Two large crates, with masses 640kg and 490kg , are connected by a stiff, massless spring (K=8.1kN/m) and propelled along an essentially frictionless, level factory floor by a force applied horizontally to the more massive crate. If the spring compresses 5.1 from its equilibrium length, what is the applied force? Express your answer using two significant figures. The answer is suppose to be 950N

Answers

Answer 1
Answer:

Answer:

950.7 N

Explanation:

m1 = 640kg

m2 = 490kg

k = 8.1 kN/m

the spring is compressed by 5.1cm

5.1/100 = 0.051m

F = kx

F = 8100 * 0.051

F = 413.1 N

F is the force of the small crate.

F(small) = ma

431.1 = 490a

a = 431.1/490

a = 0.84 m/s^2

The acceleration for the smaller crate is the same for the large create.

F(large) = ma

= 640 * 0.84

= 537.6N

Total force = F(small) + F(large)

= 413.1 + 537.6

= 950.7N


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Answers

Answer:

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You travel in a circle, whose circumference is 8 kilometers, at an average speed of 8 kilometers/hour. If you stop at the same point you started from, what is your average velocity?

Answers

Answer: The average velocity will be 0 m/s.

Explanation:

Average velocity is defined as the fraction of displacement and total time.

\text{Average velocity}=\frac{Displacement}{\text{total time}}

In the given question, it states that the person stops at the same point from where it started, which means that the displacement of this person is 0 meters.

Therefore, the average velocity becomes:

\text{Average velocity}=\frac{0}{\text{total time}}=0m/s

Hence, the average velocity will be 0 m/s.

the answer is 8 kilometers per hour

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Answers

Answer;

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Explanation;

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If you have a vector which is 12 Newtons at 75 degrees south of west, what other vector is equivalent to this vector? a) 12 N at 15 degrees west of south b) 12 N at 15 degrees south of east c) 12 N at 15 degrees north of east d) 12 N at 15 degrees south of west

Answers

To find the vector that is equivalent to a vector of 12 Newtons at 75 degrees south of west, we need to determine the direction and magnitude of the equivalent vector.

The equivalent vector will have the same magnitude of 12 Newtons but a direction that is 180 degrees opposite to the given vector.

The given vector is 75 degrees south of west, which means it is pointing towards the south but slightly to the west.

Therefore, the direction of the equivalent vector will be 75 degrees north of east (opposite direction).

Among the given options:

a) 12 N at 15 degrees west of south - This is not the correct direction.

b) 12 N at 15 degrees south of east - This is not the correct direction.

c) 12 N at 15 degrees north of east - This is the correct direction.

d) 12 N at 15 degrees south of west - This is not the correct direction.

Therefore, the vector that is equivalent to the given vector is option c) 12 N at 15 degrees north of east.

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Answers

The correct answer for the question that is being presented above is this one: "B. frictional." A naturally occurring force related to two bodies in motion is frictional force. Friction is a type of force which includes two bodies resisting each other. They key point of this frictional force is that the two forces are in the opposite point of direction with each other. 

Answer:

frictional

Explanation:

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Answers

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