1.379)

H2 = -3.13 atm

H2 = 1 + 3(-0.013)

H2 = 0.96 atm

Thus, the equilibrium pressure of H2 is 0.96 atm and the impossible solution of the quadratic equation is -1.379.

Learn more about equilibrium pressure here: brainly.com/question/25651917

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Write the condensed ground-state electron configurations of these transition metal ions, and state which are paramagnetic:(a) V³⁺ (b) Cd²⁺ (c) Co³⁺ (d) Ag⁺

Answers

Answer and Explanation :

Paramagnetic are those which has unpaired electrons and diamagnetic are those in which all electrons are paired.

(a) V³⁺

The electronic configuration is -  

[Ar]3d^1

The electrons in 3d orbital = 1 (Unpaired)

Thus, the ion is paramagnetic as the electrons are unpaired.

(b) Cd²⁺

The electronic configuration is -  

[Kr]4d^(10)

The electrons in 4d orbital = 10 (paired)

Thus, the ion is diamagnetic as the electrons are paired.

(c) Co³⁺

The electronic configuration is -  

[Ar]3d^6

The electrons in 3d orbital = 6 (Unpaired)

Thus, the ion is paramagnetic as the electrons are unpaired.

(d) Ag⁺

The electronic configuration is -  

[Kr]4d^(10)

The electrons in 4d orbital = 10 (paired)

Thus, the ion is diamagnetic as the electrons are paired.

If sodium arsenite is Na3AsO3, the formula for calcium arsenite would be

Answers

Answer:

Ca₃(AsO₃)₂

Explanation:

Sodium arsenite, with the chemical formula Na₃AsO₃, is formed  by the cation Na⁺ and the anion AsO₃³⁻. For the molecule to be neutral, 3 cations Na⁺ and 1 anion AsO₃³⁻ are required.

Calcium arsenite would be formed by the cation Ca²⁺ and the anion AsO₃³⁻. For the molecule to be neutral, we require 3 cations Ca²⁺ and 2 anions AsO₃³⁻. The resulting chemical formula is Ca₃(AsO₃)₂.